# Round the given number to nearest multiple of 10

Given a positive integer n, round it to nearest whole number having zero as last digit.

Examples:

```Input : 4722
Output : 4720

Input : 38
Output : 40

Input : 10
Output: 10
```

## Recommended: Please solve it on PRACTICE first, before moving on to the solution.

Approach:
Let’s round down the given number n to the nearest integer which ends with 0 and store this value in a variable a.
a = (n / 10) * 10. So, the round up n (call it b) is b = a + 10.

If n – a > b – n then the answer is b otherwise the answer is a.

Below is the implementation of the above approach:

## C++

 `// CPP program to round the given  ` `// integer to a whole number  ` `// which ends with zero. ` `#include ` `using` `namespace` `std; ` ` `  `// function to round the number ` `int` `round(``int` `n) ` `{ ` `    ``// Smaller multiple ` `    ``int` `a = (n / 10) * 10; ` `     `  `    ``// Larger multiple ` `    ``int` `b = a + 10; ` ` `  `    ``// Return of closest of two ` `    ``return` `(n - a > b - n)? b : a; ` `} ` ` `  `// driver function ` `int` `main() ` `{ ` `    ``int` `n = 4722; ` `    ``cout << round(n) << endl; ` `    ``return` `0; ` `} `

## Java

 `// JAVA Code for Round the given number ` `// to nearest multiple of 10 ` `import` `java.util.*; ` ` `  `class` `GFG { ` `     `  `    ``// function to round the number ` `    ``static` `int` `round(``int` `n) ` `    ``{ ` `        ``// Smaller multiple ` `        ``int` `a = (n / ``10``) * ``10``; ` `          `  `        ``// Larger multiple ` `        ``int` `b = a + ``10``; ` `      `  `        ``// Return of closest of two ` `        ``return` `(n - a > b - n)? b : a; ` `    ``} ` `     `  `    ``/* Driver program to test above function */` `    ``public` `static` `void` `main(String[] args)  ` `    ``{ ` `         ``int` `n = ``4722``; ` `         ``System.out.println(round(n)); ` `    ``} ` `} ` ` `  `// This code is contributed by Arnav Kr. Mandal. `

## Python3

 `# Python3 code to round the given  ` `# integer to a whole number  ` `# which ends with zero. ` ` `  `# function to round the number ` `def` `round``( n ): ` ` `  `    ``# Smaller multiple ` `    ``a ``=` `(n ``/``/` `10``) ``*` `10` `     `  `    ``# Larger multiple ` `    ``b ``=` `a ``+` `10` `     `  `    ``# Return of closest of two ` `    ``return` `(b ``if` `n ``-` `a > b ``-` `n ``else` `a) ` ` `  `# driver code ` `n ``=` `4722` `print``(``round``(n)) ` ` `  `# This code is contributed by "Sharad_Bhardwaj". `

## C#

 `// C# Code for Round the given number ` `// to nearest multiple of 10 ` `using` `System; ` ` `  `class` `GFG { ` `     `  `    ``// function to round the number ` `    ``static` `int` `round(``int` `n) ` `    ``{ ` `        ``// Smaller multiple ` `        ``int` `a = (n / 10) * 10; ` `         `  `        ``// Larger multiple ` `        ``int` `b = a + 10; ` `     `  `        ``// Return of closest of two ` `        ``return` `(n - a > b - n)? b : a; ` `    ``} ` `     `  `    ``// Driver program  ` `    ``public` `static` `void` `Main()  ` `    ``{ ` `        ``int` `n = 4722; ` `        ``Console.WriteLine(round(n)); ` `    ``} ` `} ` ` `  `// This code is contributed by Vt_m. `

## PHP

 ` ``\$b` `- ``\$n``) ? ``\$b` `: ``\$a``;  ` `}  ` ` `  `// Driver Code  ` `\$n` `= 4722;  ` `echo` `roundFunation(``\$n``), ``"\n"``;  ` `     `  `// This code is contributed by ajit ` `?> `

Output:

```4720
```

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Improved By : jit_t