Given a number N, the task is to find the smallest Even number with N digits.
Input: N = 1 Output: 0 Input: N = 2 Output: 10
Case 1 : If N = 1 then answer will be 0.
Case 2 : if N != 1 then answer will be (10^(N-1)) because the series of smallest even numbers will go on like, 0, 10, 100, 1000, 10000, 100000, …..
Below is the implementation of the above approach:
Time Complexity: O(1).
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Improved By : ihritik