Sort all even numbers in ascending order and then sort all odd numbers in descending order

Given an array of integers (both odd and even), sort them in such a way that the first part of the array contains odd numbers sorted in descending order, rest portion contains even numbers sorted in ascending order.
Examples:

Input: arr[] = {1, 2, 3, 5, 4, 7, 10}
Output: arr[] = {7, 5, 3, 1, 2, 4, 10}

Input: arr[] = {0, 4, 5, 3, 7, 2, 1}
Output: arr[] = {7, 5, 3, 1, 0, 2, 4} 

Naive Approach-

The idea is to store all even in a separate array or vector and sort them in ascending order and then store all odd in a separate array or vector and sort them in descending order. Then replace all input array elements with those odd array/vector elements followed by even array/vector elements

Steps to implement-

• Declare two vectors odd and even to store odd and even elements
• Run a for loop on the input array to separately store odd and even elements into odd and even vector
• Then sort even elements in ascending order and odd elements in decreasing order
• Then, first copy odd elements into the original array and then even elements into that array

Code-

C++

// C++ program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order
#include <bits/stdc++.h>
using namespace std;

// To do two way sort. First sort even numbers in
// ascending order, then odd numbers in descending
// order.
void twoWaySort(int arr[], int n)
{
    //To store odd Numbers
    vector<int> odd;

    //To store Even Numbers
    vector<int> even;

    for(int i=0;i<n;i++){
        //If number is even push them to even vector
        if(arr[i]%2==0){even.push_back(arr[i]);}

        //If number is odd push them to odd vector
        else{odd.push_back(arr[i]);}
    }
        //Sort even array in ascending order
        sort(even.begin(),even.end());

        //Sort odd array in descending order
        sort(odd.begin(),odd.end(),greater<int>());


      int i=0;

      //First store odd numbers to array
      for(int j=0;j<odd.size();j++){
          arr[i]=odd[j];
          i++;
      }

      //Then store even numbers to array
      for(int j=0;j<even.size();j++){
          arr[i]=even[j];
          i++;
      }
}

// Driver code
int main()
{
    int arr[] = { 1, 3, 2, 7, 5, 4 };
    int n = sizeof(arr) / sizeof(int);
    twoWaySort(arr, n);
    for (int i = 0; i < n; i++)
        cout << arr[i] << " ";
    return 0;
}

Java

// Java program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order
import java.util.Arrays;
import java.util.Collections;
import java.util.List;
import java.util.ArrayList;

public class Main {
    // To do two way sort.
   // First sort even numbers in ascending order,
  // then odd numbers in descending order.
    public static void twoWaySort(int[] arr) {
        // To store odd Numbers
        List<Integer> odd = new ArrayList<>();

        // To store Even Numbers
        List<Integer> even = new ArrayList<>();

        for (int i = 0; i < arr.length; i++) {
            // If number is even, push them to the even list
            if (arr[i] % 2 == 0) {
                even.add(arr[i]);
            }
            // If number is odd, push them to the odd list
            else {
                odd.add(arr[i]);
            }
        }

        // Sort even list in ascending order
        Collections.sort(even);

        // Sort odd list in descending order
        Collections.sort(odd, Collections.reverseOrder());

        int i = 0;

        // First store odd numbers in the array
        for (int j = 0; j < odd.size(); j++) {
            arr[i] = odd.get(j);
            i++;
        }

        // Then store even numbers in the array
        for (int j = 0; j < even.size(); j++) {
            arr[i] = even.get(j);
            i++;
        }
    }

    // Driver code
    public static void main(String[] args) {
        int[] arr = { 1, 3, 2, 7, 5, 4 };
        twoWaySort(arr);
        for (int i = 0; i < arr.length; i++) {
            System.out.print(arr[i] + " ");
        }
    }
}

Python3

def twoWaySort(arr, n):
    # To store odd Numbers
    odd = []
    # To store Even Numbers
    even = []
    for i in range(n):
        # If number is even push them to even vector
        if arr[i] % 2 == 0:
            even.append(arr[i])
        # If number is odd push them to odd vector
        else:
            odd.append(arr[i])
    # Sort even array in ascending order
    even.sort()
    # Sort odd array in descending order
    odd.sort(reverse=True)
    i = 0
    # First store odd numbers to array
    for j in range(len(odd)):
        arr[i] = odd[j]
        i += 1
    # Then store even numbers to array
    for j in range(len(even)):
        arr[i] = even[j]
        i += 1


arr = [1, 3, 2, 7, 5, 4]
n = len(arr)
twoWaySort(arr, n)
for i in range(n):
    print(arr[i], end=" ")

C#

// C# program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order
using System;
using System.Collections.Generic;
using System.Linq;

class Program {
    // To do two-way sort. First sort even numbers in
    // ascending order, then odd numbers in descending
    // order.
    static void TwoWaySort(int[] arr, int n)
    {
        // To store odd numbers
        List<int> odd = new List<int>();

        // To store even numbers
        List<int> even = new List<int>();

        for (int i = 0; i < n; i++) {
            // If number is even, push them to even list
            if (arr[i] % 2 == 0) {
                even.Add(arr[i]);
            }
            // If number is odd, push them to odd list
            else {
                odd.Add(arr[i]);
            }
        }

        // Sort even list in ascending order
        even.Sort();

        // Sort odd list in descending order
        odd.Sort();
        odd.Reverse();

        int index = 0;

        // First store odd numbers in the array
        foreach(int number in odd)
        {
            arr[index] = number;
            index++;
        }

        // Then store even numbers in the array
        foreach(int number in even)
        {
            arr[index] = number;
            index++;
        }
    }

    // Driver code
    static void Main(string[] args)
    {
        int[] arr = { 1, 3, 2, 7, 5, 4 };
        int n = arr.Length;
        TwoWaySort(arr, n);
        for (int i = 0; i < n; i++) {
            Console.Write(arr[i] + " ");
        }
    }
}

// This code is contributed by akshitaguprzj3

Javascript

// Javascript program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order

// Function to do two-way sort.
// First sort even numbers in ascending order,
// then odd numbers in descending order.
function twoWaySort(arr) {
  // To store odd numbers
  let odd = [];

  // To store even numbers
  let even = [];

  for (let i = 0; i < arr.length; i++) {
    // If number is even, push it to the even list
    if (arr[i] % 2 === 0) {
      even.push(arr[i]);
    }
    // If number is odd, push it to the odd list
    else {
      odd.push(arr[i]);
    }
  }

  // Sort the even list in ascending order
  even.sort((a, b) => a - b);

  // Sort the odd list in descending order
  odd.sort((a, b) => b - a);

  let index = 0;

  // First, store the odd numbers in the array
  for (let j = 0; j < odd.length; j++) {
    arr[index] = odd[j];
    index++;
  }

  // Then, store the even numbers in the array
  for (let j = 0; j < even.length; j++) {
    arr[index] = even[j];
    index++;
  }
}

// Driver code
let arr = [1, 3, 2, 7, 5, 4];
twoWaySort(arr);
console.log(arr.join(" "));


// This code is contributed by shivamgupta0987654321

Output

7 5 3 1 2 4 

Time complexity: O(n + n log n) , for sorting even vector and odd vector and running a for loop
Auxiliary Space: O(n), because there are in total n elements in both the vector

Method 1 (Using Partition)

1. Partition the input array such that all odd elements are moved to the left and all even elements on right. This step takes O(n).
2. Once the array is partitioned, sort left and right parts individually. This step takes O(n Log n).

Follow the below steps to implement the above idea:

• Initialize two variables l and r to 0 and n-1 respectively.
• Initialize a variable k to 0 which will count the number of odd elements in the array.
• Run a loop while l < r:
                a. Find the first even number from the left side of the array by checking if arr[l] is even, if not increment l and k by 1.
                b. Find the first odd number from the right side of the array by checking if arr[r] is odd, if not decrement r by 1.
                c. Swap the even number at index l with the odd number at index r.
• Sort the first k elements of the array in descending order using the in-built sort function with greater<int>() as the comparator.
• Sort the remaining n-k elements of the array in ascending order using the in-built sort function.
• The sorted array is now ready to be printed.

Below is the implementation of the above idea.  

C++

// C++ program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order
#include <bits/stdc++.h>
using namespace std;

// To do two way sort. First sort even numbers in
// ascending order, then odd numbers in descending
// order.
void twoWaySort(int arr[], int n)
{

    // Current indexes from left and right
    int l = 0, r = n - 1;

    // Count of odd numbers
    int k = 0;

    while (l < r)
    {

        // Find first even number
        // from left side.
        while (arr[l] % 2 != 0)
        {
            l++;
            k++;
        }

        // Find first odd number
        // from right side.
        while (arr[r] % 2 == 0 && l < r)
            r--;

        // Swap even number present on left and odd
        // number right.
        if (l < r)
            swap(arr[l], arr[r]);
    }

    // Sort odd number in descending order
    sort(arr, arr + k, greater<int>());

    // Sort even number in ascending order
    sort(arr + k, arr + n);
}

// Driver code
int main()
{
    int arr[] = { 1, 3, 2, 7, 5, 4 };
    int n = sizeof(arr) / sizeof(int);
    twoWaySort(arr, n);
    for (int i = 0; i < n; i++)
        cout << arr[i] << " ";
    return 0;
}

Java

// Java program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order

import java.util.Arrays;
import java.util.Collections;

public class GFG {
    // To do two way sort. First sort even numbers in
    // ascending order, then odd numbers in descending
    // order.
    static void twoWaySort(Integer arr[], int n)
    {
        // Current indexes from left and right
        int l = 0, r = n - 1;

        // Count of odd numbers
        int k = 0;

        while (l < r)
        {

            // Find first even number from left side.
            while (arr[l] % 2 != 0)
            {
                l++;
                k++;
            }

            // Find first odd number from right side.
            while (arr[r] % 2 == 0 && l < r)
                r--;

            // Swap even number present on left and odd
            // number right.
            if (l < r)
            {

                // swap arr[l] arr[r]
                int temp = arr[l];
                arr[l] = arr[r];
                arr[r] = temp;
            }
        }

        // Sort odd number in descending order
        Arrays.sort(arr, 0, k, Collections.
                                  reverseOrder());

        // Sort even number in ascending order
        Arrays.sort(arr, k, n);
    }

    // Driver Method
    public static void main(String[] args)
    {
        Integer arr[] = { 1, 3, 2, 7, 5, 4 };

        twoWaySort(arr, arr.length);

        System.out.println(Arrays.toString(arr));
    }
}

Python

# Python program to sort array
# in even and odd manner
# The odd numbers are to be
# sorted in descending order
# and the even numbers in
# ascending order

# To do two way sort. First
# sort even numbers in ascending
# order, then odd numbers in
# descending order.
def two_way_sort(arr, arr_len):

    # Current indexes l->left
    # and r->right
    l, r = 0, arr_len - 1

    # Count of number of
    # odd numbers, used in
    # slicing the array later.
    k = 0

    # Run till left(l) < right(r)
    while(l < r):

        # While left(l) is odd, if yes
        # increment the left(l) plus
        # odd count(k) if not break the
        # while for even number found
        # here to be swapped
        while(arr[l] % 2 != 0):
            l += 1
            k += 1

        # While right(r) is even,
        # if yes decrement right(r)
        # if not break the while for
        # odd number found here to
        # be swapped
        while(arr[r] % 2 == 0 and l < r):
            r -= 1

        # Swap the left(l) and right(r),
        # which is even and odd numbers
        # encountered in above loops
        if(l < r):
            arr[l], arr[r] = arr[r], arr[l]

    # Slice the number on the
    # basis of odd count(k)
    odd = arr[:k]
    even = arr[k:]

    # Sort the odd and
    # even array accordingly
    odd.sort(reverse = True)
    even.sort()

    # Extend the odd array with
    # even values and return it.
    odd.extend(even)

    return odd

# Driver code
arr_len = 6
arr = [1, 3, 2, 7, 5, 4]
result = two_way_sort(arr, arr_len)
for i in result:
    print(str(i) + " "),

# This code is contributed
# by JaySiyaRam

C#

// C# program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order
using System;
using System.Linq;

class GFG {
    // To do two way sort. First sort even numbers in
    // ascending order, then odd numbers in descending
    // order.
    static void twoWaySort(int[] arr, int n)
    {
        // Current indexes from left and right
        int l = 0, r = n - 1;

        // Count of odd numbers
        int k = 0;

        while (l < r)
        {

            // Find first even number
            // from left side.
            while (arr[l] % 2 != 0)
            {
                l++;
                k++;
            }

            // Find first odd number from right side.
            while (arr[r] % 2 == 0 && l < r)
                r--;

            // Swap even number present
            // on left and odd
            // number right.
            if (l < r) {
                // swap arr[l] arr[r]
                int temp = arr[l];
                arr[l] = arr[r];
                arr[r] = temp;
            }
        }

        // Sort odd number in descending order
        Array.Sort(arr, 0, k);
        Array.Reverse(arr, 0, k);

        // Sort even number in ascending order
        Array.Sort(arr, k, n - k);
    }

    // Driver Method
    public static void Main(String[] args)
    {
        int[] arr = { 1, 3, 2, 7, 5, 4 };

        twoWaySort(arr, arr.Length);

        Console.WriteLine(String.Join(" ", arr));
    }
}

// This code has been contributed by 29AjayKumar

Javascript

<script>

// Javascript program sort array
// in even and odd manner.
// The odd numbers are to be
// sorted in descending
// order and the even numbers in
// ascending order

    // To do two way sort.
    // First sort even numbers in
    // ascending order, then odd
    // numbers in descending
    // order.
    function twoWaySort(arr,n)
    {
        // Current indexes from
        // left and right
        let l = 0, r = n - 1;

        // Count of odd numbers
        let k = 0;

        while (l < r)
        {

            // Find first even number
            // from left side.
            while (arr[l] % 2 != 0)
            {
                l++;
                k++;
            }

            // Find first odd number
            // from right side.
            while (arr[r] % 2 == 0 && l < r)
                r--;

            // Swap even number present
            // on left and odd
            // number right.
            if (l < r)
            {

                // swap arr[l] arr[r]
                let temp = arr[l];
                arr[l] = arr[r];
                arr[r] = temp;
            }
        }

        let odd=new Array(k);
        for(let i=0;i<k;i++)
        {
            odd[i]=arr[i];
        }
        let even=new Array(n-k);
        for(let i=0;i<n-k;i++)
        {
            even[i]=arr[k+i];
        }
        // Sort odd number in descending order
        odd.sort(function(a,b){return b-a;});
        // Sort even number in ascending order
        even.sort(function(a,b){return a-b;});

        return odd.concat(even);

    }
    // Driver Method
    let arr=[1, 3, 2, 7, 5, 4 ];
    let ans=twoWaySort(arr, arr.length);
    for(let i=0;i<ans.length;i++)
    {
        document.write(ans[i]+" ");
    }


    // This code is contributed by rag2127

</script>

Output

7 5 3 1 2 4 

Time complexity: O(n log n) 
Auxiliary Space: O(1)

Method 2 (Using negative multiplication) :

1. Make all odd numbers negative.
2. Sort all numbers.
3. Revert the changes made in step 1 to get original elements back.

Implementation:

C++

// C++ program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order
#include <bits/stdc++.h>
using namespace std;

// To do two way sort. First sort even numbers in
// ascending order, then odd numbers in descending
// order.
void twoWaySort(int arr[], int n)
{
    // Make all odd numbers negative
    for (int i = 0; i < n; i++)
        if (arr[i] & 1) // Check for odd
            arr[i] *= -1;

    // Sort all numbers
    sort(arr, arr + n);

    // Retaining original array
    for (int i = 0; i < n; i++)
        if (arr[i] & 1)
            arr[i] *= -1;
}

// Driver code
int main()
{
    int arr[] = { 1, 3, 2, 7, 5, 4 };
    int n = sizeof(arr) / sizeof(int);
    twoWaySort(arr, n);
    for (int i = 0; i < n; i++)
        cout << arr[i] << " ";
    return 0;
}

Java

// Java program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order

import java.util.Arrays;

public class GFG
{
    // To do two way sort. First sort even numbers in
    // ascending order, then odd numbers in descending
    // order.
    static void twoWaySort(int arr[], int n)
    {
        // Make all odd numbers negative
        for (int i = 0; i < n; i++)
            if ((arr[i] & 1) != 0) // Check for odd
                arr[i] *= -1;

        // Sort all numbers
        Arrays.sort(arr);

        // Retaining original array
        for (int i = 0; i < n; i++)
            if ((arr[i] & 1) != 0)
                arr[i] *= -1;
    }

    // Driver Method
    public static void main(String[] args)
    {
        int arr[] = { 1, 3, 2, 7, 5, 4 };

        twoWaySort(arr, arr.length);

        System.out.println(Arrays.toString(arr));
    }
}

Python3

# Python 3 program to sort array in
# even and odd manner. The odd
# numkbers are to be sorted in
# descending order and the even
# numbers in ascending order

# To do two way sort. First sort
# even numbers in ascending order,
# then odd numbers in descending order.
def twoWaySort(arr, n):

    # Make all odd numbers negative
    for i in range(0, n):

        # Check for odd
        if (arr[i] & 1):
            arr[i] *= -1

    # Sort all numbers
    arr.sort()

    # Retaining original array
    for i in range(0, n):
        if (arr[i] & 1):
            arr[i] *= -1

# Driver code
arr = [1, 3, 2, 7, 5, 4]
n = len(arr)
twoWaySort(arr, n);
for i in range(0, n):
    print(arr[i], end = " ")

# This code is contributed by Smitha Dinesh Semwal

C#

// Java program sort array in even and
// odd manner. The odd numbers are to
// be sorted in descending order and
// the even numbers in ascending order
using System;

public class GFG
{

    // To do two way sort. First sort
    // even numbers in ascending order,
    // then odd numbers in descending
    // order.
    static void twoWaySort(int[] arr, int n)
    {

        // Make all odd numbers negative
        for (int i = 0; i < n; i++)

            // Check for odd
            if ((arr[i] & 1) != 0)
                arr[i] *= -1;

        // Sort all numbers
        Array.Sort(arr);

        // Retaining original array
        for (int i = 0; i < n; i++)
            if ((arr[i] & 1) != 0)
                arr[i] *= -1;
    }

    // Driver Method
    public static void Main()
    {
        int[] arr = { 1, 3, 2, 7, 5, 4 };

        twoWaySort(arr, arr.Length);

        for (int i = 0; i < arr.Length; i++)
            Console.Write(arr[i] + " ");
    }
}

// This code is contributed by Smitha

Javascript

<script>

// Javascript program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order

// To do two way sort. First sort even numbers in
// ascending order, then odd numbers in descending
// order.
function twoWaySort(arr, n)
{
    // Make all odd numbers negative
    for (let i = 0; i < n; i++)
        if (arr[i] & 1) // Check for odd
            arr[i] *= -1;

    // Sort all numbers
    arr.sort((a,b) => a-b);

    // Retaining original array
    for (let i = 0; i < n; i++)
        if (arr[i] & 1)
            arr[i] *= -1;
}

// Driver code

    let arr = [ 1, 3, 2, 7, 5, 4 ];
    let n = arr.length;
    twoWaySort(arr, n);
    for (let i = 0; i < n; i++)
        document.write(arr[i] + " ");

//This code is contributed by Mayank Tyagi
</script>

PHP

<?php
// PHP program sort array in even and odd manner.
// The odd numbers are to be sorted in descending
// order and the even numbers in ascending order

// To do two way sort. First sort even numbers in
// ascending order, then odd numbers in descending
// order.
function twoWaySort(&$arr, $n)
{
    // Make all odd numbers negative
    for ($i = 0 ; $i < $n; $i++)
        if ($arr[$i] & 1) // Check for odd
            $arr[$i] *= -1;

    // Sort all numbers
    sort($arr);

    // Retaining original array
    for ($i = 0 ; $i < $n; $i++)
        if ($arr[$i] & 1)
            $arr[$i] *= -1;
}

// Driver code
$arr = array(1, 3, 2, 7, 5, 4);
$n = sizeof($arr);
twoWaySort($arr, $n);
for ($i = 0; $i < $n; $i++)
    echo $arr[$i] . " ";

// This code is contributed by ita_c
?>

Output

7 5 3 1 2 4 

Time complexity: O(n log n) 
Auxiliary Space: O(1)

This method may not work when input array contains negative numbers. However, there is a way to handle this. We count the positive odd integers in the input array then sort again. Readers may refer this for implementation.

Method 3 (Using comparator):
This problem can be easily solved by using the inbuilt sort function with a custom compare method. On comparing any two elements there will be three cases: 

1. When both the elements are even: In this case, the smaller element must appear in the left of the larger element in the sorted array.
2. When both the elements are odd: The larger element must appear on left of the smaller element.
3. One is odd and the other is even: The element which is odd must appear on the left of the even element.

Below is the implementation of the above approach: 

CPP

// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;

// Utility function to print
// the contents of the array
void printArr(int arr[], int n)
{
    for (int i = 0; i < n; i++)
        cout << arr[i] << " ";
}

// To do two way sort. Make comparator function
// for the inbuilt sort function of c++ such that
// odd numbers are placed before even in descending
// and ascending order respectively
bool compare(int a, int b)
{

    // If both numbers are even,
    // smaller number should
    // be placed at lower index
    if (a % 2 == 0 && b % 2 == 0)
        return a < b;

    // If both numbers are odd larger number
    // should be placed at lower index
    if (a % 2 != 0 && b % 2 != 0)
        return b < a;

    // If a is odd and b is even,
    // a should be placed before b
    if (a % 2 != 0)
        return true;

    // If b is odd and a is even,
    // b should be placed before a
    return false;
}

// Driver code
int main()
{
    int arr[] = { 1, 3, 2, 7, 5, 4 };
    int n = sizeof(arr) / sizeof(int);

    // Sort the array
    sort(arr, arr + n, compare);

    // Print the sorted array
    printArr(arr, n);

    return 0;
}

// This code is contributed by Nikhil Yadav

Java

// Java implementation of the approach
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;

class GFG
{

    // Utility function to print
    // the contents of the array
    static void printArr(ArrayList<Integer> arr, int n) {
        for (int i = 0; i < n; i++)
            System.out.print(arr.get(i) + " ");
    }

    // Driver code
    public static void main(String args[]) {
        ArrayList<Integer> arr = new ArrayList<Integer>();
        arr.add(1);
        arr.add(3);
        arr.add(2);
        arr.add(7);
        arr.add(5);
        arr.add(4);
        int n = arr.size();


        // Sort the array
        Collections.sort(arr, new Comparator<Integer>() {
            @Override
            public int compare(Integer a, Integer b) {

                // If both numbers are even,
                // smaller number should
                // be placed at lower index
                if (a % 2 == 0 && b % 2 == 0)
                    return (a - b);

                // If both numbers are odd larger number
                // should be placed at lower index
                if (a % 2 != 0 && b % 2 != 0)
                    return (b - a);

                // If a is odd and b is even,
                // a should be placed before b
                if (a % 2 != 0)
                    return -1;

                // If b is odd and a is even,
                // b should be placed before a
                return 0;
            }
        });

        // Print the sorted array
        printArr(arr, n);
    }
}

// This code is contributed by Saurabh Jaiswal

Python3

# Python3 implementation of the approach

# Utility function to print
# the contents of the array
from functools import cmp_to_key

def printArr(arr, n):

    for i in range(n):
        print(arr[i], end = " ")

        # To do two way sort. Make comparator function
        # for the inbuilt sort function of c++ such that
        # odd numbers are placed before even in descending
        # and ascending order respectively
def compare(a, b):

    # If both numbers are even,
    # smaller number should
    # be placed at lower index
    if (a % 2 == 0 and b % 2 == 0 and a < b):
        return -1

    # If both numbers are odd larger number
    # should be placed at lower index
    if (a % 2 != 0 and b % 2 != 0 and b > a):
        return 1

    # If a is odd and b is even,
    # a should be placed before b
    if (a % 2 != 0):
        return -1

    # If b is odd and a is even,
    # b should be placed before a
    return 1

# Driver code
arr = [1, 3, 2, 7, 5, 4]
n = len(arr)

# Sort the array
arr.sort(key = cmp_to_key(compare))

# Print the sorted array
printArr(arr, n)

# This code is contributed by shinjanpatra

C#

// C# implementation of the approach
using System;
using System.Collections.Generic;

public class GFG
{

  // Utility function to print
  // the contents of the array
  static void printArr(List<int> arr, int n) {
    for (int i = 0; i < n; i++)
      Console.Write(arr[i] + " ");
  }
  private static int Compare(int a, int b)
  {

    // If both numbers are even,
    // smaller number should
    // be placed at lower index
    if (a % 2 == 0 && b % 2 == 0 && a<b)
      return -1;

    // If both numbers are odd larger number
    // should be placed at lower index
    if (a % 2 != 0 && b % 2 != 0 && b>a)
      return 1;

    // If a is odd and b is even,
    // a should be placed before b
    if (a % 2 != 0)
      return -1;

    // If b is odd and a is even,
    // b should be placed before a
    return 1;
  }

  // Driver code
  public static void Main(String []args) {
    List<int> arr = new List<int>();
    arr.Add(1);
    arr.Add(3);
    arr.Add(2);
    arr.Add(7);
    arr.Add(5);
    arr.Add(4);
    int n = arr.Count;

    // Sort the array
    arr.Sort(Compare);

    // Print the sorted array
    printArr(arr, n);
  }
}


// This code is contributed by 29AjayKumar

Javascript

<script>
        // JavaScript implementation of the approach

        // Utility function to print
        // the contents of the array
        function printArr(arr, n)
        {
            for (let i = 0; i < n; i++)
                document.write(arr[i] + " ");
        }

        // To do two way sort. Make comparator function
        // for the inbuilt sort function of c++ such that
        // odd numbers are placed before even in descending
        // and ascending order respectively
        function compare(a, b) {

            // If both numbers are even,
            // smaller number should
            // be placed at lower index
            if (a % 2 == 0 && b % 2 == 0 && a < b)
                return -1;

            // If both numbers are odd larger number
            // should be placed at lower index
            if (a % 2 != 0 && b % 2 != 0 && b > a)
                return 1;

            // If a is odd and b is even,
            // a should be placed before b
            if (a % 2 != 0)
                return -1;

            // If b is odd and a is even,
            // b should be placed before a
            return 1;
        }

        // Driver code
        var arr = [1, 3, 2, 7, 5, 4];
        var n = arr.length;

        // Sort the array
        arr.sort(compare);

        // Print the sorted array
        printArr(arr, n);

// This code is contributed by Potta Lokesh
    </script>

Output

7 5 3 1 2 4 

Time complexity : O(n*logn) [sort function has average time complexity n*logn]
Auxiliary Space : O(1)

Thanks to Amandeep Singh for suggesting this solution.

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