std::move_backward in C++
Last Updated :
20 Jul, 2017
Moves the elements in the range [first,last] starting from the end into the range terminating at result.
The function begins by moving *(last-1) into *(result-1), and then follows backward by the elements preceding these, until first is reached (and including it).
Template :
BidirectionalIterator2 move_backward (BidirectionalIterator1 first,
BidirectionalIterator1 last,
BidirectionalIterator2 result);
result
Bidirectional iterator to the past-the-end position in the destination sequence.
This shall not point to any element in the range [first,last].
Return Type :
An iterator to the first element of the destination sequence where elements
have been moved.
Examples:
Input :
vec1 contains : 3 4 5 7 8
vec2 contains : 8 9 6 2 4 7
Output :
arr2 contains : 8 9 6 5 7 8
/*3 elements from 3rd position of vector vec1 moved to starting 4th position of vec2*/
#include<bits/stdc++.h>
int main()
{
std :: vector < int > vec1 {1, 2, 3, 4, 5};
std :: vector < int > vec2 {7, 7, 7, 7, 7};
std :: cout << "Vector1 contains :" ;
for ( int i = 0; i < vec1.size(); i++)
std :: cout << " " << vec1[i];
std :: cout << "\n" ;
std :: cout << "Vector2 contains :" ;
for (unsigned int i = 0; i < vec2.size(); i++)
std :: cout << " " << vec2[i];
std :: cout << "\n\n" ;
std :: move_backward (vec2.begin(), vec2.begin() + 3, vec1.begin() + 3);
std :: cout << "Vector1 contains after std::move_backward function:" ;
for (unsigned int i = 0; i < vec1.size(); i++)
std :: cout << " " << vec1[i];
std :: cout << "\n" ;
return 0;
}
|
Output:
Vector1 contains : 1 2 3 4 5
Vector2 contains : 7 7 7 7 7
Vector1 contains after std::move_backward function: 7 7 7 4 5
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