Reverse Level Order traversal in spiral form

Given a binary tree, the task is to print the reverse level order in spiral form.

Examples:

Input: 
     1
   /  \
  2    3
 / \  / \
4   5 6  7
Output: 4 5 6 7 3 2 1

Input:
     5
   /   \
  6     4
 / \   / 
7   1 8
 \     \
  3     10
Output: 3 10 8 1 7 6 4 5


Approach: The idea is to traverse the tree in a Reverse Level Order manner but with a slight modification. We will use a variable flag and initially set it’s value to one. As we complete the reverse level order traversal of the tree, from left to right we will set the value of flag to zero, so that next time we traverse the Tree from right to left and as we complete the traversal we set it’s value back to one. We will repeat this whole step until we have traversed the Binary Tree completely.

Below is the implementation of the above approach:

C++

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// C++ program to print reverse level order 
// traversal of a binary tree in spiral form
#include <bits/stdc++.h>
using namespace std;
  
// Binary tree Node
struct Node {
    struct Node* left;
    struct Node* right;
    int data;
  
    Node(int data)
    {
        this->data = data;
        this->left = NULL;
        this->right = NULL;
    }
};
  
// Recursive Function to find height
// of binary tree
int height(struct Node* root)
{
    if (root == NULL)
        return 0;
  
    // Compute the height of each subtree
    int lheight = height(root->left);
    int rheight = height(root->right);
  
    // Return the maximum of two
    return max(lheight + 1, rheight + 1);
}
  
// Function to Print Nodes from right to left
void rightToLeft(struct Node* root, int level)
{
    if (root == NULL)
        return;
  
    if (level == 1)
        cout << root->data << " ";
  
    else if (level > 1) {
        rightToLeft(root->right, level - 1);
        rightToLeft(root->left, level - 1);
    }
}
  
// Function to Print Nodes from left to right
void leftToRight(struct Node* root, int level)
{
    if (root == NULL)
        return;
  
    if (level == 1)
        cout << root->data << " ";
  
    else if (level > 1) {
        leftToRight(root->left, level - 1);
        leftToRight(root->right, level - 1);
    }
}
  
// Function to print Reverse level order traversal
// of a Binary tree in spiral form
void reverseSpiral(struct Node* root)
{
    // Flag is used to mark the change
    // in level
    int flag = 1;
  
    // Height of tree
    int h = height(root);
  
    for (int i = h; i >= 1; i--) {
  
        // If flag value is one print Nodes
        // from left to right
        if (flag == 1) {
            leftToRight(root, i);
  
            // Mark flag as zero so that next time
            // tree is traversed from right to left
            flag = 0;
        }
  
        // If flag is zero print Nodes
        // from right to left
        else if (flag == 0) {
            rightToLeft(root, i);
  
            // Mark flag as one so that next time
            // Nodes are printed from left to right
            flag = 1;
        }
    }
}
  
// Driver code
int main()
{
    struct Node* root = new Node(5);
    root->left = new Node(9);
    root->right = new Node(3);
    root->left->left = new Node(6);
    root->right->right = new Node(4);
    root->left->left->left = new Node(8);
    root->left->left->right = new Node(7);
  
    reverseSpiral(root);
  
    return 0;
}

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Python3

# Python3 program to prreverse level order
# traversal of a binary tree in spiral form

class newNode:

# Construct to create a newNode
def __init__(self, key):
self.data = key
self.left = None
self.right = None

# Recursive Function to find height
# of binary tree
def height(root):

if (root == None):
return 0

# Compute the height of each subtree
lheight = height(root.left)
rheight = height(root.right)

# Return the maximum of two
return max(lheight + 1, rheight + 1)

# Function to PrNodes from right to left
def rightToLeft(root, level):
if (root == None):
return

if (level == 1):
print(root.data,end=” “)

elif (level > 1):
rightToLeft(root.right, level – 1)
rightToLeft(root.left, level – 1)

# Function to PrNodes from left to right
def leftToRight(root, level):
if (root == None):
return

if (level == 1) :
print(root.data, end = ” “)

elif (level > 1):
leftToRight(root.left, level – 1)
leftToRight(root.right, level – 1)

# Function to prReverse level order traversal
# of a Binary tree in spiral form
def reverseSpiral(root):

# Flag is used to mark the
# change in level
flag = 1

# Height of tree
h = height(root)

for i in range(h, 0, -1):

# If flag value is one prNodes
# from left to right
if (flag == 1):
leftToRight(root, i)

# Mark flag as zero so that next time
# tree is traversed from right to left
flag = 0

# If flag is zero prNodes
# from right to left
elif (flag == 0):
rightToLeft(root, i)

# Mark flag as one so that next time
# Nodes are printed from left to right
flag = 1

# Driver Code
if __name__ == ‘__main__’:
root = newNode(5)
root.left = newNode(9)
root.right = newNode(3)
root.left.left = newNode(6)
root.right.right = newNode(4)
root.left.left.left = newNode(8)
root.left.left.right = newNode(7)

reverseSpiral(root)

# This code is contributed
# by SHUBHAMSINGH10

Output:

8 7 4 6 9 3 5


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Improved By : SHUBHAMSINGH10