# Sort an array of strings according to string lengths

• Difficulty Level : Easy
• Last Updated : 22 Sep, 2022

We are given an array of strings, we need to sort the array in increasing order of string lengths.
Examples:

Input : {“GeeksforGeeeks”, “I”, “from”, “am”}
Output : I am from GeeksforGeeks

Input :  {“You”, “are”, “beautiful”, “looking”}
Output : You are looking beautiful

A simple solution is to write our own sort function that compares string lengths to decide which string should come first. Below is the implementation, that uses Insertion Sort to sort the array.

Algorithm:

1. Initialize the string with the input words.
2. Calculate the string length.
3. Sort the string array according to the length of words in ascending order With the help of insertion sort.
4. Print the sorted array.

Below is the implementation of the above approach:

## C++

 `// C++ program to sort an Array of``// Strings according to their lengths``#include``using` `namespace` `std;` `// Function to print the sorted array of string``void` `printArraystring(string,``int``);` `// Function to Sort the array of string``// according to lengths. This function``// implements Insertion Sort.``void` `sort(string s[], ``int` `n)``{``    ``for` `(``int` `i=1 ;i= 0 && temp.length() < s[j].length())``        ``{``            ``s[j+1] = s[j];``            ``j--;``        ``}``        ``s[j+1] = temp;``    ``}``}`` ` `// Function to print the sorted array of string``void` `printArraystring(string str[], ``int` `n)``{``    ``for` `(``int` `i=0; i

## Java

 `// Java program to sort an Array of``// Strings according to their lengths``import` `java.util.*;` `class` `solution``{` `// Function to print the sorted array of string``// void printArraystring(string,int);` `// Function to Sort the array of string``// according to lengths. This function``// implements Insertion Sort.``static` `void` `sort(String []s, ``int` `n)``{``    ``for` `(``int` `i=``1` `;i= ``0` `&& temp.length() < s[j].length())``        ``{``            ``s[j+``1``] = s[j];``            ``j--;``        ``}``        ``s[j+``1``] = temp;``    ``}``}` `// Function to print the sorted array of string``static` `void` `printArraystring(String str[], ``int` `n)``{``    ``for` `(``int` `i=``0``; i

## Python3

 `# Python3 program to sort an Array of``# Strings according to their lengths` `# Function to print the sorted array of string``def` `printArraystring(string, n):``    ``for` `i ``in` `range``(n):``        ``print``(string[i], end ``=` `" "``)` `# Function to Sort the array of string``# according to lengths. This function``# implements Insertion Sort.``def` `sort(s, n):``    ``for` `i ``in` `range``(``1``, n):``        ``temp ``=` `s[i]` `        ``# Insert s[j] at its correct position``        ``j ``=` `i ``-` `1``        ``while` `j >``=` `0` `and` `len``(temp) < ``len``(s[j]):``            ``s[j ``+` `1``] ``=` `s[j]``            ``j ``-``=` `1` `        ``s[j ``+` `1``] ``=` `temp` `# Driver code``if` `__name__ ``=``=` `"__main__"``:``    ``arr ``=` `[``"GeeksforGeeks"``, ``"I"``, ``"from"``, ``"am"``]``    ``n ``=` `len``(arr)` `    ``# Function to perform sorting``    ``sort(arr, n)` `    ``# Calling the function to print result``    ``printArraystring(arr, n)` `# This code is contributed by``# sanjeev2552`

## C#

 `    ` `// C# program to sort an Array of``// Strings according to their lengths``using` `System;`` ` `public` `class` `solution{` `    ``// Function to print the sorted array of string``    ``// void printArraystring(string,int);` `    ``// Function to Sort the array of string``    ``// according to lengths. This function``    ``// implements Insertion Sort.``    ``static` `void` `sort(String []s, ``int` `n)``    ``{``        ``for` `(``int` `i=1 ;i= 0 && temp.Length < s[j].Length)``            ``{``                ``s[j+1] = s[j];``                ``j--;``            ``}``            ``s[j+1] = temp;``        ``}``    ``}` `    ``// Function to print the sorted array of string``    ``static` `void` `printArraystring(String []str, ``int` `n)``    ``{``        ``for` `(``int` `i=0; i

## Javascript

 ``

Output

`I am from GeeksforGeeks `

Time Complexity: O(n*m), where m is the length of the string and n is the size of the input array.
Auxiliary Space: O(1)

A better solution is to use the sort function provided by programming languages like C++, Java. These functions also allow us to write our own custom comparator. Below is C++ implementation that uses C++ STL Sort function

Algorithm:

1. Initialize the string with the input words.
2. Calculate the string length.
3. Compare the strings and return the smallest one.
4. Sort the string array with the help of the built-in sort function.
5. Print the sorted array.

Below is the implementation of the above approach:

## CPP

 `#include ``using` `namespace`  `std;` `// Function to check the small string``bool` `compare(string &s1,string &s2)``{``    ``return` `s1.size() < s2.size();``}` `// Function to print the sorted array of string``void` `printArraystring(string str[], ``int` `n)``{``    ``for` `(``int` `i=0; i

## Java

 `import` `java.util.Arrays;``import` `java.util.Comparator;` `class` `GFG {` `  ``// Function to check the small String` `  ``// Function to print the sorted array of String``  ``static` `void` `printArrayString(String str[], ``int` `n) {``    ``for` `(``int` `i = ``0``; i < n; i++)``      ``System.out.print(str[i] + ``" "``);``  ``}` `  ``// Driver function``  ``public` `static` `void` `main(String[] args) {``    ``String arr[] = { ``"GeeksforGeeks"``, ``"I"``, ``"from"``, ``"am"` `};``    ``int` `n = arr.length;` `    ``// Function to perform sorting``    ``Arrays.sort(arr, Comparator.comparing(s->s.length()));` `    ``// Calling the function to print result``    ``printArrayString(arr, n);``  ``}``}` `// This code is contributed by 29AjayKumar`

## Javascript

 ``

## Python3

 `from` `functools ``import` `cmp_to_key` `# Function to check the small string``def` `compare(s1,s2):``    ``return` `len``(s1) ``-` `len``(s2)` `# Function to print the sorted array of string``def` `printArraystring(``str``,n):``    ``for` `i ``in` `range``(n):``        ``print``(``str``[i],end ``=` `" "``)` `# Driver function``arr ``=` `[``"GeeksforGeeks"``, ``"I"``, ``"from"``, ``"am"``]``n ``=` `len``(arr)` `# Function to perform sorting``arr.sort(key ``=` `cmp_to_key(compare))` `# Calling the function to print result``printArraystring(arr, n)` `# This code is contributed by shinjanpatra.`

Output

`I am from GeeksforGeeks `

Time Complexity: O(nlogn), where n is the size of the array.
Auxiliary Space: O(1)

Method 2: Simplified solution using sorted() function in python

1. Take string as a list.
2. Use the sorted function in python by providing the key as len.

Below is the implementation of the above approach:

## Python3

 `# Python code for the above approach``def` `printsorted(arr):``  ` `    ``# Sorting using sorted function``    ``# providing key as len``    ``print``(``*``sorted``(arr, key``=``len``))`  `# Driver code``arr ``=` `[``"GeeksforGeeks"``, ``"I"``, ``"from"``, ``"am"``]` `# Passing list to printsorted function``printsorted(arr)` `# this code is contributed by vikkycirus`

Output

`I am from GeeksforGeeks`

Time Complexity: O(nlogn)
Auxiliary Space: O(1)

This article is contributed by Rishabh jain. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

My Personal Notes arrow_drop_up