StrictMath floor() Method in Java
The java.lang.StrictMath.floor() is the inbuilt method which returns the largest double value, less than or equal to the given argument and is equal to the integer value.
- The result is the same as the argument when the given argument is equal to the integer.
- The result is the same as the argument when the given argument is NaN, infinity, positive zero or negative zero.
Syntax :
public static double floor(double num)
Parameters: This method accepts one parameter num which is of double type .
Return Value : The method returns the largest value which, closest to positive infinity, less than or equal to the argument and equal to an integer.
Examples :
Input: num = 9.6
Output: 9.0
Input: num = -7.8
Output: -8.0
Below programs illustrate the java.lang.StrictMath.floor() method:
Program 1:
java
import java.lang.*;
public class Geeks {
public static void main(String[] args) {
double num1 = 7.8 , num2 = 1.4 ;
double fValue = StrictMath.floor(num1);
System.out.println("The floor value of "+
num1+" = " + fValue);
fValue = StrictMath.floor(num2);
System.out.println("The floor value of "+
num2+" = " + fValue);
}
}
|
Output:
The floor value of 7.8 = 7.0
The floor value of 1.4 = 1.0
Program2:
java
import java.lang.*;
public class Geeks {
public static void main(String[] args) {
double num1 = - 7.8 , num2 = - 1.4 ,num3 = 0.1 ;
double fValue = StrictMath.floor(num1);
System.out.println("The floor value of "+
num1+" = " + fValue);
fValue = StrictMath.floor(num2);
System.out.println("The floor value of "+
num2+" = " + fValue);
fValue = StrictMath.floor(num3);
System.out.println("The floor value of "+
num3+" = " + fValue);
}
}
|
Output:
The floor value of -7.8 = -8.0
The floor value of -1.4 = -2.0
The floor value of 0.1 = 0.0
Last Updated :
13 Dec, 2021
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