Given side of a square n and two points (x1, y1) and (x2, y2) on the boundaries of the given square. The task is to find the shortest path through the square sides between these two points where the corner coordinates of the square are are (0, 0), (n, 0), (0, n) and (n, n) .
Input: n = 2, x1 = 0, y1 = 0, x2 = 1, y2 = 0
Input: n = 26, x1 = 21, y1 = 0, x2 = 26, y2 = 14
- If both the x and y coordinates of a point is greater than the other and the points are not on opposite sides of square then the shortest distance will be abs(x2 – x1) + abs(y2 – y1).
- Else, the shortest distance will be equal to min((x1 + y1 + x2 + y2), (4 * n) – (x1 + y1 + x2 + y2))
Below is the implementation of the above approach:
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