# Set, Clear and Toggle a given bit of a number in C

Given a number N, the task is to set, clear and toggle the K-th bit of this number N.

• Setting a bit means that if K-th bit is 0, then set it to 1 and if it is 1 then leave it unchanged.
• Clearing a bit means that if K-th bit is 1, then clear it to 0 and if it is 0 then leave it unchanged.
• Toggling a bit means that if K-th bit is 1, then change it to 0 and if it is 0 then change it to 1.

Examples:

```Input: N = 5, K = 1
Output:
Setting Kth bit: 5
Clearing Kth bit: 4
Toggling Kth bit: 4
Explanation:
5 is represented as 101 in binary
and has its first bit 1, so
setting it will result in 101 i.e. 5.
clearing it will result in 100 i.e. 4.
toggling it will result in 100 i.e. 4.

Input: N = 7, K = 2
Output:
Setting Kth bit: 7
Clearing Kth bit: 5
Toggling Kth bit: 5
Explanation:
7 is represented as 111 in binary
and has its second bit 1, so
setting it will result in 111 i.e. 7.
clearing it will result in 101 i.e. 5.
toggling it will result in 101 i.e. 5.
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

Below are the steps to set, clear and toggle Kth bit of N:

Setting a bit

• Since we all know that performing bitwise OR of any bit with a set bit results in a set bit, i.e.
```Any bit <bitwise OR> Set bit = Set bit

which means,
0 | 1 = 1
1 | 1 = 1
```
• So for setting a bit, performing a bitwise OR of the number with a set bit is the best idea.
```N = N | 1 << K
OR
N |= 1 << K

where K is the bit that is to be set
```

Clearing a bit

• Since bitwise AND of any bit with a reset bit results in a reset bit, i.e.
```Any bit <bitwise AND> Reset bit = Reset bit

which means,
0 & 0 = 0
1 & 0 = 0
```
• So for clearing a bit, performing a bitwise AND of the number with a reset bit is the best idea.
```n = n & ~(1 << k)
OR
n &= ~(1 << k)

where k is the bit that is to be cleared
```

Toggle a bit

• Since XOR of unset and set bit results in a set bit and XOR of a set and set bit results in an unset bit. Hence performing bitwise XOR of any bit with a set bit results in toggle of that bit, i.e.
```Any bit <bitwise XOR> Set bit = Toggle

which means,
0 ^ 1 = 1
1 ^ 1 = 0
```
• So in order to toggle a bit, performing a bitwise XOR of the number with a reset bit is the best idea.
```n = n ^ 1 << k
OR
n ^= 1 << k

where k is the bit that is to be cleared
```

Below is the implementation of the above approach:

 `// C program to set, clear and toggle a bit ` ` `  `#include ` ` `  `// Function to set the kth bit of n ` `int` `setBit(``int` `n, ``int` `k) ` `{ ` `    ``return` `(n | (1 << (k - 1))); ` `} ` ` `  `// Function to clear the kth bit of n ` `int` `clearBit(``int` `n, ``int` `k) ` `{ ` `    ``return` `(n & (~(1 << (k - 1)))); ` `} ` ` `  `// Function to toggle the kth bit of n ` `int` `toggleBit(``int` `n, ``int` `k) ` `{ ` `    ``return` `(n ^ (1 << (k - 1))); ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `n = 5, k = 1; ` ` `  `    ``printf``(``"%d with %d-th bit Set: %d\n"``, ` `           ``n, k, setBit(n, k)); ` `    ``printf``(``"%d with %d-th bit Cleared: %d\n"``, ` `           ``n, k, clearBit(n, k)); ` `    ``printf``(``"%d with %d-th bit Toggled: %d\n"``, ` `           ``n, k, toggleBit(n, k)); ` `    ``return` `0; ` `} `

Output:

```5 with 1-th bit Set: 5
5 with 1-th bit Cleared: 4
5 with 1-th bit Toggled: 4
```

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