# Smallest number required to be added to M to make it divisible by N

Given two positive integers **M** and **N**, the task is to calculate the smallest number that needs to be added to **M**, to make it divisible by **N**.

**Examples:**

Input:M = 6, N = 7Output:1Explanation:1 is the smallest number that can be added to 6 to make it divisible by 7.

Input:M = 100, N = 28Output:12

**Approach: **The idea is to find the smallest number greater than or equal to **M**, that is divisible by **N**, and then subtract **M** from it. To get the smallest multiple of **N** **â‰¥ M**, divide **M + N** by **N**. If the remainder is **0**, then the value is **M**. Otherwise, the value is **M + N â€“ remainder**.

Below is the implementation of the above approach:

## C++

`// C++ program for the above approach` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to find the smallest` `// number greater than or equal` `// to N, that is divisible by k` `int` `findNum(` `int` `N, ` `int` `K)` `{` ` ` `int` `rem = (N + K) % K;` ` ` `if` `(rem == 0)` ` ` `return` `N;` ` ` `else` ` ` `return` `N + K - rem;` `}` `// Function to find the smallest` `// number required to be added to` `// to M to make it divisible by N` `int` `findSmallest(` `int` `M, ` `int` `N)` `{` ` ` `// Stores the smallest multiple` ` ` `// of N, greater than or equal to M` ` ` `int` `x = findNum(M, N);` ` ` `// Return the result` ` ` `return` `x - M;` `}` `// Driver Code` `int` `main()` `{` ` ` `// Given Input` ` ` `int` `M = 100, N = 28;` ` ` `// Function Call` ` ` `cout << findSmallest(M, N);` ` ` `return` `0;` `}` |

## Java

`// Java program for the above approach` `class` `GFG{` `// Function to find the smallest` `// number greater than or equal` `// to N, that is divisible by k` `public` `static` `int` `findNum(` `int` `N, ` `int` `K)` `{` ` ` `int` `rem = (N + K) % K;` ` ` `if` `(rem == ` `0` `)` ` ` `return` `N;` ` ` `else` ` ` `return` `N + K - rem;` `}` `// Function to find the smallest` `// number required to be added to` `// to M to make it divisible by N` `public` `static` `int` `findSmallest(` `int` `M, ` `int` `N)` `{` ` ` ` ` `// Stores the smallest multiple` ` ` `// of N, greater than or equal to M` ` ` `int` `x = findNum(M, N);` ` ` `// Return the result` ` ` `return` `x - M;` `}` `// Driver Code` `public` `static` `void` `main(String args[])` `{` ` ` ` ` `// Given Input` ` ` `int` `M = ` `100` `, N = ` `28` `;` ` ` `// Function Call` ` ` `System.out.println(findSmallest(M, N));` `}}` `// This code is contributed by SoumikMondal` |

## Python3

`# Python3 program for the above approach` `# Function to find the smallest` `# number greater than or equal` `# to N, that is divisible by k` `def` `findNum(N, K):` ` ` ` ` `rem ` `=` `(N ` `+` `K) ` `%` `K` ` ` `if` `(rem ` `=` `=` `0` `):` ` ` `return` `N` ` ` `else` `:` ` ` `return` `N ` `+` `K ` `-` `rem` `# Function to find the smallest` `# number required to be added to` `# to M to make it divisible by N` `def` `findSmallest(M, N):` ` ` ` ` `# Stores the smallest multiple` ` ` `# of N, greater than or equal to M` ` ` `x ` `=` `findNum(M, N)` ` ` `# Return the result` ` ` `return` `x ` `-` `M` `# Driver Code` `if` `__name__ ` `=` `=` `'__main__'` `:` ` ` ` ` `# Given Input` ` ` `M ` `=` `100` ` ` `N ` `=` `28` ` ` `# Function Call` ` ` `print` `(findSmallest(M, N))` ` ` `# This code is contributed by ipg2016107` |

## C#

`// C# program for the above approach` `using` `System;` ` ` `class` `GFG{` ` ` `// Function to find the smallest` `// number greater than or equal` `// to N, that is divisible by k` `public` `static` `int` `findNum(` `int` `N, ` `int` `K)` `{` ` ` `int` `rem = (N + K) % K;` ` ` ` ` `if` `(rem == 0)` ` ` `return` `N;` ` ` `else` ` ` `return` `N + K - rem;` `}` ` ` `// Function to find the smallest` `// number required to be added to` `// to M to make it divisible by N` `public` `static` `int` `findSmallest(` `int` `M, ` `int` `N)` `{` ` ` ` ` `// Stores the smallest multiple` ` ` `// of N, greater than or equal to M` ` ` `int` `x = findNum(M, N);` ` ` ` ` `// Return the result` ` ` `return` `x - M;` `}` ` ` `// Driver Code` `public` `static` `void` `Main()` `{` ` ` ` ` `// Given Input` ` ` `int` `M = 100, N = 28;` ` ` ` ` `// Function Call` ` ` `Console.WriteLine(findSmallest(M, N));` `}` `}` `// This code is contributed by susmitakundugoaldanga` |

## Javascript

`<script>` `// Javascript program for the above approach` `// Function to find the smallest` `// number greater than or equal` `// to N, that is divisible by k` `function` `findNum(N, K)` `{` ` ` `var` `rem = (N + K) % K;` ` ` `if` `(rem == 0)` ` ` `return` `N;` ` ` `else` ` ` `return` `N + K - rem;` `}` `// Function to find the smallest` `// number required to be added to` `// to M to make it divisible by N` `function` `findSmallest(M, N)` `{` ` ` ` ` `// Stores the smallest multiple` ` ` `// of N, greater than or equal to M` ` ` `var` `x = findNum(M, N);` ` ` `// Return the result` ` ` `return` `x - M;` `}` `// Driver Code` `// Given Input` `var` `M = 100, N = 28;` `// Function Call` `document.write(findSmallest(M, N));` `// This code is contributed by itsok` `</script>` |

**Output:**

12

**Time Complexity:** O(1)**Auxiliary Space: **O(1)