# Reverse Anti Clockwise Spiral Traversal of a Binary Tree

Given a binary tree, the task is to print the nodes of the tree in a reverse anti-clockwise spiral manner.

Examples:

```Input :
1
/  \
2    3
/ \    \
4   5    6
/    / \
7    8   9
Output : 7 8 9 1 4 5 6 3 2

Input :
20
/   \
8     22
/   \  /   \
5     3 4    25
/ \
10  14
Output : 10 14 20 5 3 4 25 22 8
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The idea is to use two variables i initialized to 1 and j initialized to the height of tree and run a while loop which wont break until i becomes greater than j. We will use another variable flag and initialize it to 1. Now in the while loop we will check a condition that if flag is equal to 1 we will traverse the tree from left to right and mark flag as 0 so that next time we traverse the tree from right to left and then decrement the value of j so that next time we visit the level just above the current level. Also when we will traverse the level from top we will mark flag as 1 so that next time we traverse the tree from left to right and then increment the value of i so that next time we visit the level just below the current level. Repeat the whole process until the binary tree is completely traversed.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach ` `#include ` `using` `namespace` `std; ` ` `  `// Binary tree node ` `struct` `Node { ` `    ``struct` `Node* left; ` `    ``struct` `Node* right; ` `    ``int` `data; ` ` `  `    ``Node(``int` `data) ` `    ``{ ` `        ``this``->data = data; ` `        ``this``->left = NULL; ` `        ``this``->right = NULL; ` `    ``} ` `}; ` ` `  `// Recursive Function to find height ` `// of binary tree ` `int` `height(``struct` `Node* root) ` `{ ` `    ``// Base condition ` `    ``if` `(root == NULL) ` `        ``return` `0; ` ` `  `    ``// Compute the height of each subtree ` `    ``int` `lheight = height(root->left); ` `    ``int` `rheight = height(root->right); ` ` `  `    ``// Return the maximum of two ` `    ``return` `max(1 + lheight, 1 + rheight); ` `} ` ` `  `// Function to Print Nodes from left to right ` `void` `leftToRight(``struct` `Node* root, ``int` `level) ` `{ ` `    ``if` `(root == NULL) ` `        ``return``; ` ` `  `    ``if` `(level == 1) ` `        ``cout << root->data << ``" "``; ` ` `  `    ``else` `if` `(level > 1) { ` `        ``leftToRight(root->left, level - 1); ` `        ``leftToRight(root->right, level - 1); ` `    ``} ` `} ` ` `  `// Function to Print Nodes from right to left ` `void` `rightToLeft(``struct` `Node* root, ``int` `level) ` `{ ` `    ``if` `(root == NULL) ` `        ``return``; ` ` `  `    ``if` `(level == 1) ` `        ``cout << root->data << ``" "``; ` ` `  `    ``else` `if` `(level > 1) { ` `        ``rightToLeft(root->right, level - 1); ` `        ``rightToLeft(root->left, level - 1); ` `    ``} ` `} ` ` `  `// Function to print Reverse anti clockwise spiral ` `// traversal of a binary tree ` `void` `ReverseAntiClockWiseSpiral(``struct` `Node* root) ` `{ ` `    ``int` `i = 1; ` `    ``int` `j = height(root); ` ` `  `    ``// Flag to mark a change in the direction ` `    ``// of printing nodes ` `    ``int` `flag = 1; ` `    ``while` `(i <= j) { ` ` `  `        ``// If flag is zero print nodes ` `        ``// from right to left ` `        ``if` `(flag == 0) { ` `            ``rightToLeft(root, i); ` ` `  `            ``// Set the value of flag as zero ` `            ``// so that nodes are next time ` `            ``// printed from left to right ` `            ``flag = 1; ` ` `  `            ``// Increment i ` `            ``i++; ` `        ``} ` ` `  `        ``// If flag is one print nodes ` `        ``// from left to right ` `        ``else` `{ ` `            ``leftToRight(root, j); ` ` `  `            ``// Set the value of flag as zero ` `            ``// so that nodes are next time ` `            ``// printed from right to left ` `            ``flag = 0; ` ` `  `            ``// Decrement j ` `            ``j--; ` `        ``} ` `    ``} ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``struct` `Node* root = ``new` `Node(20); ` `    ``root->left = ``new` `Node(8); ` `    ``root->right = ``new` `Node(22); ` `    ``root->left->left = ``new` `Node(5); ` `    ``root->left->right = ``new` `Node(3); ` `    ``root->right->left = ``new` `Node(4); ` `    ``root->right->right = ``new` `Node(25); ` `    ``root->left->right->left = ``new` `Node(10); ` `    ``root->left->right->right = ``new` `Node(14); ` ` `  `    ``ReverseAntiClockWiseSpiral(root); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation of the approach  ` `class` `GfG  ` `{ ` ` `  `// Binary tree node  ` `static` `class` `Node ` `{  ` `    ``Node left;  ` `    ``Node right;  ` `    ``int` `data;  ` ` `  `    ``Node(``int` `data)  ` `    ``{  ` `        ``this``.data = data;  ` `        ``this``.left = ``null``;  ` `        ``this``.right = ``null``;  ` `    ``}  ` `}  ` ` `  `// Recursive Function to find height  ` `// of binary tree  ` `static` `int` `height(Node root)  ` `{  ` `    ``// Base condition  ` `    ``if` `(root == ``null``)  ` `        ``return` `0``;  ` ` `  `    ``// Compute the height of each subtree  ` `    ``int` `lheight = height(root.left);  ` `    ``int` `rheight = height(root.right);  ` ` `  `    ``// Return the maximum of two  ` `    ``return` `Math.max(``1` `+ lheight, ``1` `+ rheight);  ` `}  ` ` `  `// Function to Print Nodes from left to right  ` `static` `void` `leftToRight(Node root, ``int` `level)  ` `{  ` `    ``if` `(root == ``null``)  ` `        ``return``;  ` ` `  `    ``if` `(level == ``1``)  ` `        ``System.out.print(root.data + ``" "``);  ` ` `  `    ``else` `if` `(level > ``1``) ` `    ``{  ` `        ``leftToRight(root.left, level - ``1``);  ` `        ``leftToRight(root.right, level - ``1``);  ` `    ``}  ` `}  ` ` `  `// Function to Print Nodes from right to left  ` `static` `void` `rightToLeft( Node root, ``int` `level)  ` `{  ` `    ``if` `(root == ``null``)  ` `        ``return``;  ` ` `  `    ``if` `(level == ``1``)  ` `        ``System.out.print(root.data + ``" "``);  ` ` `  `    ``else` `if` `(level > ``1``)  ` `    ``{  ` `        ``rightToLeft(root.right, level - ``1``);  ` `        ``rightToLeft(root.left, level - ``1``);  ` `    ``}  ` `}  ` ` `  `// Function to print Reverse anti clockwise spiral  ` `// traversal of a binary tree  ` `static` `void` `ReverseAntiClockWiseSpiral(Node root)  ` `{  ` `    ``int` `i = ``1``;  ` `    ``int` `j = height(root);  ` ` `  `    ``// Flag to mark a change in the direction  ` `    ``// of printing nodes  ` `    ``int` `flag = ``1``;  ` `    ``while` `(i <= j)  ` `    ``{  ` ` `  `        ``// If flag is zero print nodes  ` `        ``// from right to left  ` `        ``if` `(flag == ``0``)  ` `        ``{  ` `            ``rightToLeft(root, i);  ` ` `  `            ``// Set the value of flag as zero  ` `            ``// so that nodes are next time  ` `            ``// printed from left to right  ` `            ``flag = ``1``;  ` ` `  `            ``// Increment i  ` `            ``i++;  ` `        ``}  ` ` `  `        ``// If flag is one print nodes  ` `        ``// from left to right  ` `        ``else`  `        ``{  ` `            ``leftToRight(root, j);  ` ` `  `            ``// Set the value of flag as zero  ` `            ``// so that nodes are next time  ` `            ``// printed from right to left  ` `            ``flag = ``0``;  ` ` `  `            ``// Decrement j  ` `            ``j--;  ` `        ``}  ` `    ``}  ` `}  ` ` `  `// Driver code  ` `public` `static` `void` `main(String[] args)  ` `{  ` `    ``Node root = ``new` `Node(``20``);  ` `    ``root.left = ``new` `Node(``8``);  ` `    ``root.right = ``new` `Node(``22``);  ` `    ``root.left.left = ``new` `Node(``5``);  ` `    ``root.left.right = ``new` `Node(``3``);  ` `    ``root.right.left = ``new` `Node(``4``);  ` `    ``root.right.right = ``new` `Node(``25``);  ` `    ``root.left.right.left = ``new` `Node(``10``);  ` `    ``root.left.right.right = ``new` `Node(``14``);  ` ` `  `    ``ReverseAntiClockWiseSpiral(root);  ` ` `  `}  ` `}  ` ` `  `// This code is contributed by Prerna Saini. `

## C#

 `// C# implementation of the approach ` `using` `System; ` ` `  `class` `GfG  ` `{  ` ` `  `// Binary tree node  ` `public` `class` `Node  ` `{  ` `    ``public` `Node left;  ` `    ``public` `Node right;  ` `    ``public` `int` `data;  ` ` `  `    ``public` `Node(``int` `data)  ` `    ``{  ` `        ``this``.data = data;  ` `        ``this``.left = ``null``;  ` `        ``this``.right = ``null``;  ` `    ``}  ` `}  ` ` `  `// Recursive Function to find height  ` `// of binary tree  ` `static` `int` `height(Node root)  ` `{  ` `    ``// Base condition  ` `    ``if` `(root == ``null``)  ` `        ``return` `0;  ` ` `  `    ``// Compute the height of each subtree  ` `    ``int` `lheight = height(root.left);  ` `    ``int` `rheight = height(root.right);  ` ` `  `    ``// Return the maximum of two  ` `    ``return` `Math.Max(1 + lheight, 1 + rheight);  ` `}  ` ` `  `// Function to Print Nodes from left to right  ` `static` `void` `leftToRight(Node root, ``int` `level)  ` `{  ` `    ``if` `(root == ``null``)  ` `        ``return``;  ` ` `  `    ``if` `(level == 1)  ` `        ``Console.Write(root.data + ``" "``);  ` ` `  `    ``else` `if` `(level > 1)  ` `    ``{  ` `        ``leftToRight(root.left, level - 1);  ` `        ``leftToRight(root.right, level - 1);  ` `    ``}  ` `}  ` ` `  `// Function to Print Nodes from right to left  ` `static` `void` `rightToLeft( Node root, ``int` `level)  ` `{  ` `    ``if` `(root == ``null``)  ` `        ``return``;  ` ` `  `    ``if` `(level == 1)  ` `        ``Console.Write(root.data + ``" "``);  ` ` `  `    ``else` `if` `(level > 1)  ` `    ``{  ` `        ``rightToLeft(root.right, level - 1);  ` `        ``rightToLeft(root.left, level - 1);  ` `    ``}  ` `}  ` ` `  `// Function to print Reverse anti clockwise spiral  ` `// traversal of a binary tree  ` `static` `void` `ReverseAntiClockWiseSpiral(Node root)  ` `{  ` `    ``int` `i = 1;  ` `    ``int` `j = height(root);  ` ` `  `    ``// Flag to mark a change in the direction  ` `    ``// of printing nodes  ` `    ``int` `flag = 1;  ` `    ``while` `(i <= j)  ` `    ``{  ` ` `  `        ``// If flag is zero print nodes  ` `        ``// from right to left  ` `        ``if` `(flag == 0)  ` `        ``{  ` `            ``rightToLeft(root, i);  ` ` `  `            ``// Set the value of flag as zero  ` `            ``// so that nodes are next time  ` `            ``// printed from left to right  ` `            ``flag = 1;  ` ` `  `            ``// Increment i  ` `            ``i++;  ` `        ``}  ` ` `  `        ``// If flag is one print nodes  ` `        ``// from left to right  ` `        ``else` `        ``{  ` `            ``leftToRight(root, j);  ` ` `  `            ``// Set the value of flag as zero  ` `            ``// so that nodes are next time  ` `            ``// printed from right to left  ` `            ``flag = 0;  ` ` `  `            ``// Decrement j  ` `            ``j--;  ` `        ``}  ` `    ``}  ` `}  ` ` `  `// Driver code  ` `public` `static` `void` `Main(String[] args)  ` `{  ` `    ``Node root = ``new` `Node(20);  ` `    ``root.left = ``new` `Node(8);  ` `    ``root.right = ``new` `Node(22);  ` `    ``root.left.left = ``new` `Node(5);  ` `    ``root.left.right = ``new` `Node(3);  ` `    ``root.right.left = ``new` `Node(4);  ` `    ``root.right.right = ``new` `Node(25);  ` `    ``root.left.right.left = ``new` `Node(10);  ` `    ``root.left.right.right = ``new` `Node(14);  ` ` `  `    ``ReverseAntiClockWiseSpiral(root);  ` ` `  `}  ` `}  ` ` `  `// This code has been contributed by 29AjayKumar `

Output:

```10 14 20 5 3 4 25 22 8
```

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Improved By : prerna saini, 29AjayKumar