Given a non-negative number n and two values l and r. The problem is to set the bits in the range l to r in the binary representation of n, i.e, to unset bits from the rightmost lth bit to the rightmost r-th bit.
Constraint: 1 <= l <= r <= number of bits in the binary representation of n.
Examples :
Input : n = 17, l = 2, r = 3 Output : 23 (17)10 = (10001)2 (23)10 = (10111)2 The bits in the range 2 to 3 in the binary representation of 17 are set. Input : n = 50, l = 2, r = 5 Output : 62
Approach: Following are the steps:
1. Find a number 'range' that has all set bits in given range. And all other bits of this number are 0. range = (((1 << (l - 1)) - 1) ^ ((1 << (r)) - 1)); 2. Now, perform "n = n | range". This will set the bits in the range from l to r in n.
C++
// C++ implementation to Set bits in // the given range #include <iostream> using namespace std; // function to toggle bits in the given range int setallbitgivenrange( int n, int l, int r) { // calculating a number 'range' having set // bits in the range from l to r and all other // bits as 0 (or unset). int range = (((1 << (l - 1)) - 1) ^ ((1 << (r)) - 1)); return (n | range); } // Driver code int main() { int n = 17, l = 2, r = 3; cout << setallbitgivenrange(n, l, r); return 0; } |
Java
// java implementation to Set bits in // the given range import java.util.*; class GFG { // function to toggle bits in the // given range static int setallbitgivenrange( int n, int l, int r) { // calculating a number 'range' // having set bits in the range // from l to r and all other // bits as 0 (or unset). int range = ((( 1 << (l - 1 )) - 1 ) ^ (( 1 << (r)) - 1 )); return (n | range); } // Driver code public static void main(String[] args) { int n = 17 , l = 2 , r = 3 ; System.out.println(setallbitgivenrange( n, l, r)); } } // This code is contributed by Sam007. |
Python3
# Python3 implementation to Set # bits in the given range # Function to toggle bits # in the given range def setallbitgivenrange(n, l, r): # calculating a number 'range' # having set bits in the range # from l to r and all other # bits as 0 (or unset). range = ((( 1 << (l - 1 )) - 1 ) ^ (( 1 << (r)) - 1 )) return (n | range ) # Driver code n, l, r = 17 , 2 , 3 print (setallbitgivenrange(n, l, r)) # This code is contributed by Anant Agarwal. |
C#
// C# implementation to Set // bits in the given range using System; class GFG { // function to toggle bits // in the given range static int setallbitgivenrange( int n, int l, int r) { // calculating a number 'range' // having set bits in the range // from l to r and all other // bits as 0 (or unset). int range = (((1 << (l - 1)) - 1) ^ ((1 << (r)) - 1)); return (n | range); } // Driver code static void Main() { int n = 17, l = 2, r = 3; Console.Write(setallbitgivenrange(n, l, r)); } } // This code is contributed by Sam007 |
PHP
<?php // PHP implementation to Set // bits in the given range // function to toggle bits // in the given range function setallbitgivenrange( $n , $l , $r ) { // calculating a number 'range' // having set bits in the range // from l to r and all other // bits as 0 (or unset). $range = (((1 << ( $l - 1)) - 1) ^ ((1 << ( $r )) - 1)); return ( $n | $range ); } // Driver code $n = 17; $l = 2; $r = 3; echo setallbitgivenrange( $n , $l , $r ); // This code is contributed by Sam007 ?> |
Output :
23
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