Remove duplicates from a sorted doubly linked list

Given a sorted doubly linked list containing n nodes. The problem is removing duplicate nodes from the given list.

Examples:

Algorithm:

removeDuplicates(head_ref, x)
      if head_ref == NULL
          return
      Initialize current = head_ref
      while current->next != NULL
           if current->data == current->next->data
               deleteNode(head_ref, current->next)
           else
               current = current->next

The algorithm for deleteNode(head_ref, current) (which deletes the node using the pointer to the node) is discussed in this post.

Implementation:

C++

/* C++ implementation to remove duplicates from a
   sorted doubly linked list */
#include <bits/stdc++.h>

using namespace std;

/* a node of the doubly linked list */
struct Node {
    int data;
    struct Node* next;
    struct Node* prev;
};

/* Function to delete a node in a Doubly Linked List.
   head_ref --> pointer to head node pointer.
   del  -->  pointer to node to be deleted. */
void deleteNode(struct Node** head_ref, struct Node* del)
{
    /* base case */
    if (*head_ref == NULL || del == NULL)
        return;

    /* If node to be deleted is head node */
    if (*head_ref == del)
        *head_ref = del->next;

    /* Change next only if node to be deleted
        is NOT the last node */
    if (del->next != NULL)
        del->next->prev = del->prev;

    /* Change prev only if node to be deleted
       is NOT the first node */
    if (del->prev != NULL)
        del->prev->next = del->next;

    /* Finally, free the memory occupied by del*/
    free(del);
}

/* function to remove duplicates from a
   sorted doubly linked list */
void removeDuplicates(struct Node** head_ref)
{
    /* if list is empty */
    if ((*head_ref) == NULL)
        return;

    struct Node* current = *head_ref;
    struct Node* next;

    /* traverse the list till the last node */
    while (current->next != NULL) {

        /* Compare current node with next node */
        if (current->data == current->next->data)

            /* delete the node pointed to by
              'current->next' */
            deleteNode(head_ref, current->next);

        /* else simply move to the next node */
        else
            current = current->next;
    }
}

/* Function to insert a node at the beginning
   of the Doubly Linked List */
void push(struct Node** head_ref, int new_data)
{
    /* allocate node */
    struct Node* new_node =
           (struct Node*)malloc(sizeof(struct Node));

    /* put in the data  */
    new_node->data = new_data;

    /* since we are adding at the beginning,
    prev is always NULL */
    new_node->prev = NULL;

    /* link the old list of the new node */
    new_node->next = (*head_ref);

    /* change prev of head node to new node */
    if ((*head_ref) != NULL)
        (*head_ref)->prev = new_node;

    /* move the head to point to the new node */
    (*head_ref) = new_node;
}

/* Function to print nodes in a given doubly linked list */
void printList(struct Node* head)
{
    /* if list is empty */
    if (head == NULL)
        cout << "Doubly Linked list empty";

    while (head != NULL) {
        cout << head->data << " ";
        head = head->next;
    }
}

/* Driver program to test above functions*/
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;

    /* Create the doubly linked list:
     4<->4<->4<->4<->6<->8<->8<->10<->12<->12 */
    push(&head, 12);
    push(&head, 12);
    push(&head, 10);
    push(&head, 8);
    push(&head, 8);
    push(&head, 6);
    push(&head, 4);
    push(&head, 4);
    push(&head, 4);
    push(&head, 4);

    cout << "Original doubly linked list:\n";
    printList(head);

    /* remove duplicate nodes */
    removeDuplicates(&head);

    cout << "\nDoubly linked list after"
             " removing duplicates:\n";
    printList(head);

    return 0;
}

Java

/* Java implementation to remove duplicates from a
   sorted doubly linked list */
public class removeDuplicatesFromSortedList {

    /* function to remove duplicates from a
   sorted doubly linked list */
    public static void removeDuplicates(Node head)
    {
        /* if list is empty */
        if (head== null)
            return;

        Node current = head;

        /* traverse the list till the last node */
        while (current.next != null)
        {
            /* Compare current node with next node */
            if (current.data == current.next.data)
                /* delete the node pointed to by
              ' current->next' */
                deleteNode(head, current.next);

            /* else simply move to the next node */
            else
                current = current.next;
        }

    }


    /* Function to delete a node in a Doubly Linked List.
    head_ref --> pointer to head node pointer.
    del  -->  pointer to node to be deleted. */
    public static void deleteNode(Node head, Node del)
    {
         /* base case */
        if(head==null || del==null)
        {
            return ;
        }
        /* If node to be deleted is head node */
        if(head==del)
        {
            head=del.next;
        }
        /* Change next only if node to be deleted
        is NOT the last node */
        if(del.next!=null)
        {
            del.next.prev=del.prev;
        }
        /* Change prev only if node to be deleted
       is NOT the first node */
        if (del.prev != null)
            del.prev.next = del.next;

    }


    /* Function to insert a node at the beginning
    of the Doubly Linked List */
    public static Node push(Node head, int data)
    {
        /* allocate node */
        Node newNode=new Node(data);
        /* since we are adding at the beginning,
        prev is always NULL */
        newNode.prev=null;
        /* link the old list of the new node */
        newNode.next =head;
        /* change prev of head node to new node */
        if(head!=null)
        {
            head.prev=newNode;
        }
        head=newNode;
        return head;
    }

    /* Function to print nodes in a given doubly linked list */
    public static void printList(Node head)
    {
        if (head == null)
            System.out.println("Doubly Linked list empty");

        while (head != null)
        {
            System.out.print(head.data+" ") ;
            head = head.next;
        }
    }

    public static void main(String args[]) {
        Node head=null;
        head=push(head, 12);
        head=push(head, 12);
        head=push(head, 10);
        head=push(head, 8);
        head=push(head, 8);
        head=push(head, 6);
        head=push(head, 4);
        head=push(head, 4);
        head=push(head, 4);
        head=push(head, 4);

        System.out.println("Original doubly linked list:");
        printList(head);

        /* remove duplicate nodes */
        removeDuplicates(head);
        System.out.println("\nDoubly linked list after removing duplicates:");
        printList(head);
    }
}
class Node
{
    int data;
    Node next,prev;

    Node(int data)
    {
        this.data=data;
        next=null;
        prev=null;
    }
}
//This code is contributed by Gaurav Tiwari

Python

# Python implementation to remove duplicates from a
# sorted doubly linked list

# A linked list node
class Node:
    def __init__(self, new_data):
        self.data = new_data
        self.next = None
        self.prev = None

# Function to _delete a node in a Doubly Linked List.
# head_ref -. pointer to head node pointer.
# _del -. pointer to node to be _deleted.
def _deleteNode(head_ref, _del):

    # base case
    if (head_ref == None or _del == None):
        return

    # If node to be _deleted is head node
    if (head_ref == _del):
        head_ref = _del.next

    # Change next only if node to be _deleted
    # is NOT the last node
    if (_del.next != None):
        _del.next.prev = _del.prev

    # Change prev only if node to be _deleted
    # is NOT the first node
    if (_del.prev != None):
        _del.prev.next = _del.next

    return head_ref

# function to remove duplicates from a
# sorted doubly linked list
def removeDuplicates(head_ref):

    # if list is empty
    if ((head_ref) == None):
        return None

    current = head_ref
    next = None

    # traverse the list till the last node
    while (current.next != None) :

        # Compare current node with next node
        if (current.data == current.next.data):

            # _delete the node pointed to by
            # 'current.next'
            _deleteNode(head_ref, current.next)

        # else simply move to the next node
        else:
            current = current.next

    return head_ref

# Function to insert a node at the beginning
# of the Doubly Linked List
def push(head_ref, new_data):

    # allocate node
    new_node = Node(0)

    # put in the data
    new_node.data = new_data

    # since we are adding at the beginning,
    # prev is always None
    new_node.prev = None

    # link the old list of the new node
    new_node.next = (head_ref)

    # change prev of head node to new node
    if ((head_ref) != None):
        (head_ref).prev = new_node

    # move the head to point to the new node
    (head_ref) = new_node

    return head_ref

# Function to print nodes in a given doubly linked list
def printList(head):

    # if list is empty
    if (head == None):
        print("Doubly Linked list empty")

    while (head != None) :
        print(head.data, end = " ")
        head = head.next

# Driver program to test above functions

# Start with the empty list
head = None

# Create the doubly linked list:
# 4<->4<->4<->4<->6<->8<->8<->10<->12<->12
head = push(head, 12)
head = push(head, 12)
head = push(head, 10)
head = push(head, 8)
head = push(head, 8)
head = push(head, 6)
head = push(head, 4)
head = push(head, 4)
head = push(head, 4)
head = push(head, 4)

print( "Original doubly linked list:")
printList(head)

# remove duplicate nodes
head = removeDuplicates(head)

print("\nDoubly linked list after removing duplicates:")
printList(head)

# This code is contributed by Arnab Kundu

C#

/* C# implementation to remove duplicates from a
sorted doubly linked list */
using System;

public class removeDuplicatesFromSortedList
{

    /* function to remove duplicates from a
    sorted doubly linked list */
    public static void removeDuplicates(Node head)
    {
        /* if list is empty */
        if (head == null)
            return;

        Node current = head;

        /* traverse the list till the last node */
        while (current.next != null)
        {

            /* Compare current node with next node */
            if (current.data == current.next.data)

            /* delete the node pointed to by
            'current->next' */
                deleteNode(head, current.next);

            /* else simply move to the next node */
            else
                current = current.next;
        }
    }


    /* Function to delete a node in a Doubly Linked List.
    head_ref --> pointer to head node pointer.
    del --> pointer to node to be deleted. */
    public static void deleteNode(Node head, Node del)
    {
        /* base case */
        if(head == null || del == null)
        {
            return ;
        }

        /* If node to be deleted is head node */
        if(head == del)
        {
            head = del.next;
        }

        /* Change next only if node to be deleted
        is NOT the last node */
        if(del.next != null)
        {
            del.next.prev = del.prev;
        }

        /* Change prev only if node to be deleted
        is NOT the first node */
        if (del.prev != null)
            del.prev.next = del.next;

    }


    /* Function to insert a node at the beginning
    of the Doubly Linked List */
    public static Node push(Node head, int data)
    {
        /* allocate node */
        Node newNode = new Node(data);

        /* since we are adding at the beginning,
        prev is always NULL */
        newNode.prev = null;

        /* link the old list of the new node */
        newNode.next = head;

        /* change prev of head node to new node */
        if(head != null)
        {
            head.prev = newNode;
        }
        head = newNode;
        return head;
    }

    /* Function to print nodes in a given doubly linked list */
    public static void printList(Node head)
    {
        if (head == null)
            Console.WriteLine("Doubly Linked list empty");

        while (head != null)
        {
            Console.Write(head.data + " ") ;
            head = head.next;
        }
    }

    // Driver code
    public static void Main(String []args)
    {
        Node head = null;
        head = push(head, 12);
        head = push(head, 12);
        head = push(head, 10);
        head = push(head, 8);
        head = push(head, 8);
        head = push(head, 6);
        head = push(head, 4);
        head = push(head, 4);
        head = push(head, 4);
        head = push(head, 4);

        Console.WriteLine("Original doubly linked list:");
        printList(head);

        /* remove duplicate nodes */
        removeDuplicates(head);
        Console.WriteLine("\nDoubly linked list after" +
                            " removing duplicates:");
        printList(head);
    }
}

public class Node
{
    public int data;
    public Node next,prev;

    public Node(int data)
    {
        this.data = data;
        next = null;
        prev = null;
    }
}

// This code is contributed by 29AjayKumar.

Javascript

<script>
/* javascript implementation to remove duplicates from a
   sorted doubly linked list */

    class Node {
            constructor(val){
            this.data = val;
            this.prev = null;
            this.next = null;
        }
    }
    /*
     * function to remove duplicates from a sorted doubly linked list
     */
    function removeDuplicates(head) {
        /* if list is empty */
        if (head == null)
            return;

        var current = head;

        /* traverse the list till the last node */
        while (current.next != null) {
            /* Compare current node with next node */
            if (current.data == current.next.data)
                /*
                 * delete the node pointed to by ' current->next'
                 */
                deleteNode(head, current.next);

            /* else simply move to the next node */
            else
                current = current.next;
        }

    }

    /*
     * Function to delete a node in a Doubly Linked List. head_ref --> pointer to
     * head node pointer. del --> pointer to node to be deleted.
     */
    function deleteNode(head,  del) {
        /* base case */
        if (head == null || del == null) {
            return;
        }
        /* If node to be deleted is head node */
        if (head == del) {
            head = del.next;
        }
        /*
         * Change next only if node to be deleted is NOT the last node
         */
        if (del.next != null) {
            del.next.prev = del.prev;
        }
        /*
         * Change prev only if node to be deleted is NOT the first node
         */
        if (del.prev != null)
            del.prev.next = del.next;

    }

    /*
     * Function to insert a node at the beginning of the Doubly Linked List
     */
    function push(head , data) {
        /* allocate node */
        var newNode = new Node(data);
        /*
         * since we are adding at the beginning, prev is always NULL
         */
        newNode.prev = null;
        /* link the old list of the new node */
        newNode.next = head;
        /* change prev of head node to new node */
        if (head != null) {
            head.prev = newNode;
        }
        head = newNode;
        return head;
    }

    /* Function to print nodes in a given doubly linked list */
    function printList(head) {
        if (head == null)
            document.write("Doubly Linked list empty");

        while (head != null) {
            document.write(head.data + " ");
            head = head.next;
        }
    }


        var head = null;
        head = push(head, 12);
        head = push(head, 12);
        head = push(head, 10);
        head = push(head, 8);
        head = push(head, 8);
        head = push(head, 6);
        head = push(head, 4);
        head = push(head, 4);
        head = push(head, 4);
        head = push(head, 4);

        document.write("Original Doubly linked list<br/>");
        printList(head);

        /* remove duplicate nodes */
        removeDuplicates(head);
        document.write("<br/>Doubly linked list after removing duplicates:<br/>");
        printList(head);


// This code contributed by gauravrajput1
</script>

Output

Original Doubly linked list:n4 4 4 4 6 8 8 10 12 12 
Doubly linked list after removing duplicates:n4 6 8 10 12 

Time Complexity: O(n)
Auxiliary Space: O(1) since using constant space for pointers

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