Servlet – Page Redirection
Last Updated :
04 Jan, 2023
Programming for a website is an art. To provide the view in an eminent manner, numerous steps are getting taken. Usually, a client(A simple JSP page) provides a request to a web server or app server and they process the request and provide the response. Sometimes, it happens that in order to load balance the server, a few pages might be moved to other places, or according to the authorized authenticated credentials, the response should get diverted. In this article, let us see how to handle those scenarios. i.e. Using page redirection can be achieved via servlets.
sendRedirect(): It redirects the response to another resource that is present inside the server or even outside. Hence it makes the client(browser) create a new request and hence we can see the new URL in the browser. sendRedirect() can accept a relative URL and hence only redirection can happen inside or outside the server.
Proper syntax to do page redirection is
public void sendRedirect(String URL)throws IOException;
Let us see an example of how to do that. Here let us do a user is searching a key term and on click of the button, it will get redirected to the GeeksforGeeks page.
Example
JSP Code: index.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Learn Courses Online</title>
</head>
<body>
<h1>Example to show page redirection!</h1>
<form action="searchServlet" method="post"><!-- It is calling searchServlet on click of button -->
Enter your search term: <input type="text" name="yourSearchTerm" size="20">
<input type="submit" value="Invoke Search" />
</form>
</body>
</html>
Java code: (Servlet code) -> SearchServlet.java
Java
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/searchServlet")
public class SearchServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public SearchServlet() {
super();
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");
response.setStatus(response.SC_ACCEPTED);
response.setHeader("Location", site);
response.sendRedirect(site);
return;
}
}
|
The above set of lines should be present in a dynamic web project pattern and once it is created in eclipse, by default it will come with the web.xml file
XML
<?xml version="1.0" encoding="UTF-8"?>
<display-name>sampleProject1</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
</web-app>
|
Once the index.jsp page is run on the server (Usually Apache Tomcat) will be used, we can see the following output. A short video will explain how it is getting done
By using request.getRequestDispathcer(“<a specific page present in the same webserver>”).forward(request, response) we can do page redirect. But the specified page should be available in the webserver that is getting used. Otherwise, it cannot forward/redirect. As a thumb rule, if the requirement is redirecting to pages which is present outside the server, then go for the response.sendRedirect. The name itself specifies that it is always a new request and can be used within or outside of the server. The main thing is it works on the client-side. Regarding HttpResponse.setStatus, we have different status set
Status code explanation
Let us see how the page redirection works out with “getRequestDispatcher().forward”. Servlet code alone will have a change and also since the forwarded page should be available in the same web server, it is also shown here.
Java
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/searchServlet")
public class SearchServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public SearchServlet() {
super();
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
request.getRequestDispatcher("searchpage.jsp").forward(request, response);
return;
}
}
|
searchpage.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Learn Courses Online</title>
</head>
<body>
<h1>Example to show page redirection via forward!</h1>
<a href = "https://www.geeksforgeeks.org/learn-java-on-your-own-in-20-days-free/">Learn Java</a>
</body>
</html>
Output is explained in the attached video
Conclusion
Hence by using response.sendRedirection(“<a valid URL>”) which can be either present in the same webserver/outside and request.getRequestDispatcher(“<a valid page present in the same webserver>”).forward(request, response) we can do page redirection. Due to several reasons, it can be done. The ultimate concept is the end-user is provided with a proper response page.
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