Smallest number greater than or equal to N divisible by K

Given a number N and a number K, the task is to find the smallest number greater than or equal to N which is divisible by K.

Examples:

Input: N = 45, K = 6
Output: 48
48 is the smallest number greater than or equal to 45
which is divisible by 6.

Input: N = 11, K = 3
Output: 12

Approach: The idea is to divide the N+K by K. If the remainder is 0 then print N else print N + K – remainder.

Below is the implementation of the above approach :

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ implementation of the above approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to find the smallest number
// greater than or equal to N
// that is divisible by k
int findNum(int N, int K)
{
    int rem = (N + K) % K;
  
    if (rem == 0)
        return N;
    else
        return N + K - rem;
}
  
// Driver code
int main()
{
    int N = 45, K = 6;
  
    cout << "Smallest number greater than or equal to " << N
         << "\nthat is divisible by " << K << " is " << findNum(N, K);
  
    return 0;
}

chevron_right






                        filter_none









Java














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// Java implementation of the above approach 


  


public class GFG{ 


  


    // Function to find the smallest number 


    // greater than or equal to N 


    // that is divisible by k 


    static int findNum(int N, int K) 


    { 


        int rem = (N + K) % K; 


      


        if (rem == 0) 


            return N; 


        else


            return N + K - rem; 


    } 


  


  


     // Driver Code 


     public static void main(String []args){ 


           


        int N = 45, K = 6; 


  


    System.out.println("Smallest number greater than or equal to " + N 


          +"\nthat is divisible by " + K + " is " + findNum(N, K)); 


  


     } 


     // This code is contributed by ANKITRAI1 


} 



















                        chevron_right







                        filter_none









Python





# Python 3 implementation of the

# above approach 


# Function to find the smallest number

# greater than or equal to N

# that is divisible by k

def findNum(N, K):

	rem = (N + K) % K; 


	if (rem == 0):

		return N

	else:

		return (N + K – rem) 


# Driver Code

N = 45

K = 6

print(‘Smallest number greater than’,

                   ‘or equal to’ , N,

           ‘that is divisible by’, K,

               ‘is’ , findNum(45, 6))


# This code is contributed by Arnab Kundu



C#














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















// C# implementation of the above approach 


  


public class GFG{ 


  


    // Function to find the smallest number 


    // greater than or equal to N 


    // that is divisible by k 


    static int findNum(int N, int K) 


    { 


        int rem = (N + K) % K; 


      


        if (rem == 0) 


            return N; 


        else


            return N + K - rem; 


    } 


  


  


    // Driver Code 


    static void Main(){ 


          


        int N = 45, K = 6; 


  


    System.Console.WriteLine("Smallest number greater than or equal to " + N 


        +"\nthat is divisible by " + K + " is " + findNum(N, K)); 


  


    } 


    // This code is contributed by mits 


} 



















                        chevron_right







                        filter_none









PHP














                                    filter_none




                                    edit

                                    close




                                    play_arrow




                                    link

                                    brightness_4

                                    code
                                




















<?php 


// PHP implementation of the above approach 


  


// Function to find the smallest number 


// greater than or equal to N that is 


// divisible by k 


function findNum($N, $K) 


{ 


    $rem = ($N + $K) % $K; 


  


    if ($rem == 0) 


        return $N; 


    else


        return $N + $K - $rem; 


} 


  


// Driver code 


$N = 45; $K = 6; 


  


echo "Smallest number greater than " .  


                   "or equal to ", $N; 


echo "\nthat is divisible by " , $K ,  


            " is " , findNum($N, $K); 


  


// This code is contributed by anuj_67 


?> 



















                        chevron_right







                        filter_none











Output:


Smallest number greater than or equal to 45
that is divisible by 6 is 48






          
          
          
          

            

    

        My Personal Notes
        arrow_drop_up
    

    

        
        

            
            
        

    


Recommended Posts:
Shivam.Pradhan
Discovering ways to develop a plane for soaring career goals
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on  the "Improve Article" button below.