Second most repeated word in a sequence in Python

Given a sequence of strings, the task is to find out the second most repeated (or frequent) string in the given sequence. (Considering no two words are the second most repeated, there will be always a single word).

Examples:

Input : {"aaa", "bbb", "ccc", "bbb", 
         "aaa", "aaa"}
Output : bbb

Input : {"geeks", "for", "geeks", "for", 
          "geeks", "aaa"}
Output : for

This problem has existing solution please refer Second most repeated word in a sequence link. We can solve this problem quickly in Python using Counter(iterator) method.

Approach is very simple –



  1. Create a dictionary using Counter(iterator) method which contains words as keys and it’s frequency as value.
  2. Now get a list of all values in dictionary and sort it in descending order. Choose second element from the sorted list because it will be the second largest.
  3. Now traverse dictionary again and print key whose value is equal to second largest element.
filter_none

edit
close

play_arrow

link
brightness_4
code

# Python code to print Second most repeated 
# word in a sequence in Python 
from collections import Counter 
    
def secondFrequent(input): 
    
    # Convert given list into dictionary 
    # it's output will be like {'ccc':1,'aaa':3,'bbb':2} 
    dict = Counter(input
    
    # Get the list of all values and sort it in ascending order 
    value = sorted(dict.values(), reverse=True
    
    # Pick second largest element 
    secondLarge = value[1
    
    # Traverse dictionary and print key whose 
    # value is equal to second large element 
    for (key, val) in dict.items(): 
        if val == secondLarge: 
            print (key) 
            return
    
# Driver program 
if __name__ == "__main__"
    input = ['aaa','bbb','ccc','bbb','aaa','aaa'
    secondFrequent(input)
chevron_right

Output:

bbb


Alternate Implementation :

filter_none

edit
close

play_arrow

link
brightness_4
code

# Second most repeated word in a sequence in Python
  
def secondFrequent(input):
    from collections import Counter
  
    # this sorts from most common to least common to least common
    c = Counter(input
       
    # c.most_common()[1] prints ('bbb',2) 
    # c.most_common()[1][0] prints output: bbb
    print(c.most_common()[1][0])
  
# Driver code
input = ['aaa','bbb','ccc','bbb','aaa','aaa']
secondFrequent(input)
chevron_right

Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course.





Experienced Software Engineer with a demonstrated history of working in the information technology and services industry Skilled in Big Data technologies, Data Structures, Algorithm, Software Development, App Development, Databases, Python, Java, C, and WordPress

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.



Improved By : Midhilesh

Article Tags :
Practice Tags :