Scala Iterator forall() method with example

The forall() method belongs to the concrete value members of the Class AbstractIterator. It is defined in the class IterableOnceOps. It tests whether a used predicate holds for all the elements of the stated collection. It may not terminate for the infinite sized collection.

Method Definition : def forall(p: (A) => Boolean): Boolean

Return Type : It returns true if the stated collection is empty or if the given predicate p holds for all elements of this collection, else it returns false.



Example #1:

filter_none

edit
close

play_arrow

link
brightness_4
code

// Scala program of forall()
// method
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating an Iterator 
        val iter = Iterator(3, 6, 15, 12, 21)
          
        // Applying forall method
        val result= iter.forall(x => {x % 3 == 0})
          
        // Displays output
        println(result)
      
    }
}

chevron_right


Output:

true

Example #2:

filter_none

edit
close

play_arrow

link
brightness_4
code

// Scala program of forall()
// method
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating an Iterator 
        val iter = Iterator(3, 6, 15, 19, 21)
          
        // Applying forall method
        val result= iter.forall(x => {x % 3 == 0})
          
        // Displays output
        println(result)
      
    }
}

chevron_right


Output:

false


My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.




Article Tags :

Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.