Given a line passing through two points A and B and an arbitrary point C in a 3-D plane, the task is to find the shortest distance between the point C and the line passing through the points A and B.
Examples:
Input: A = (5, 2, 1), B = (3, 1, -1), C = (0, 2, 3) Output: Shortest Distance is 5 Input: A = (4, 2, 1), B = (3, 2, 1), C = (0, 2, 0) Output: Shortest Distance is 1
Consider a point C and a line that passes through A and B as shown in the below figure.
Now Consider the vectors, AB and AC and the shortest distance as CD. The Shortest Distance is always the perpendicular distance. The point D is taken on AB such that CD is perpendicular to AB.
Construct BP and CP as shown in the figure to form a Parallelogram. Now C is a vertex of parallelogram ABPC and CD is perpendicular to Side AB. Hence CD is the height of the parallelogram.
Note: In the case when D does not fall on line segment AB there will be a point D’ such that PD’ is perpendicular to AB and D’ lies on line segment AB with CD = PD’.
The magnitude of cross product AB and AC gives the Area of the parallelogram. Also, the area of a parallelogram is Base * Height = AB * CD. So,
CD = |ABxAC| / |AB|
Below is the CPP program to find the shortest distance:
// C++ program to find the Shortest // Distance Between A line and a // Given point. #include<bits/stdc++.h> using namespace std;
class Vector {
private :
int x, y, z;
// 3D Coordinates of the Vector
public :
Vector( int x, int y, int z)
{
// Constructor
this ->x = x;
this ->y = y;
this ->z = z;
}
Vector operator+(Vector v); // ADD 2 Vectors
Vector operator-(Vector v); // Subtraction
int operator^(Vector v); // Dot Product
Vector operator*(Vector v); // Cross Product
float magnitude()
{
return sqrt ( pow (x, 2) + pow (y, 2) + pow (z, 2));
}
friend ostream& operator<<(ostream& out, const Vector& v);
// To output the Vector
}; // ADD 2 Vectors Vector Vector::operator+(Vector v) { int x1, y1, z1;
x1 = x + v.x;
y1 = y + v.y;
z1 = z + v.z;
return Vector(x1, y1, z1);
} // Subtract 2 vectors Vector Vector::operator-(Vector v) { int x1, y1, z1;
x1 = x - v.x;
y1 = y - v.y;
z1 = z - v.z;
return Vector(x1, y1, z1);
} // Dot product of 2 vectors int Vector::operator^(Vector v)
{ int x1, y1, z1;
x1 = x * v.x;
y1 = y * v.y;
z1 = z * v.z;
return (x1 + y1 + z1);
} // Cross product of 2 vectors Vector Vector::operator*(Vector v) { int x1, y1, z1;
x1 = y * v.z - z * v.y;
y1 = z * v.x - x * v.z;
z1 = x * v.y - y * v.x;
return Vector(x1, y1, z1);
} // Display Vector ostream& operator<<(ostream& out, const Vector& v)
{ out << v.x << "i " ;
if (v.y >= 0)
out << "+ " ;
out << v.y << "j " ;
if (v.z >= 0)
out << "+ " ;
out << v.z << "k" << endl;
return out;
} // calculate shortest dist. from point to line float shortDistance(Vector line_point1, Vector line_point2,
Vector point)
{ Vector AB = line_point2 - line_point1;
Vector AC = point - line_point1;
float area = Vector(AB * AC).magnitude();
float CD = area / AB.magnitude();
return CD;
} // Driver program int main()
{ // Taking point C as (2, 2, 2)
// Line Passes through A(4, 2, 1)
// and B(8, 4, 2).
Vector line_point1(4, 2, 1), line_point2(8, 4, 2);
Vector point(2, 2, 2);
cout << "Shortest Distance is : "
<< shortDistance(line_point1, line_point2, point);
return 0;
} |
// Java program to find the Shortest // Distance Between A line and a // Given point. public class Vector {
private int x, y, z;
// 3D Coordinates of the Vector
public Vector( int x, int y, int z)
{
// Constructor
this .x = x;
this .y = y;
this .z = z;
}
// ADD 2 Vectors
public Vector add(Vector v)
{
int x1, y1, z1;
x1 = x + v.x;
y1 = y + v.y;
z1 = z + v.z;
return new Vector(x1, y1, z1);
}
// Subtract 2 vectors
public Vector subtract(Vector v)
{
int x1, y1, z1;
x1 = x - v.x;
y1 = y - v.y;
z1 = z - v.z;
return new Vector(x1, y1, z1);
}
// Dot product of 2 vectors
public int dotProduct(Vector v)
{
int x1, y1, z1;
x1 = x * v.x;
y1 = y * v.y;
z1 = z * v.z;
return (x1 + y1 + z1);
}
// Cross product of 2 vectors
public Vector crossProduct(Vector v)
{
int x1, y1, z1;
x1 = y * v.z - z * v.y;
y1 = z * v.x - x * v.z;
z1 = x * v.y - y * v.x;
return new Vector(x1, y1, z1);
}
public float magnitude()
{
return ( float )Math.sqrt(Math.pow(x, 2 )
+ Math.pow(y, 2 )
+ Math.pow(z, 2 ));
}
public String toString()
{
return x + "i " + (y >= 0 ? "+ " : "" ) + y + "j "
+ (z >= 0 ? "+ " : "" ) + z + "k" ;
}
// calculate shortest dist. from point to line
public static float shortDistance(Vector line_point1,
Vector line_point2,
Vector point)
{
Vector AB = line_point2.subtract(line_point1);
Vector AC = point.subtract(line_point1);
float area = (AB.crossProduct(AC)).magnitude();
float CD = area / AB.magnitude();
return CD;
}
// Driver Code
public static void main(String[] args)
{
// Taking point C as (2, 2, 2)
// Line Passes through A(4, 2, 1)
// and B(8, 4, 2).
Vector line_point1 = new Vector( 4 , 2 , 1 );
Vector line_point2 = new Vector( 8 , 4 , 2 );
Vector point = new Vector( 2 , 2 , 2 );
System.out.println( "Shortest Distance is : "
+ shortDistance(line_point1,
line_point2,
point));
}
} |
import math
class Vector:
def __init__( self , x, y, z):
# Constructor
self .x = x
self .y = y
self .z = z
# ADD 2 Vectors
def __add__( self , v):
x1, y1, z1 = self .x + v.x, self .y + v.y, self .z + v.z
return Vector(x1, y1, z1)
# Subtract 2 vectors
def __sub__( self , v):
x1, y1, z1 = self .x - v.x, self .y - v.y, self .z - v.z
return Vector(x1, y1, z1)
# Dot product of 2 vectors
def __xor__( self , v):
x1, y1, z1 = self .x * v.x, self .y * v.y, self .z * v.z
return x1 + y1 + z1
# Cross product of 2 vectors
def __mul__( self , v):
x1 = self .y * v.z - self .z * v.y
y1 = self .z * v.x - self .x * v.z
z1 = self .x * v.y - self .y * v.x
return Vector(x1, y1, z1)
# Display Vector
def __str__( self ):
out = self .x + "i "
if self .y > = 0 :
out + = "+ "
out + = self .y + "j "
if self .z > = 0 :
out + = "+ "
out + = self .z + "k\n"
return out
def magnitude( self ):
return math.sqrt( self .x * * 2 + self .y * * 2 + self .z * * 2 )
# calculate shortest dist. from point to line def shortDistance(line_point1, line_point2, point):
AB = line_point2 - line_point1
AC = point - line_point1
area = (AB * AC).magnitude()
CD = area / AB.magnitude()
return CD
# Driver program if __name__ = = "__main__" :
# Taking point C as (2, 2, 2)
# Line Passes through A(4, 2, 1)
# and B(8, 4, 2).
line_point1 = Vector( 4 , 2 , 1 )
line_point2 = Vector( 8 , 4 , 2 )
point = Vector( 2 , 2 , 2 )
print ( "Shortest Distance is:" , shortDistance(line_point1, line_point2, point))
|
// C# program to find the Shortest // Distance Between A line and a // Given point. using System;
using System.Collections.Generic;
class Vector {
public int x, y, z;
// 3D Coordinates of the Vector
public Vector( int x1, int y1, int z1)
{
// Constructor
x = x1;
y = y1;
z = z1;
}
public double magnitude()
{
return Math.Sqrt(Math.Pow(x, 2) + Math.Pow(y, 2)
+ Math.Pow(z, 2));
}
// To output the Vector
// ADD 2 Vectors
public static Vector operator + (Vector v1, Vector v)
{
int x1, y1, z1;
x1 = v1.x + v.x;
y1 = v1.y + v.y;
z1 = v1.z + v.z;
return new Vector(x1, y1, z1);
}
// Subtract 2 vectors
public static Vector operator - (Vector v1, Vector v)
{
int x1, y1, z1;
x1 = v1.x - v.x;
y1 = v1.y - v.y;
z1 = v1.z - v.z;
return new Vector(x1, y1, z1);
}
// Cross product of 2 vectors
public static Vector operator *(Vector v, Vector v1)
{
int x1, y1, z1;
x1 = v1.y * v.z - v1.z * v.y;
y1 = v1.z * v.x - v1.x * v.z;
z1 = v1.x * v.y - v1.y * v.x;
return new Vector(x1, y1, z1);
}
} class GFG {
// calculate shortest dist. from point to line
static double shortDistance(Vector line_point1,
Vector line_point2,
Vector point)
{
Vector AB = line_point2 - line_point1;
Vector AC = point - line_point1;
double area = (AB * AC).magnitude();
double CD = area / AB.magnitude();
return CD;
}
// Driver program
public static void Main( string [] args)
{
// Taking point C as (2, 2, 2)
// Line Passes through A(4, 2, 1)
// and B(8, 4, 2).
Vector line_point1 = new Vector(4, 2, 1);
Vector line_point2 = new Vector(8, 4, 2);
Vector point = new Vector(2, 2, 2);
Console.WriteLine( "Shortest Distance is : "
+ shortDistance(line_point1,
line_point2,
point));
}
} // This code is contributed by phasing17 |
class Vector { constructor(x, y, z) {
// Constructor
this .x = x;
this .y = y;
this .z = z;
}
// ADD 2 Vectors
add(v) {
let x1 = this .x + v.x;
let y1 = this .y + v.y;
let z1 = this .z + v.z;
return new Vector(x1, y1, z1);
}
// Subtract 2 vectors
sub(v) {
let x1 = this .x - v.x;
let y1 = this .y - v.y;
let z1 = this .z - v.z;
return new Vector(x1, y1, z1);
}
// Dot product of 2 vectors
dot(v) {
let x1 = this .x * v.x;
let y1 = this .y * v.y;
let z1 = this .z * v.z;
return x1 + y1 + z1;
}
// Cross product of 2 vectors
cross(v) {
let x1 = this .y * v.z - this .z * v.y;
let y1 = this .z * v.x - this .x * v.z;
let z1 = this .x * v.y - this .y * v.x;
return new Vector(x1, y1, z1);
}
// Display Vector
toString() {
let out = this .x + "i " ;
if ( this .y >= 0) {
out += "+ " ;
}
out += this .y + "j " ;
if ( this .z >= 0) {
out += "+ " ;
}
out += this .z + "k\n" ;
return out;
}
magnitude() {
return Math.sqrt( this .x ** 2 + this .y ** 2 + this .z ** 2);
}
} // calculate shortest dist. from point to line function shortDistance(line_point1, line_point2, point) {
let AB = line_point2.sub(line_point1);
let AC = point.sub(line_point1);
let area = AB.cross(AC).magnitude();
let CD = area / AB.magnitude();
return CD;
} // Driver program let line_point1 = new Vector(4, 2, 1);
let line_point2 = new Vector(8, 4, 2);
let point = new Vector(2, 2, 2);
console.log( "Shortest Distance is:" , shortDistance(line_point1, line_point2, point));
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Shortest Distance is : 1.63299
Time Complexity: O(log N), for using the inbuilt sqrt() function.
Auxiliary Space: O(1), as constant space is required.