# Removing a number from array without changing its arithmetic mean

• Difficulty Level : Easy
• Last Updated : 04 Jan, 2022

Given an array a[] of positive integers of size N. The task is to remove one element from the given array such that the arithmetic mean of the array remains the same as it was before. If it is possible to remove any such number then print that number. Otherwise, print -1.
Examples:

Input : a[] = {1, 2, 3, 4, 5}
Output : 3
Mean of the given array is 3. After removing the 3rd element
array becomes {1, 2, 4, 5} whose mean is 3 too.
Input : a[] = {5, 4, 3, 6}
Output : -1

Approach :

An efficient approach is to find the mean of the array, and check whether the mean is present in the given array or not. We can only remove elements whose value is equal to mean.

let mean of the original array be M, the sum of the elements be sum. Then sum = M * N. After removing M, the new mean will be ( (M * N ) – M) / (N – 1) = M, which remains same. So just use any search approach and print the element.

Below is the implementation of the above approach :

## C++

 `// CPP program to remove a number from the``// array without changing its arithmetic mean``#include ``using` `namespace` `std;` `// Function to remove a number from the``// array without changing its arithmetic mean``int` `FindElement(``int` `a[], ``int` `n)``{``    ``// Find sum of all elements``    ``int` `sum = 0;``    ``for` `(``int` `i = 0; i < n; i++)``        ``sum = sum + a[i];` `    ``// If mean is an integer``    ``if` `(sum % n == 0) {``        ``int` `m = sum / n;` `        ``// Check if mean is present in the array or not``        ``for` `(``int` `i = 0; i < n; i++)``            ``if` `(a[i] == m)``                ``return` `m;``    ``}` `    ``return` `-1;``}` `// Driver code``int` `main()``{``    ``int` `a[] = { 1, 2, 3, 4, 5 };` `    ``int` `n = ``sizeof``(a) / ``sizeof``(``int``);` `    ``cout << FindElement(a, n);` `    ``return` `0;``}`

## Java

 `// Java program to remove a number from the``// array without changing its arithmetic mean``import` `java.io.*;` `class` `GFG``{` `// Function to remove a number from the``// array without changing its arithmetic mean``static` `int` `FindElement(``int` `a[], ``int` `n)``{``    ``// Find sum of all elements``    ``int` `sum = ``0``;``    ``for` `(``int` `i = ``0``; i < n; i++)``        ``sum = sum + a[i];` `    ``// If mean is an integer``    ``if` `(sum % n == ``0``)``    ``{``        ``int` `m = sum / n;` `        ``// Check if mean is present in the array or not``        ``for` `(``int` `i = ``0``; i < n; i++)``            ``if` `(a[i] == m)``                ``return` `m;``    ``}` `    ``return` `-``1``;``}` `// Driver code``public` `static` `void` `main (String[] args)``{``    ``int` `a[] = { ``1``, ``2``, ``3``, ``4``, ``5` `};``    ``int` `n = a.length;` `    ``System.out.print(FindElement(a, n));``}``}` `// This code is contributed by anuj_67..`

## Python3

 `# Python3 program to remove a number from the``# array without changing its arithmetic mean` `# Function to remove a number from the``# array without changing its arithmetic mean``def` `FindElement(a, n):` `    ``# Find sum of all elements``    ``s ``=` `0``    ``for` `i ``in` `range``(n):``        ``s ``=` `s ``+` `a[i]` `    ``# If mean is an integer``    ``if` `s ``%` `n ``=``=` `0``:``        ``m ``=` `s ``/``/` `n` `        ``# Check if mean is present``        ``# in the array or not``        ``for` `j ``in` `range``(n):``            ``if` `a[j] ``=``=` `m:``                ``return` `m``    ``return` `-``1` `# Driver code``if` `__name__ ``=``=` `"__main__"``:``    ``a ``=` `[``1``, ``2``, ``3``, ``4``, ``5``]``    ``n ``=` `len``(a)``    ``print``(FindElement(a, n))` `# This code is contributed by``# sanjeev2552`

## C#

 `// C# program to remove a number from the``// array without changing its arithmetic mean``using` `System;` `class` `GFG``{` `// Function to remove a number from the``// array without changing its arithmetic mean``static` `int` `FindElement(``int` `[]a, ``int` `n)``{``    ``// Find sum of all elements``    ``int` `sum = 0;``    ``for` `(``int` `i = 0; i < n; i++)``        ``sum = sum + a[i];` `    ``// If mean is an integer``    ``if` `(sum % n == 0)``    ``{``        ``int` `m = sum / n;` `        ``// Check if mean is present in the array or not``        ``for` `(``int` `i = 0; i < n; i++)``            ``if` `(a[i] == m)``                ``return` `m;``    ``}` `    ``return` `-1;``}` `// Driver code``public` `static` `void` `Main ()``{``    ``int` `[]a = { 1, 2, 3, 4, 5 };``    ``int` `n = a.Length;` `    ``Console.WriteLine(FindElement(a, n));``}``}` `// This code is contributed by anuj_67..`

## Javascript

 ``

Output:

`3`

Time Complexity : O(N)

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