Given a binary tree, the task is to print the reverse level order in spiral form.
Input: 1 / \ 2 3 / \ / \ 4 5 6 7 Output: 4 5 6 7 3 2 1 Input: 5 / \ 6 4 / \ / 7 1 8 \ \ 3 10 Output: 3 10 8 1 7 6 4 5
Approach: The idea is to traverse the tree in a Reverse Level Order manner but with a slight modification. We will use a variable flag and initially set it’s value to one. As we complete the reverse level order traversal of the tree, from left to right we will set the value of flag to zero, so that next time we traverse the Tree from right to left and as we complete the traversal we set it’s value back to one. We will repeat this whole step until we have traversed the Binary Tree completely.
Below is the implementation of the above approach:
8 7 4 6 9 3 5
- Level order traversal in spiral form
- Level order traversal in spiral form | Using one stack and one queue
- Reverse Level Order Traversal
- Connect Nodes at same Level (Level Order Traversal)
- Print a Binary Tree in Vertical Order | Set 3 (Using Level Order Traversal)
- Flatten Binary Tree in order of Level Order Traversal
- Reverse Clockwise spiral traversal of a binary tree
- Insertion in n-ary tree in given order and Level order traversal
- Reverse Anti Clockwise Spiral Traversal of a Binary Tree
- Construct BST from its given level order traversal
- Construct BST from its given level order traversal | Set-2
- Level Order Tree Traversal
- Density of Binary Tree using Level Order Traversal
- Level order traversal with direction change after every two levels
- Zig Zag Level order traversal of a tree using single queue
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