Related Articles

# Search a string in Matrix Using Split function in Java

• Difficulty Level : Easy
• Last Updated : 21 Nov, 2018

Given a string str and a matrix mat[][] of lowercase English alphabets, the task is to find whether the string str appears in the matrix (either row-wise or column-wise).

Examples:

Input: str = "GFG"
mat[][] = {{'G', 'E', 'E', 'K', 'S'},
{'F', 'O', 'R', 'A', 'N'},
{'G', 'E', 'E', 'K', 'S'}}
Output: Yes
GFG is present in the first column.

Input: str = "SSS"
mat[][] = {{'G', 'E', 'E', 'K', 'S'},
{'F', 'O', 'R', 'A', 'N'},
{'G', 'E', 'E', 'K', 'S'}}
Output: No

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:
If the search string is present in any row of the matrix the following results will be produced by the split function:

1. If the string occupies the whole row then the split function will return an array of length zero.
2. If the string is present in between characters then the array length will be greater than one.
3. If the array length is one then three possible cases can be there-
• The string occurs in first half.
• The string occurs in second half.
• The string is not present in that row.
4. To search the string column wise transpose the matrix and repeat step one.
5. Print Yes if the string is found else print No.

Below is the implementation of the above approach:

 // Java program to search a string in// the matrix using split functionimport java.util.*;public class GFG {      // Function to check the occurrence of string in the matrix    public static int check(String[] matrix, String string)    {        // Looping the contents in the matrix        for (String input : matrix) {              // using split operator            String[] value = input.split(string);              if (value.length >= 2 || value.length == 0) {                return 1;            }            else if (value.length == 1                     && input.length() != value[0].length()) {                return 1;            }        }        return 0;    }      // Function to transpose the given matrix    public static String[] vertical(String[] matrix)    {        String[] vertical_value = new String[matrix[0].length()];        for (int i = 0; i < matrix[0].length(); i++) {            String temp = "";            for (int j = 0; j < matrix.length; j++)                temp += matrix[j].charAt(i);            vertical_value[i] = temp;        }          // returning the transposed matrix        return vertical_value;    }      // Driver code    public static void main(String[] args)    {          // Input matrix of characters        String[] matrix = { "GEEKS", "FORAN", "GEEKS" };          // element to be searched        String search = "GFG";          // Transpose of the matrix        String[] verticalMatrix = vertical(matrix);          // Searching process        int horizontal_search = check(matrix, search);        int vertical_search = check(verticalMatrix, search);          // If found        if (horizontal_search == 1 || vertical_search == 1)            System.out.println("Yes");        else            System.out.println("No");    }}
Output:
Yes

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.

My Personal Notes arrow_drop_up