std::is_literal_type in C++ with Examples
The std::is_literal_type template of C++ STL is present in the <type_traits> header file. The std::is_literal_type template of C++ STL is used to check whether the T is literal type or not. It return the boolean value true if T is literal type, otherwise return false.
Header File:
#include<type_traits>
Template:
template< class T >
struct is_literal_type;
Syntax:
std::is_literal_type::value
Parameter: The template std::is_literal_type accepts a single parameter T(Trait class) to check whether T is literal type or not.
Return Value: The template std::is_literal_type returns a boolean variable as shown below:
- True: If the type T is a literal type.
- False: If the type T is not a literal type.
Below is the program to demonstrate std::is_literal_type: in C/C++:
Program:
#include <bits/stdc++.h>
#include <type_traits>
using namespace std;
class X {
};
class Y {
~Y() {}
};
struct A {
int m;
};
struct B {
virtual ~B();
};
int main()
{
cout << boolalpha;
cout << "int: "
<< is_literal_type< int >::value
<< endl;
cout << "class X: "
<< is_literal_type<X>::value
<< endl;
cout << "class Y: "
<< is_literal_type<Y>::value
<< endl;
cout << "int*: "
<< is_literal_type< int *>::value
<< endl;
cout << "struct A: "
<< is_literal_type<A>::value
<< endl;
cout << "struct B: "
<< is_literal_type<B>::value
<< endl;
return 0;
}
|
Output:
int: true
class X: true
class Y: false
int*: true
struct A: true
struct B: false
Reference: http://www.cplusplus.com/reference/type_traits/is_literal_type/
Last Updated :
12 Jun, 2020
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