std::is_trivially_destructible in C++ with Examples
Last Updated :
21 Sep, 2022
The std::is_trivially_destructible template of C++ STL is present in the <type_traits> header file. The std::is_trivially_denstructible template of C++ STL is used to check whether T is trivially destructible type or not. It return the boolean value true if T is trivially destructible type Otherwise return false. Header File:
#include<type_traits>
Template Class:
template <class T>
struct is_trivially_destructible;
Syntax:
std::is_trivially_destructible<T>::value
Parameters: The template std::is_trivially_destructible accepts a single parameter T(Trait class) to check whether T is trivially destructible type or not. Return Value: This template returns a boolean variable as shown below:
- True: If the type T is a trivially destructible type.
- False: If the type T is not a trivially destructible type.
Below is the program to illustrates the std::is_trivially_destructible template in C/C++: Program 1:
CPP
#include <bits/stdc++.h>
#include <type_traits>
using namespace std;
struct Y {
Y( int , int ){};
};
struct X {
~X() noexcept( false )
{
}
};
struct Z {
~Z() = default ;
};
class A {
virtual void fn() {}
};
int main()
{
cout << boolalpha;
cout << " int : "
<< is_trivially_destructible< int >::value
<< endl;
cout << " struct X: "
<< is_trivially_destructible<X>::value
<< endl;
cout << " struct Y: "
<< is_trivially_destructible<Y>::value
<< endl;
cout << " struct Z: "
<< is_trivially_destructible<Z>::value
<< endl;
cout << " class A: "
<< is_trivially_destructible<A>::value
<< endl;
cout << "Constructor Y( int , int ): "
<< is_trivially_destructible<Y( int , int )>::value
<< endl;
return 0;
}
|
Output:
int: true
struct X: false
struct Y: true
struct Z: true
class A: true
Constructor Y(int, int): false
Reference: http://www.cplusplus.com/reference/type_traits/is_trivially_destructible/
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