Reorder the position of the words in alphabetical order

Given an array arr[] of strings, the task is to reorder the strings lexicographically and print their positions in the original list.

Examples:

Input: arr[] = {“zxc”, “efg”, “jkl”}
Output: 2 3 1
Sorted list will be {“efg”, “jkl”, “zxc”} and their
original positions were 2, 3 and 1 respectively.



Input: arr[] = {“live”, “place”, “travel”, “word”, “sky”}
Output: 1 2 5 3 4

Approach: Assign all the words an integer number equal to their position in the array. Then sort the list of words lexicographically and there positions are altered, and therefore there positions are printed starting from the first word in the sorted list.

Below is the implementation of the above approach:

C++

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// CPP implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to print the ordering of words
void reArrange(string words[], int n)
{
  
    // Creating list of words and assigning
    // them index numbers
    map<string, int> mp;
    for (int i = 0; i < n; i++)
        mp[words[i]] = i + 1;
  
    // Sort the list of words
    // lexicographically
    sort(words, words + n);
  
    // Print the ordering
    for (int i = 0; i < n; i++)
        cout << mp[words[i]] << " ";
}
  
// Driver Code
int main()
{
    string words[] = { "live", "place", "travel", "word", "sky" };
    int n = sizeof(words) / sizeof(words[0]);
    reArrange(words, n);
}
  
// This code is contributed by
// Surendra_Gangwar

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Java














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// Java implementation of the approach 


import java.util.*; 


class GFG { 


  


    // Function to print the ordering of words 


    static void reArrange(String words[], int n) 


    { 


  


        // Creating list of words and assigning 


        // them index numbers 


        HashMap<String, Integer> freq = new HashMap<>(); 


        for (int i = 0; i < n; i++) { 


            freq.put(words[i], (i + 1)); 


        } 


  


        // Sort the list of words 


        // lexicographically 


        Arrays.sort(words); 


  


        // Print the ordering 


        for (int i = 0; i < n; i++) 


            System.out.print(freq.get(words[i]) + " "); 


    } 


  


    // Driver Code 


    public static void main(String[] args) 


    { 


        String words[] = { "live", "place", "travel", "word", "sky" }; 


        int n = words.length; 


        reArrange(words, n); 


    } 


} 



















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Python3














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# Python3 implementation of the approach  


  


# Function to print the ordering of words  


def reArrange(words, n): 


    # Creating list of words and assigning  


    # them index numbers 


    mp = {} 


    for i in range(n): 


        mp[words[i]] = i + 1


  


    # Sort the list of words 


    # lexicographically 


    words.sort(); 


  


    # Print the ordering 


    for i in range(n): 


        print(mp[words[i]], end = " ")  


  


# Driver Code  


  


words = [ "live", "place", "travel", "word", "sky" ]  


n = len(words)  


reArrange(words, n);  


  


# This code is contributed by  


# Rajnis09  



















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C#














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// C# implementation of the approach 


using System; 


using System.Collections.Generic; 


  


class GFG { 


  


    // Function to print the ordering of words 


    static void reArrange(String[] words, int n) 


    { 


  


        // Creating list of words and assigning 


        // them index numbers 


        Dictionary<String, int> freq = new Dictionary<String, int>(); 


        for (int i = 0; i < n; i++) { 


            freq.Add(words[i], (i + 1)); 


        } 


  


        // Sort the list of words 


        // lexicographically 


        Array.Sort(words); 


  


        // Print the ordering 


        for (int i = 0; i < n; i++) 


            Console.Write(freq[words[i]] + " "); 


    } 


  


    // Driver Code 


    public static void Main(String[] args) 


    { 


        String[] words = { "live", "place", "travel", "word", "sky" }; 


        int n = words.Length; 


        reArrange(words, n); 


    } 


} 


  


// This code contributed by Rajput-Ji 



















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PHP














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<?php 


// PHP implementation of the approach  


  


    // Function to print the ordering of words  


    function reArrange($words, $n)  


    {  


  


        // Creating list of words and assigning  


        // them index numbers  


        $freq = array();  


        for ($i = 0; $i < $n; $i++) 


        {  


            $freq[$words[$i]] = ($i + 1) ;  


        }  


  


        // Sort the list of words  


        // lexicographically  


        sort($words);  


  


        // Print the ordering  


        for ($i = 0; $i < $n; $i++)  


            echo $freq[$words[$i]], " " ;  


    }  


  


    // Driver Code  


    $words = array( "live", "place", "travel", "word", "sky" );  


    $n = count($words);  


    reArrange($words, $n); 


      


    // This code is contributed by Ryuga 


?> 



















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Output:


1 2 5 3 4







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