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# sciPy stats.trim1() function | Python

• Last Updated : 20 Feb, 2019

scipy.stats.trim1(a, proportiontocut, tail=’right’) function slices off the portion of elements in the array from one end of the passed array distribution.

Parameters :
arr : [array_like] Input array or object to trim.
tail : [optional] {‘left’, ‘right’} Defaults to right.
proportiontocut : Proportion (in range 0-1) of data to trim of each end.

Results : trimmed array elements from both the ends in the given proportion.

Code #1: Working

 `# stats.trim1() method ``import` `numpy as np``from` `scipy ``import` `stats``  ` `arr1 ``=` `[``0``, ``1``, ``2``, ``3``, ``4``, ``5``, ``6``, ``7``, ``8``, ``9``]`` ` `print` `(``"\narr1 : "``, arr1)`` ` `print` `(``"\nclipped arr1 : \n"``, ``       ``stats.trim1(arr1, proportiontocut ``=` `.``3``, tail ``=` `'right'``))`` ` `print` `(``"\nclipped arr1 : \n"``, ``       ``stats.trim1(arr1, proportiontocut ``=` `.``3``, tail ``=` `'left'``))`` ` `print` `(``"\nclipped arr1 : \n"``, ``       ``stats.trim1(arr1, proportiontocut ``=` `.``1``, tail ``=` `'left'``))`` ` `print` `(``"\nclipped arr1 : \n"``, ``       ``stats.trim1(arr1, proportiontocut ``=` `.``1``, tail ``=` `'right'``))`

Output :

```arr1 :  [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

clipped arr1 :
[0 2 1 3 4 5 6]

clipped arr1 :
[3 4 6 5 7 8 9]

clipped arr1 :
[1 3 2 4 5 6 7 8 9]

clipped arr1 :
[0 2 1 3 4 5 6 7 8]
```

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