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Sort an array of strings lexicographically based on prefix

  • Difficulty Level : Easy
  • Last Updated : 31 Aug, 2021

Given an array of strings arr[] of size N, the task is to sort the array of strings in lexicographical order and if while sorting for any two string A and string B, if string A is prefix of string B then string B should come in the sorted order.

Examples:

Input: arr[] = {“sun”, “moon”, “mock”} 
Output: 
mock 
moon 
sun 
Explanation: 
The lexicographical sorting is mock, moon, and sun.

Input: arr[] = {“geeks”, “geeksfor”, “geeksforgeeks”} 
Output: 
geeksforgeeks 
geeksfor 
geeks 
 

Approach: The idea is to sort the given array of strings using the inbuilt sort function using the below comparator function. The comparator function used to check if any string occurs as a substring in another string using compare() function in C++ then, it should arrange them in decreasing order of their length.



C++




bool my_compare(string a, string b)
{
    // If any string is a substring then
    // return the size with greater length
    if (a.compare(0, b.size(), b) == 0
        || b.compare(0, a.size(), a) == 0)
        return a.size() & gt;
    b.size();
 
    // Else return lexicographically
    // smallest string
    else return a & lt;
    b;
}

Below is the implementation of the above approach:

C++




// C++ program for the above approach
 
#include <bits/stdc++.h>
using namespace std;
 
// Function to print the vector
void Print(vector<string> v)
{
    for (auto i : v)
        cout << i << endl;
}
 
// Comparator function to sort the
// array of string wrt given conditions
bool my_compare(string a, string b)
{
    // Check if a string is present as
    // prefix in another string, then
    // compare the size of the string
    // and return the larger size
    if (a.compare(0, b.size(), b) == 0
        || b.compare(0, a.size(), a) == 0)
 
        return a.size() > b.size();
 
    // Else return lexicographically
    // smallest string
    else
        return a < b;
}
 
// Driver Code
int main()
{
    // GIven vector of strings
    vector<string> v = { "batman", "bat", "apple" };
 
    // Calling Sort STL with my_compare
    // function passed as third parameter
    sort(v.begin(), v.end(), my_compare);
 
    // Function call to print the vector
    Print(v);
    return 0;
}
Output: 
apple
batman
bat

 

Time Complexity: O(N*log N)
Auxiliary Space: O(1)

 

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