Split array into two subarrays such that difference of their maximum is minimum

Given an array arr[] consisting of integers, the task is to split the given array into two sub-arrays such that difference between their maximum elements is minimum.
Example:

Input: arr[] = {7, 9, 5, 10}
Output: 1
Explanation:
The subarrays are {5, 10} and {7, 9} with the difference between their maximums = 10 – 9 = 1.

Input: arr[] = {6, 6, 6}
Output: 0

Approach:
We can observe that we need to split the array into two subarrays such that:

This ensures that the difference between the maximum elements of the two subarrays is maximized.
Hence, we need to sort the array, and then the difference between largest 2 elements, i.e. arr[n – 1] and arr[n – 2], is the required answer.



Below is the implementation of the above approach:

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// C++ Program to split a given
// array such that the difference
// between their maximums is minimized.
  
#include <bits/stdc++.h>
using namespace std;
  
int findMinDif(int arr[], int N)
{
    // Sort the array
    sort(arr, arr + N);
  
    // Return the difference
    // between two highest
    // elements
    return (arr[N - 1] - arr[N - 2]);
}
  
// Driver Program
int main()
{
  
    int arr[] = { 7, 9, 5, 10 };
    int N = sizeof(arr) / sizeof(arr[0]);
  
    cout << findMinDif(arr, N);
    return 0;
}
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// Java Program to split a given array 
// such that the difference between 
// their maximums is minimized.
import java.util.*;
  
class GFG{
  
static int findMinDif(int arr[], int N)
{
      
    // Sort the array
    Arrays.sort(arr);
      
    // Return the difference between 
    // two highest elements
    return (arr[N - 1] - arr[N - 2]);
}
  
// Driver code
public static void main(String[] args)
{
    int arr[] = { 7, 9, 5, 10 };
    int N = arr.length;
  
    System.out.println(findMinDif(arr, N));
}
}
  
// This code is contributed by offbeat
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# Python3 Program to split a given 
# array such that the difference 
# between their maximums is minimized. 
def findMinDif(arr, N):
      
    # Sort the array 
    arr.sort()
  
    # Return the difference 
    # between two highest 
    # elements 
    return (arr[N - 1] - arr[N - 2])
  
# Driver Program 
arr = [ 7, 9, 5, 10 ]
N = len(arr)
print(findMinDif(arr, N))
  
# This code is contributed by yatinagg
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// C# Program to split a given array 
// such that the difference between 
// their maximums is minimized.
using System;
class GFG{
  
static int findMinDif(int []arr, int N)
{
      
    // Sort the array
    Array.Sort(arr);
      
    // Return the difference between 
    // two highest elements
    return (arr[N - 1] - arr[N - 2]);
}
  
// Driver code
public static void Main()
{
    int []arr = { 7, 9, 5, 10 };
    int N = arr.Length;
  
    Console.Write(findMinDif(arr, N));
}
}
  
// This code is contributed by Code_Mech
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Output:
1

Time complexity: O(N*log(N)), N is the number of elements of the array.

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Improved By : yatinagg, offbeat, Code_Mech

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