Remove all the palindromic words from the given sentence

1

Given a sentence str. The problem is to remove all the palindromic words from the given sentence.

Examples:

Input : str = "Text contains malayalam and level words"
Output : This contains and words

Input : str = "abc bcd"
Output : abc bcd

Approach: One by one extract all the words. Check if the current word is not a palindrome then add it to the final string.
Algorithm:

removePalinWords(str, n)
    Initialize final_str = "", word = ""
    str = str + " "
    
    for i = 0 to n-1
        if str[i] != ' ', then
        word = word + str[i]
    else 
        if (!(isPalindrome(word)), then
            final_str += word + " "
        word = ""
            
    return final_str

isPalindrome() function is used to check whether the given string is palindrome or not. Refer this post.

// C++ implementation to remove all the 
// palindromic words from the given sentence
#include <bits/stdc++.h>
using namespace std;

// function to check if 'str' is palindrome
bool isPalindrome(string str) {
  int i = 0, j = str.size() - 1;

  // traversing from both the ends
  while (i < j)

    // not palindrome
    if (str[i++] != str[j--])
      return false;

  // palindrome
  return true;
}

// function to remove all the palindromic words
// from the given sentence
string removePalinWords(string str) {

  // 'final_str' to store the final string and
  // 'word' to one by one store each word of 'str'
  string final_str = "", word = "";

  // add space at the end of 'str'
  str = str + " ";
  int n = str.size();

  // traversing 'str'
  for (int i = 0; i < n; i++) {

    // accumulating characters of the current word
    if (str[i] != ' ')
      word = word + str[i];

    else {

      // if 'word' is not palindrome then a
      // add it to 'final_str'
      if (!(isPalindrome(word)))
        final_str += word + " ";

      // reset
      word = "";
    }
  }

  // required final string
  return final_str;
}

// Driver program to test above
int main() {
  string str = "Text contains malayalam and level words";
  cout << removePalinWords(str);
  return 0;
}

Output:

Text contains and words

Time Complexity: O(n).


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