# Sort strings on the basis of their numeric part

• Difficulty Level : Hard
• Last Updated : 27 Jan, 2022

Given a sentence S of size N where each word is a concatenation of a numeric part followed by a bunch of characters. The task is to arrange the words in increasing order of their numeric part.

Examples:

Input: S = “24-amazing 7-coders 11-are”
Output: coders are amazing
Explanation: order of numeric values are 7, 11, 24.
So they are arranged accordingly

Input: S = “19-Love 10-I 2001-cricket”
Output: I Love cricket

Approach: The approach of the solution is based on the concept of min-heap. Split the strings on the basis of spaces and put them in the heap. At last pop them from the heap and print them in order. That will give the desired solution.

Below is the implementation of the above approach.

## Java

 `// Java code to implement above approach``import` `java.util.*;` `class` `GFG {` `    ``// For arranging words on the basis``    ``// of numeric part``    ``public` `static` `class` `pair``        ``implements` `Comparable {` `        ``int` `num;``        ``String word;` `        ``pair(``int` `num, String word)``        ``{``            ``this``.num = num;``            ``this``.word = word;``        ``}``        ``public` `int` `compareTo(pair o)``        ``{``            ``return` `this``.num - o.num;``        ``}``    ``}` `    ``// Function to arrange the sentence``    ``public` `static` `String solve(String str)``    ``{``        ``String[] arr = str.split(``" "``);``        ``PriorityQueue pq``            ``= ``new` `PriorityQueue<>();``        ``for` `(``int` `i = ``0``; i < arr.length;``             ``i++) {``            ``String s = arr[i];``            ``String N = ``""``;``            ``int` `a = ``0``;``            ``while` `(s.charAt(a) != ``'-'``) {``                ``N += s.charAt(a);``                ``a++;``            ``}``            ``int` `num = Integer.parseInt(N);``            ``String word = s.substring(a + ``1``);``            ``pq.add(``new` `pair(num, word));``        ``}` `        ``StringBuilder sb``            ``= ``new` `StringBuilder();``        ``while` `(pq.size() > ``0``) {``            ``pair p = pq.remove();``            ``sb.append(p.word);``            ``sb.append(``" "``);``        ``}``        ``sb.deleteCharAt(sb.length() - ``1``);``        ``return` `sb.toString();``    ``}` `    ``// Driver code``    ``public` `static` `void` `main(String[] args)``    ``{``        ``String S = ``"19-Love 10-I 2001-cricket"``;` `        ``String ans = solve(S);``        ``System.out.println(ans);``    ``}``}`

## Python3

 `# python3 code for the above approach` `# For arranging words on the basis``# of numeric part` `# Function to arrange the sentence``def` `solve(``str``):``    ``arr ``=` `str``.split(``" "``)` `    ``pq ``=` `[]``    ``for` `i ``in` `range``(``0``, ``len``(arr)):``        ``s ``=` `arr[i]``        ``N ``=` `""``        ``a ``=` `0``        ``while` `(s[a] !``=` `'-'``):``            ``N ``+``=` `s[a]``            ``a ``+``=` `1` `        ``num ``=` `int``(N)``        ``word ``=` `s[a ``+` `1``:]` `        ``pq.append([num, word])` `    ``pq.sort()` `    ``sb ``=` `""``    ``k ``=` `0``    ``while` `(k < ``len``(pq)):``        ``sb ``+``=` `pq[k][``1``] ``+` `" "``        ``k``        ``k ``+``=` `1` `    ``return` `sb` `# Driver code``if` `__name__ ``=``=` `"__main__"``:` `    ``S ``=` `"19-Love 10-I 2001-cricket"` `    ``ans ``=` `solve(S)``    ``print``(ans)` `    ``# This code is contributed by rakeshsahni`

## Javascript

 ``

Output
`I Love cricket`

Time Complexity: O(N)
Auxiliary Space: O(N)

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