# StrictMath exp() Method in Java

All methods of java.lang.StrictMath class : Set 1, Set 2
The java.lang.StrictMath.exp() is an inbuilt method in Java is used to return a Euler number raised to the power of the specified double value. It gives rise to three special results:

• The result is positive infinity when the given argument is positive infinity.
• The result is positive zero when the argument is negative infinity.
• The result is NaN when the given argument is NaN.

Syntax :

`public static double exp(double num)`

Parameters: This method accepts one parameter num which is of double type which is the exponent to raise e to.

Return Value: The method returns the value e^num, where e is the base of the natural logarithms.

Examples:

```Input: num = 7
Output: 1096.6331584284585

Input: num = (1.0 / 0.0)
Output: Infinity
```

Below programs illustrate the java.lang.StrictMath.exp() method:
Program 1:

 `// Java praogram to illustrate the ` `// java.lang.StrictMath.exp() ` `import` `java.lang.*; ` ` `  `public` `class` `Geeks { ` ` `  `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` ` `  `        ``double` `num1 = ``0.0``, num2 = (``1.0` `/ ``0.0``); ` `        ``double` `num3 = ``4``; ` ` `  `        ``// Returns Euler's number e raised to the given power ` `        ``double` `expValue = StrictMath.exp(num1); ` `        ``System.out.println(``"The exp value of "``+ ` `                         ``num1+``" = "` `+ expValue); ` ` `  `        ``expValue = StrictMath.exp(num2); ` `        ``System.out.println(``"The exp value of "``+ ` `                         ``num2+``" = "` `+ expValue); ` ` `  `        ``expValue = StrictMath.exp(num3); ` `        ``System.out.println(``"The exp value of "``+ ` `                         ``num3+``" = "` `+ expValue);    } ` `} `

Output:

```The exp value of 0.0 = 1.0
The exp value of Infinity = Infinity
The exp value of 4.0 = 54.598150033144236
```

Program 2:

 `// Java praogram to illustrate the ` `// java.lang.StrictMath.exp() ` `import` `java.lang.*; ` ` `  `public` `class` `Geeks { ` ` `  `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` ` `  `        ``double` `num1 = -``0.0``, num2 = (``1.0` `/ ``0.0``); ` `        ``double` `num3 = ``14``; ` ` `  `        ``// Returns Euler's number e raised to the given power ` `        ``double` `expValue = StrictMath.exp(num1); ` `        ``System.out.println(``"The exp value of "``+ ` `                         ``num1+``" = "` `+ expValue); ` ` `  `        ``expValue = StrictMath.exp(num2); ` `        ``System.out.println(``"The exp value of "``+ ` `                         ``num2+``" = "` `+ expValue); ` ` `  `        ``expValue = StrictMath.exp(num3); ` `        ``System.out.println(``"The exp value of "``+ ` `                         ``num3+``" = "` `+ expValue); ` `    ``} ` `} `

Output:

```The exp value of -0.0 = 1.0
The exp value of Infinity = Infinity
The exp value of 14.0 = 1202604.2841647768
```

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