Given an integer N ≥ 1, the task is to find the smallest and the largest sum of two N digit numbers.
Input: N = 1
Largest = 18
Smallest = 0
Largest 1-digit number is 9 and 9 + 9 = 18
Smallest 1-digit number is 0 and 0 + 0 = 0
Input: N = 2
Largest = 198
Smallest = 20
- For largest: The answer will be 2 * (10N – 1) because the series of sum of two n digit numbers will go on like 2 * 9, 2 * 99, 2 * 999, …
- For smallest:
- If N = 1 then the answer will be 0.
- If N > 1 then the answer will be 2 * (10N – 1) because the series of sum of two n digit numbers will go on like 0, 20, 200, 2000, …
Below is the implementation of the above approach:
Largest = 19998 Smallest = 2000
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- Find kth smallest number in range [1, n] when all the odd numbers are deleted
- K-th smallest element after removing given integers from natural numbers | Set 2
- Largest N digit number divisible by given three numbers
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