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# Smallest odd number with N digits

• Last Updated : 25 Mar, 2021

Given a number N. The task is to find the smallest N digit ODD number.
Examples:

```Input: N = 1
Output: 1

Input: N = 3
Output: 101 ```

Approach: There can be two cases depending on the value of N.
Case 1 : If N = 1 then answer will be 1.
Case 2 : If N != 1 then answer will be (10^(n-1)) + 1 because the series of the smallest odd numbers will go on like: 1, 11, 101, 1001, 10001, 100001, ….
Below is the implementation of the above approach:

## C++

 `// C++ implementation of the above approach` `#include ``using` `namespace` `std;` `// Function to return smallest odd``// with n digits``int` `smallestOdd(``int` `n)``{``    ``if` `(n == 1)``        ``return` `1;` `    ``return` `pow``(10, n - 1) + 1;``}` `// Driver Code``int` `main()``{``    ``int` `n = 4;``    ``cout << smallestOdd(n);` `    ``return` `0;``}`

## Java

 `// Java implementation of the approach``class` `Solution {` `    ``// Function to return smallest odd with n digits``    ``static` `int` `smallestOdd(``int` `n)``    ``{``        ``if` `(n == ``1``)``            ``return` `0``;``        ``return` `Math.pow(``10``, n - ``1``) + ``1``;``    ``}` `    ``// Driver code``    ``public` `static` `void` `main(String args[])``    ``{``        ``int` `n = ``4``;` `        ``System.out.println(smallestOdd(n));``    ``}``}`

## Python3

 `# Python3 implementation of the approach` `# Function to return smallest even``# number with n digits``def` `smallestOdd(n) :` `    ``if` `(n ``=``=` `1``):``        ``return` `1``    ``return` `pow``(``10``, n ``-` `1``) ``+` `1` `# Driver Code``n ``=` `4``print``(smallestOdd(n))` `# This code is contributed by ihritik.`

## C#

 `// C# implementation of the approach``using` `System;``class` `Solution {` `    ``// Function to return smallest odd with n digits``    ``static` `int` `smallestOdd(``int` `n)``    ``{``        ``if` `(n == 1)``            ``return` `0;` `        ``return` `Math.pow(10, n - 1) + 1;``    ``}` `    ``// Driver code``    ``public` `static` `void` `Main()``    ``{``        ``int` `n = 4;` `        ``Console.Write(smallestOdd(n));``    ``}``}`

## PHP

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## Javascript

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Output:
`1001`

Time Complexity: O(1).

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