Sometimes, while working with Python, we can have a problem in which we need to sort a particular list which has mixed data types. That it contains integers and strings and we need to sort each of them accordingly. Let’s discuss certain ways in which this problem can be solved.
Method #1 : Using sort()
+ comparator
This problem can be solved using sort functionality provided by Python. We can construct our own custom comparator to complete the task of mixed sort.
# Python3 code to demonstrate working of # Sort Mixed List # using sort() + comparator # comparator function for sort def mixs(num): try : ele = int (num) return ( 0 , ele, '') except ValueError: return ( 1 , num, '') # initialize list test_list = [ 4 , 'gfg' , 2 , 'best' , 'is' , 3 ] # printing original list print ( "The original list : " + str (test_list)) # Sort Mixed List # using sort() + comparator test_list.sort(key = mixs) # printing result print ( "List after mixed sorting : " + str (test_list)) |
The original list : [4, 'gfg', 2, 'best', 'is', 3] List after mixed sorting : [2, 3, 4, 'best', 'gfg', 'is']
Method #2 : Using sorted() + key + lambda + isdigit()
The combination of above functionalities can also be used to achieve solution to this problem. In this, we just sort the list using sorted() using key functionality using lambda function to segregate digits using isdigit().
# Python3 code to demonstrate working of # Sort Mixed List # using sorted() + key + lambda + isdigit() # initialize list test_list = [ '4' , 'gfg' , '2' , 'best' , 'is' , '3' ] # printing original list print ( "The original list : " + str (test_list)) # Sort Mixed List # using sorted() + key + lambda + isdigit() res = sorted (test_list, key = lambda ele: ( 0 , int (ele)) if ele.isdigit() else ( 1 , ele)) # printing result print ( "List after mixed sorting : " + str (res)) |
The original list : ['4', 'gfg', '2', 'best', 'is', '3'] List after mixed sorting : ['2', '3', '4', 'best', 'gfg', 'is']
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