SQL | UNIQUE Constraint

SQL Constraints

Unique constraint in SQL is used to check whether the sub query has duplicate tuples in it’s result. It returns a boolean value indicating the presence/absence of duplicate tuples. Unique construct returns true only if the sub query has no duplicate tuples, else it return false.

Important Points:

• Evaluates to true on an empty sub query.
• Returns true only if there are unique tuples present as the output of the sub query (two tuples are unique if the value of any attribute of the two tuples differ).
• Returns true if the sub query has two duplicate rows with at least one attribute as NULL.

Syntax:

SELECT table.ID
FROM  table
WHERE UNIQUE (SELECT table2.ID
              FROM table2
              WHERE table.ID = table2.ID);

Note: During the execution, first the outer query is evaluated to obtain table.ID. Following this, the inner sub query is processed which produces a new relation that contains the output of inner query such that table.ID == table2.ID. If every row in the new relation is unique then unique returns true and the corresponding table.ID is added as a tuple in the output relation produced. However, if every row in the new relation is not unique then unique evaluates to false and the corresponding table.ID is not add to the output relation.

Unique applied to a sub query return false if and only if there are two tuples t1 and t2 such that t1 = t2. It considers t1 and t2 to be two different tuple, when unique is applied to a sub query that contains t1 and t2 such that t1 = t2 and at least one of the attribute of these tuples contains a NULL value. Unique predicate in this case evaluates to true. This is because, a NULL value in SQL is treated as an unknown value therefore, two NULL values are considered to be distinct.

Note: The SQL statement without UNIQUE clause can also be written as:

SELECT table.ID
FROM  table
WHERE 1 <= (SELECT count(table2.ID)
              FROM table2
              WHERE table.ID = table2.ID);

Queries

Example 1: Find all the instructors that taught at most one course in the year 2017.
Instructor relation:

EmployeeID	Name	CourseID	Year
77505	Alan	SC110	2017
77815	Will	CSE774	2017
85019	Smith	EE457	2017
92701	Sam	PYS504	2017
60215	Harold	HSS103	2016
77505	Alan	BIO775	2017
92701	Sam	ECO980	2017

SQL Query:

SELECT I.EMPLOYEEID, I.NAME
FROM Instructor as I
WHERE UNIQUE (SELECT Inst.EMPLOYEEID
              FROM Instructor as Inst
              WHERE I.EMPLOYEEID = Inst.EMPLOYEEID
                          and Inst.YEAR = 2017);

Output:

EmployeeID	Name
77815	Will
85019	Smith

Explanation: In the Instructor relation, only instructors Will and Smith teach a single course during the year 2017. The sub query corresponding to these instructors contains only a single tuple and therefore the unique clause corresponding to these instructors evaluates to true thereby producing these two instructors in the output relation.

---

Example 2: Find all the courses in Computer Science department that has only a single instructor allotted to that course.
Course relation:

CourseID	Name	Department	InstructorID
CSE505	Computer Network	Computer Science	11071
CSE245	Operating System	Computer Science	74505
CSE101	Programming	Computer Science	12715
HSS505	Psychology	Social Science	85017
EE475	Signals & Systems	Electrical	22150
CSE314	DBMS	Computer Science	44704
CSE505	Computer Network	Computer Science	11747
CSE314	DBMS	Computer Science	44715

SQL Query:

SELECT C.COURSEID, C.NAME
FROM Course as C
WHERE UNIQUE (SELECT T.INSTRUCTORID
              FROM Course as T
              WHERE T.COURSEID = C.COURSEID 
                          and C.DEPARTMENT = 'Computer Science');

Output:

COURSEID	Name
CSE245	Operating System
CSE101	Programming

Explanation: In the course relation, the only courses in computer science department that has a single instructor allotted are Operating System and Programming. The unique constraint corresponding to these two courses has only a single tuple consisting of the corresponding instructors. So, the unique clause for these two courses evaluates to true and these courses are displayed in output relation. Other courses in the Course relation either have two or more instructors or they do not belong to computer science department and therefore, those courses aren’t displayed in the output relation.

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