Given an N-ary tree, find and return the node with second largest value in the given tree. Return NULL if no node with required value is present.
For example, in the given tree
Second largest node is 20.
A simple solution is to traverse the array twice. In the first traversal find the maximum value node. In the second traversal find the greatest element node less than the element obtained in first traversal. The time complexity of this solution is O(n).
An Efficient Solution can be to find the second largest element in a single traversal.
Below is the complete algorithm for doing this:
1) Initialize two nodes first and second to NULL as, first = second = NULL 2) Start traversing the tree, a) If the current node data say root->key is greater than first->key then update first and second as, second = first first = root b) If the current node data is in between first and second, then update second to store the value of current node as second = root 3) Return the node stored in second.
Second largest element is : 6
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