Given a circular linked list with N nodes and an integer K where 0 < K < N, the task is to split the first K nodes into a new list and at the same time preserving the rest of the nodes in the original circular linked list.
Input: 2 -> 3 -> 4 -> 5 -> 6 -> 7 -> 8, K = 3
2 3 4 5 6 7 8
The new lists are:
2 3 4
5 6 7 8
Input: 2 -> 4 -> 6 -> 8- > 10 -> 12, N = 4
2 4 6 8 10 12
The new lists are:
2 4 6 8
- Traverse an iterator until the required node i.e. the Kth node.
- Point the node just previous to the Kth node to the head of the original list.
- Point the last node of the original list to the Kth node.
Below is the implementation of the above approach:
Original list: 2 4 6 8 10 12 The new lists are: 2 4 6 8 10 12
- Sum of the nodes of a Circular Linked List
- Delete all the even nodes of a Circular Linked List
- Count nodes in Circular linked list
- Exchange first and last nodes in Circular Linked List
- Delete all odd or even positioned nodes from Circular Linked List
- Sum and Product of the nodes of a Circular Singly Linked List which are divisible by K
- Delete all Prime Nodes from a Circular Singly Linked List
- Append odd position nodes in reverse at the end of even positioned nodes in a Linked List
- Delete N nodes after M nodes of a linked list
- Construct a Maximum Sum Linked List out of two Sorted Linked Lists having some Common nodes
- Linked List Sum of Nodes Between 0s
- Sum of the alternate nodes of linked list
- Sum and Product of all the nodes which are less than K in the linked list
- Linked List Product of Nodes Between 0s
- Sum of the nodes of a Singly Linked List
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Improved By : Rajput-Ji