Given a number, you have to represent this number as sum of minimum number of possible *psuedobinary* numbers. A number is said to be *psuedobinary* number if its decimal number consists of only two digits (0 and 1). Example: 11,10,101 are all psuedobinary numbers.

**Examples :-**

Input : 44 Output : 11 11 11 11 Explanation : 44 can be represented as sum of minimum 4 psuedobinary numbers as 11+11+11+11 Input : 31 Output : 11 10 10 Explanation : 31 can be represented as sum of minimum 3 psuedobinary numbers as 11+10+10

The idea to do this is to first observe carefully that we need to calculate minimum number of possible psuedobinary numbers. To do this we find a new number m such that if for a place in given number n, the digit is non-zero then the digit in that place in m is 1 otherwise zero. For example if n = 5102, then m will be 1101. Then we will print this number m and subtract m from n. We will keep repeating these steps until n is greater than zero.

## C++

`// C++ program to represent a given ` `// number as sum of minimum possible` `// psuedobinary numbers` `#include<iostream>` `using` `namespace` `std;` ` ` `// function to represent a given ` `// number as sum of minimum possible` `// psuedobinary numbers` `void` `psuedoBinary(` `int` `n)` `{` ` ` `// Repeat below steps until n > 0` ` ` `while` `(n > 0)` ` ` `{ ` ` ` `// calculate m (A number that has same` ` ` `// number of digits as n, but has 1 in` ` ` `// place of non-zero digits 0 in place` ` ` `// of 0 digits)` ` ` `int` `temp = n, m = 0, p = 1;` ` ` `while` `(temp)` ` ` `{` ` ` `int` `rem = temp % 10;` ` ` `temp = temp / 10;` ` ` ` ` `if` `(rem != 0)` ` ` `m += p;` ` ` ` ` `p *= 10;` ` ` `}` ` ` ` ` `cout << m << ` `" "` `;` ` ` ` ` `// subtract m from n` ` ` `n = n - m;` ` ` `}` `}` ` ` `// Driver code` `int` `main()` `{` ` ` `int` `n = 31;` ` ` ` ` `psuedoBinary(n);` ` ` ` ` `return` `0;` `}` |

## Java

`// Java program to represent a given` `// number as sum of minimum possible` `// psuedobinary numbers` ` ` `import` `java.util.*;` `import` `java.lang.*;` ` ` `class` `GFG` `{` ` ` `public` `static` `void` `psuedoBinary(` `int` `n)` ` ` `{` ` ` `// Repeat below steps until n > 0` ` ` `while` `(n != ` `0` `)` ` ` `{` ` ` `// calculate m (A number that has same` ` ` `// number of digits as n, but has 1 in` ` ` `// place of non-zero digits 0 in place` ` ` `// of 0 digits)` ` ` `int` `temp = n, m = ` `0` `, p = ` `1` `;` ` ` `while` `(temp != ` `0` `)` ` ` `{` ` ` `int` `rem = temp % ` `10` `;` ` ` `temp = temp / ` `10` `;` ` ` ` ` `if` `(rem != ` `0` `)` ` ` `m += p;` ` ` ` ` `p *= ` `10` `;` ` ` `}` ` ` ` ` `System.out.print(m + ` `" "` `);` ` ` ` ` `// subtract m from n` ` ` `n = n - m;` ` ` `}` ` ` `System.out.println(` `" "` `);` ` ` `}` ` ` `// Driver code` `public` `static` `void` `main(String[] args)` ` ` `{` ` ` `int` `n = ` `31` `;` ` ` `psuedoBinary(n);` ` ` `}` `}` ` ` `// This code is contributed by Mohit Gupta_OMG` |

## Python3

`# Python3 program to represent ` `# a given number as sum of ` `# minimum possible psuedobinary ` `# numbers` ` ` `# function to represent a ` `# given number as sum of` `# minimum possible` `# psuedobinary numbers` `def` `psuedoBinary(n):` ` ` ` ` `# Repeat below steps` ` ` `# until n > 0` ` ` `while` `(n > ` `0` `):` ` ` ` ` `# calculate m (A number ` ` ` `# that has same number ` ` ` `# of digits as n, but ` ` ` `# has 1 in place of non-zero ` ` ` `# digits 0 in place of 0 digits)` ` ` `temp ` `=` `n;` ` ` `m ` `=` `0` `;` ` ` `p ` `=` `1` `;` ` ` `while` `(temp):` ` ` `rem ` `=` `temp ` `%` `10` `;` ` ` `temp ` `=` `int` `(temp ` `/` `10` `);` ` ` ` ` `if` `(rem !` `=` `0` `):` ` ` `m ` `+` `=` `p;` ` ` `p ` `*` `=` `10` `;` ` ` ` ` `print` `(m,end` `=` `" "` `);` ` ` ` ` `# subtract m from n` ` ` `n ` `=` `n ` `-` `m;` ` ` `# Driver code` `n ` `=` `31` `;` `psuedoBinary(n);` ` ` `# This code is contributed` `# by mits.` |

## C#

`// C# program to represent a given` `// number as sum of minimum possible` `// psuedobinary numbers` ` ` `using` `System;` ` ` `class` `GFG` `{` ` ` `public` `static` `void` `psuedoBinary(` `int` `n)` ` ` `{` ` ` `// Repeat below steps until n > 0` ` ` `while` `(n != 0)` ` ` `{` ` ` `// calculate m (A number that has same` ` ` `// number of digits as n, but has 1 in` ` ` `// place of non-zero digits 0 in place` ` ` `// of 0 digits)` ` ` `int` `temp = n, m = 0, p = 1;` ` ` `while` `(temp != 0)` ` ` `{` ` ` `int` `rem = temp % 10;` ` ` `temp = temp / 10;` ` ` ` ` `if` `(rem != 0)` ` ` `m += p;` ` ` ` ` `p *= 10;` ` ` `}` ` ` ` ` `Console.Write(m + ` `" "` `);` ` ` ` ` `// subtract m from n` ` ` `n = n - m;` ` ` `}` ` ` `Console.Write(` `" "` `);` ` ` `}` ` ` `// Driver code` `public` `static` `void` `Main()` ` ` `{` ` ` `int` `n = 31;` ` ` `psuedoBinary(n);` ` ` `}` `}` ` ` `// This code is contributed by nitin mittal` |

## PHP

`<?php` `// PHP program to represent a ` `// given number as sum of minimum ` `// possible psuedobinary numbers` ` ` `// Function to represent a ` `// given number as sum of minimum ` `// possible psuedobinary numbers` `function` `psuedoBinary(` `$n` `)` `{` ` ` `// Repeat below steps until n > 0` ` ` `while` `(` `$n` `> 0)` ` ` `{ ` ` ` `// calculate m (A number ` ` ` `// that has same number of ` ` ` `// digits as n, but has 1 ` ` ` `// in place of non-zero ` ` ` `// digits 0 in place of 0 ` ` ` `// digits)` ` ` `$temp` `= ` `$n` `; ` `$m` `= 0; ` `$p` `= 1;` ` ` `while` `(` `$temp` `)` ` ` `{` ` ` `$rem` `= ` `$temp` `% 10;` ` ` `$temp` `= ` `$temp` `/ 10;` ` ` ` ` `if` `(` `$rem` `!= 0)` ` ` `$m` `+= ` `$p` `;` ` ` ` ` `$p` `*= 10;` ` ` `}` ` ` ` ` `echo` `$m` `, ` `" "` `;` ` ` ` ` `// subtract m from n` ` ` `$n` `= ` `$n` `- ` `$m` `;` ` ` `}` `}` ` ` `// Driver code` `$n` `= 31;` `psuedoBinary(` `$n` `);` ` ` `// This code is contributed` `// by nitin mittal.` `?>` |

**Output :**

11 10 10

**Time Complexity** : O( log n )**Auxiliary Space** : O(1)

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