# Reverse string in Python (6 different ways)

• Difficulty Level : Easy
• Last Updated : 23 Jun, 2022

Python string library does’nt support the in-built “reverse()” as done by other python containers like list, hence knowing other methods to reverse string can prove to be useful. This article discusses several ways to achieve it.

Using loop

## Python3

 `# Python code to reverse a string``# using loop` `def` `reverse(s):``str` `=` `""``for` `i ``in` `s:``    ``str` `=` `i ``+` `str``return` `str` `s ``=` `"Geeksforgeeks"` `print` `(``"The original string is : "``,end``=``"")``print` `(s)` `print` `(``"The reversed string(using loops) is : "``,end``=``"")``print` `(reverse(s))`

Output:

```The original string  is : Geeksforgeeks
The reversed string(using loops) is : skeegrofskeeG```

Explanation : In above code, we call a function to reverse a string, which iterates to every element and intelligently join each character in the beginning so as to obtain the reversed string.

Time complexity : O(n)
Auxiliary Space : O(1)

Using recursion

## Python3

 `# Python code to reverse a string``# using recursion` `def` `reverse(s):``    ``if` `len``(s) ``=``=` `0``:``        ``return` `s``    ``else``:``        ``return` `reverse(s[``1``:]) ``+` `s[``0``]` `s ``=` `"Geeksforgeeks"` `print` `(``"The original string is : "``,end``=``"")``print` `(s)` `print` `(``"The reversed string(using recursion) is : "``,end``=``"")``print` `(reverse(s))`

Output:

```The original string  is : Geeksforgeeks
The reversed string(using recursion) is : skeegrofskeeG```

Time complexity : O(n)
Auxiliary Space : O(n)
Explanation : In the above code, string is passed as an argument to a recursive function to reverse the string. In the function, the base condition is that if the length of the string is equal to 0, the string is returned. If not equal to 0, the reverse function is recursively called to slice the part of the string except the first character and concatenate the first character to the end of the sliced string.

Using stack

## Python3

 `# Python code to reverse a string``# using stack` `# Function to create an empty stack. It``# initializes size of stack as 0``def` `createStack():``    ``stack``=``[]``    ``return` `stack` `# Function to determine the size of the stack``def` `size(stack):``    ``return` `len``(stack)` `# Stack is empty if the size is 0``def` `isEmpty(stack):``    ``if` `size(stack) ``=``=` `0``:``        ``return` `true` `# Function to add an item to stack . It``# increases size by 1``def` `push(stack,item):``    ``stack.append(item)` `# Function to remove an item from stack.``# It decreases size by 1``def` `pop(stack):``    ``if` `isEmpty(stack): ``return``    ``return` `stack.pop()` `# A stack based function to reverse a string``def` `reverse(string):``    ``n ``=` `len``(string)``    ` `    ``# Create a empty stack``    ``stack ``=` `createStack()` `    ``# Push all characters of string to stack``    ``for` `i ``in` `range``(``0``,n,``1``):``        ``push(stack,string[i])` `    ``# Making the string empty since all``    ``# characters are saved in stack``    ``string``=``""` `    ``# Pop all characters of string and put``    ``# them back to string``    ``for` `i ``in` `range``(``0``,n,``1``):``        ``string``+``=``pop(stack)``        ` `    ``return` `string` `# Driver code``s ``=` `"Geeksforgeeks"``print` `(``"The original string is : "``,end``=``"")``print` `(s)``print` `(``"The reversed string(using stack) is : "``,end``=``"")``print` `(reverse(s))`

Output:

```The original string  is : Geeksforgeeks
The reversed string(using stack) is : skeegrofskeeG```

Time complexity : O(n)
Auxiliary Space : O(n)
Explanation : An empty stack is created. One by one characters of string are pushed to stack. One by one all characters from stack are popped, and put them back to string.

Using extended slice syntax

## Python3

 `# Python code to reverse a string``# using extended slice syntax` `# Function to reverse a string``def` `reverse(string):``    ``string ``=` `string[::``-``1``]``    ``return` `string` `s ``=` `"Geeksforgeeks"` `print` `(``"The original string is : "``,end``=``"")``print` `(s)` `print` `(``"The reversed string(using extended slice syntax) is : "``,end``=``"")``print` `(reverse(s))`

Output:

```The original string  is : Geeksforgeeks
The reversed string(using extended slice syntax) is : skeegrofskeeG```

Time complexity : O(n)
Auxiliary Space : O(1)
Explanation : Extended slice offers to put a “step” field as [start,stop,step], and giving no field as start and stop indicates default to 0 and string length respectively and “-1” denotes starting from end and stop at the start, hence reversing string.

Using reversed

## Python3

 `# Python code to reverse a string``# using reversed()` `# Function to reverse a string``def` `reverse(string):``    ``string ``=` `"".join(``reversed``(string))``    ``return` `string` `s ``=` `"Geeksforgeeks"` `print` `(``"The original string is : "``,end``=``"")``print` `(s)` `print` `(``"The reversed string(using reversed) is : "``,end``=``"")``print` `(reverse(s))`

Output:

```The original string  is : Geeksforgeeks
The reversed string(using reversed) is : skeegrofskeeG```

Time complexity : O(n)
Auxiliary Space : O(1)
Explanation : The reversed() returns the reversed iterator of the given string and then its elements are joined empty string separated using join(). And reversed order string is formed.

Using List-Comprehension

## Python3

 `# Python code to reverse a string``# using list comprehension()` `# Function to reverse a string``def` `reverse(string):``    ``string ``=` `[string[i] ``for` `i ``in` `range``(``len``(string)``-``1``, ``-``1``, ``-``1``)]``    ``return` `"".join(string)` `s ``=``"Geeksforgeeks"``;` `print` `(``"The original string  is : "``,s)` `print` `(``"The reversed string(using reversed) is : "``, reverse(s))`

Output

```The original string  is :  Geeksforgeeks
The reversed string(using reversed) is :  skeegrofskeeG```

Time complexity : O(n)
Auxiliary Space : O(1)

Or you can do that (easy-to-understand),

## Python3

 `# Python code to reverse a string``# using list comprehension()` `# Function to reverse a string``# by coverting string to list``# then reversed it and again convert it to string``def` `reverse(string):``    ``string ``=` `list``(string)``    ``string.reverse()``    ``return` `"".join(string)` `s ``=``"Geeksforgeeks"``;` `print` `(``"The original string  is : "``,s)` `print` `(``"The reversed string(using reversed) is : "``, reverse(s))` `#This code is contributed by Susobhan AKhuli`

Output

```The original string  is :  Geeksforgeeks
The reversed string(using reversed) is :  skeegrofskeeG```

Time complexity : O(n)
Auxiliary Space : O(1)

Explanation: List comprehension create the list of elements of string in reverse order and then its elements are join using join(). And reversed order string is formed.