Given a non-negative number n and two values l and r. The problem is to set the bits in the range l to r in the binary representation of n, i.e, to unset bits from the rightmost lth bit to the rightmost r-th bit.
Constraint: 1 <= l <= r <= number of bits in the binary representation of n.
Examples :
Input : n = 17, l = 2, r = 3 Output : 23 (17)10 = (10001)2 (23)10 = (10111)2 The bits in the range 2 to 3 in the binary representation of 17 are set. Input : n = 50, l = 2, r = 5 Output : 62
Approach: Following are the steps:
1. Find a number 'range' that has all set
bits in given range. And all other bits
of this number are 0.
range = (((1 << (l - 1)) - 1) ^
((1 << (r)) - 1));
2. Now, perform "n = n | range". This will
set the bits in the range from l to r
in n.
C++
// C++ implementation to Set bits in // the given range #include <iostream> using namespace std; // function to toggle bits in the given range int setallbitgivenrange(int n, int l, int r) { // calculating a number 'range' having set // bits in the range from l to r and all other // bits as 0 (or unset). int range = (((1 << (l - 1)) - 1) ^ ((1 << (r)) - 1)); return (n | range); } // Driver code int main() { int n = 17, l = 2, r = 3; cout << setallbitgivenrange(n, l, r); return 0; } |
Java
// java implementation to Set bits in // the given range import java.util.*; class GFG { // function to toggle bits in the // given range static int setallbitgivenrange(int n, int l, int r) { // calculating a number 'range' // having set bits in the range // from l to r and all other // bits as 0 (or unset). int range = (((1 << (l - 1)) - 1) ^ ((1 << (r)) - 1)); return (n | range); } // Driver code public static void main(String[] args) { int n = 17, l = 2, r = 3; System.out.println(setallbitgivenrange( n, l, r)); } } // This code is contributed by Sam007. |
Python3
# Python3 implementation to Set # bits in the given range # Function to toggle bits # in the given range def setallbitgivenrange(n, l, r): # calculating a number 'range' # having set bits in the range # from l to r and all other # bits as 0 (or unset). range = (((1 << (l - 1)) - 1) ^ ((1 << (r)) - 1)) return (n | range) # Driver code n, l, r = 17, 2, 3print(setallbitgivenrange(n, l, r)) # This code is contributed by Anant Agarwal. |
C#
// C# implementation to Set // bits in the given range using System; class GFG { // function to toggle bits // in the given range static int setallbitgivenrange(int n, int l, int r) { // calculating a number 'range' // having set bits in the range // from l to r and all other // bits as 0 (or unset). int range = (((1 << (l - 1)) - 1) ^ ((1 << (r)) - 1)); return (n | range); } // Driver code static void Main() { int n = 17, l = 2, r = 3; Console.Write(setallbitgivenrange(n, l, r)); } } // This code is contributed by Sam007 |
PHP
<?php // PHP implementation to Set // bits in the given range // function to toggle bits // in the given range function setallbitgivenrange($n, $l, $r) { // calculating a number 'range' // having set bits in the range // from l to r and all other // bits as 0 (or unset). $range = (((1 << ($l - 1)) - 1) ^ ((1 << ($r)) - 1)); return ($n | $range); } // Driver code $n = 17; $l = 2; $r = 3; echo setallbitgivenrange($n, $l, $r); // This code is contributed by Sam007 ?> |
Output :
23
This article is contributed by Devanshu Agarwal. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.
