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# Second largest value in a Python Dictionary

In this problem, we will find the second-largest value in the given dictionary.

Examples:

```Input :  {'one':5, 'two':1, 'three':6, 'four':10}
Output :  Second largest value of the dictionary is 6

Input :   {1: 'Geeks', 'name': 'For', 3: 'Geeks'}
Output :  Second largest value of the dictionary is Geeks```

## Python3

 `dictionary ``=` `{``1``: ``'Geeks'``, ``'name'``: ``'For'``, ``3``: ``'Geeks'``}``val ``=` `list``(dictionary.values())``val.sort()``res ``=` `val[``-``2``]``print``(res)`

Output:

`Geeks`

Time Complexity : O(n Log n)
Auxiliary Space: O(n)

#### Approach #2 : Using Reverse sort function

1. Define a dictionary with key-value pairs.
2. Convert dictionary values to list.
3. Use built-in reverse sort() function on list of dictionary values.
4. After reverse sorting of dictionary, print the index 1 of dictionary which is second largest value in dictionary.

## Python3

 `# Python3 code using reverse sort method``# code for finding second largest value in dictionary` `dictionary ``=` `{``1``: ``'Geeks'``, ``'name'``: ``'For'``, ``3``: ``'Geeks'``}` `val ``=` `list``(dictionary.values())` `# using reverse sort() method``val.sort(reverse ``=` `True``)` `res ``=` `val[``1``]` `print``(res)` `# This code is contributed by Pratik Gupta (guptapratik)`

Output

`Geeks`

Time Complexity : O(n * Log n), where n is the size of the dictionary
Auxiliary Space: O(n)

Please refer below post for more methods : Python program to find second maximum value in Dictionary

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