Given an integer N ≥ 1, the task is to find the smallest N digit number which is a multiple of 5.
Input: N = 1
Input: N = 2
Input: N = 3
- If N = 1 then the answer will be 5.
- If N > 1 then the answer will be (10(N – 1)) because the series of smallest multiple of 5 will go on like 10, 100, 1000, 10000, 100000, …
Below is the implementation of the above approach:
Time Complexity: O(1)
- Smallest integer with digit sum M and multiple of N
- Nth number whose sum of digit is multiple of 10
- Smallest K digit number divisible by X
- Largest and smallest digit of a number
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- Check if the first and last digit of the smallest number forms a prime
- Smallest multiple of N formed using the given set of digits
- Smallest multiple of 3 which consists of three given non-zero digits
- Smallest and Largest sum of two n-digit numbers
- Count of Numbers in Range where first digit is equal to last digit of the number
- Smallest and Largest N-digit perfect squares
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