Secant Formula
Last Updated :
11 Jan, 2024
Trigonometry is a very important branch of mathematics which has a wide variety of applications. One such application pertains to the ratio of sides and angle measurements of triangles, particularly right-angled triangles.Â
In the figure below, we are given a right triangle ABC. Here, AC being the longest side, is the hypotenuse and AB is the perpendicular to the base BC.Â
Â
The different combinations of the ratios of these three sides of a given triangle yield the formulas for sin, cos, tan, cosec, sec and cot. Here we are going to discuss the secant formula.
Secant Formula
sec θ = Hypotenuse/Base
or,Â
sec θ = 1/cos θ
since cos θ = Base/Hypotenuse
Using the secant formula in the above figure, sec A would be AC/BC.
Sample Problems
Problem 1. The value of cosine in a right triangle is 1/2. Find the value of the secant.
Solution:
The secant formula states that sec θ = 1/cos θ.
Since cos θ = 1/2
⇒ sec θ = 1/(1/2)
⇒ sec θ = 2
Problem 2. The hypotenuse and base of a right triangle are given to be 17 and 15 respectively. Find the value of the secant.
Solution:
sec θ = Hypotenuse/Base
Here, H = 17 and B = 15
⇒ sec θ = 17/15
Problem 3. Find the secant of a right triangle if its hypotenuse is 17 and perpendicular to the base is 8.
Solution:
Here, H = 17 and P = 8
As per Pythagoras Theorem, H2 = P2 + B2
B2 = 172 – 82
B = 15
Now, since sec θ = Hypotenuse/Base
⇒ sec θ = 17/15
Problem 4. The value of cosine in a right triangle is 0.1. Find the value of the secant.
Solution:
The secant formula states that sec θ = 1/cos θ.
Since cos θ = 0.1 = 1/10
⇒ sec θ = 1/(1/10)
⇒ sec θ = 10
Problem 5. The value of cosine in a right triangle is 0.2. Find the value of the secant.
Solution:
The secant formula states that sec θ = 1/cos θ.
Since cos θ = 0.2 = 1/5
⇒ sec θ = 1/(1/5)
⇒ sec θ = 5
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