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# Replace every element of the array by product of all other elements

Given an array of positive integers. Replace every element by the product of all other elements of the array.

Examples:

```Input : arr[] = { 2, 3, 3, 5, 7 }
Output : 315 210 210 126 90```

Approach :

• First, take the product of all the element of the array.
• Now replace each element by the product divided by that element.
• Print the modified array.

Below is the implementation of above approach:

## C++

 `// C++ program to Replace every element``// by the product of all other elements``#include "iostream"``using` `namespace` `std;` `void` `ReplaceElements(``int` `arr[], ``int` `n)``{``    ``int` `prod = 1;` `    ``// Calculate the product of all the elements``    ``for` `(``int` `i = 0; i < n; ++i) {``        ``prod *= arr[i];``    ``}` `    ``// Replace every element product``    ``// of all other elements``    ``for` `(``int` `i = 0; i < n; ++i) {``        ``arr[i] = prod / arr[i];``    ``}``}` `int` `main()``{``    ``int` `arr[] = { 2, 3, 3, 5, 7 };``    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr[0]);` `    ``ReplaceElements(arr, n);` `    ``// Print the modified array.``    ``for` `(``int` `i = 0; i < n; ++i) {``        ``cout << arr[i] << ``" "``;``    ``}``    ``return` `0;``}`

## Java

 `// Java program to Replace every element``// by the product of all other elements` `class` `GFG{``static` `void` `ReplaceElements(``int` `arr[], ``int` `n)``{``    ``int` `prod = ``1``;` `    ``// Calculate the product of all the elements``    ``for` `(``int` `i = ``0``; i < n; ++i) {``        ``prod *= arr[i];``    ``}` `    ``// Replace every element product``    ``// of all other elements``    ``for` `(``int` `i = ``0``; i < n; ++i) {``        ``arr[i] = prod / arr[i];``    ``}``}` `public` `static` `void` `main(String[] args)``{``    ``int` `arr[] = { ``2``, ``3``, ``3``, ``5``, ``7` `};``    ``int` `n = arr.length;` `    ``ReplaceElements(arr, n);` `    ``// Print the modified array.``    ``for` `(``int` `i = ``0``; i < n; ++i) {``        ``System.out.print(arr[i]+``" "``);``    ``}``    ``System.out.println(``""``);` `}``}``// This code is contributed by mits`

## Python 3

 `# Python 3 program to Replace every``# element by the product of all``# other elements` `def` `ReplaceElements(arr, n):``    ``prod ``=` `1` `    ``# Calculate the product of``    ``# all the elements``    ``for` `i ``in` `range``(n):``        ``prod ``*``=` `arr[i]` `    ``# Replace every element product``    ``# of all other elements``    ``for` `i ``in` `range``(n) :``        ``arr[i] ``=` `prod ``/``/` `arr[i]` `# Driver Code``if` `__name__ ``=``=` `"__main__"``:``    ``arr ``=` `[ ``2``, ``3``, ``3``, ``5``, ``7` `]``    ``n ``=` `len``(arr)` `    ``ReplaceElements(arr, n)` `    ``# Print the modified array.``    ``for` `i ``in` `range``( n):``        ``print``(arr[i], end ``=` `" "``)` `# This code is contributed``# by ChitraNayal`

## C#

 `// C# program to Replace every element``// by the product of all other elements``using` `System;` `class` `GFG``{``static` `void` `ReplaceElements(``int` `[]arr, ``int` `n)``{``    ``int` `prod = 1;` `    ``// Calculate the product of``    ``// all the elements``    ``for` `(``int` `i = 0; i < n; ++i)``    ``{``        ``prod *= arr[i];``    ``}` `    ``// Replace every element product``    ``// of all other elements``    ``for` `(``int` `i = 0; i < n; ++i)``    ``{``        ``arr[i] = prod / arr[i];``    ``}``}` `// Driver Code``static` `public` `void` `Main ()``{``    ``int` `[]arr = { 2, 3, 3, 5, 7 };``    ``int` `n = arr.Length;``    ` `    ``ReplaceElements(arr, n);``    ` `    ``// Print the modified array.``    ``for` `(``int` `i = 0; i < n; ++i)``    ``{``        ``Console.Write(arr[i]+``" "``);``    ``}``    ``Console.WriteLine(``""``);``}``}` `// This code is contributed by ajit`

## PHP

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## Javascript

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Output

`315 210 210 126 90 `

Complexity Analysis:

• Time Complexity: O(N)
• Auxiliary Space: O(1)