Remove duplicates from a sorted linked list

Write a function which takes a list sorted in non-decreasing order and deletes any duplicate nodes from the list. The list should only be traversed once. 
For example if the linked list is 11->11->11->21->43->43->60 then removeDuplicates() should convert the list to 11->21->43->60. 

Algorithm: 
Traverse the list from the head (or start) node. While traversing, compare each node with its next node. If data of next node is same as current node then delete the next node. Before we delete a node, we need to store next pointer of the node 

Implementation: 
Functions other than removeDuplicates() are just to create a linked list and test removeDuplicates(). 

C++

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/* C++ Program to remove duplicates from a sorted linked list */
#include <bits/stdc++.h>
using namespace std;
  
/* Link list node */
class Node 
    public:
    int data; 
    Node* next; 
}; 
  
/* The function removes duplicates from a sorted list */
void removeDuplicates(Node* head) 
    /* Pointer to traverse the linked list */
    Node* current = head; 
  
    /* Pointer to store the next pointer of a node to be deleted*/
    Node* next_next; 
      
    /* do nothing if the list is empty */
    if (current == NULL) 
    return
  
    /* Traverse the list till last node */
    while (current->next != NULL) 
    
    /* Compare current node with next node */
    if (current->data == current->next->data) 
    
        /* The sequence of steps is important*/        
        next_next = current->next->next; 
        free(current->next); 
        current->next = next_next; 
    
    else /* This is tricky: only advance if no deletion */
    
        current = current->next; 
    
    
  
/* UTILITY FUNCTIONS */
/* Function to insert a node at the beginging of the linked list */
void push(Node** head_ref, int new_data) 
    /* allocate node */
    Node* new_node = new Node();
              
    /* put in the data */
    new_node->data = new_data; 
                  
    /* link the old list off the new node */
    new_node->next = (*head_ref);     
          
    /* move the head to point to the new node */
    (*head_ref) = new_node; 
  
/* Function to print nodes in a given linked list */
void printList(Node *node) 
    while (node!=NULL) 
    
        cout<<" "<<node->data; 
        node = node->next; 
    
  
/* Driver program to test above functions*/
int main() 
    /* Start with the empty list */
    Node* head = NULL; 
      
    /* Let us create a sorted linked list to test the functions 
    Created linked list will be 11->11->11->13->13->20 */
    push(&head, 20); 
    push(&head, 13); 
    push(&head, 13); 
    push(&head, 11); 
    push(&head, 11); 
    push(&head, 11);                                     
  
    cout<<"Linked list before duplicate removal "
    printList(head); 
  
    /* Remove duplicates from linked list */
    removeDuplicates(head); 
  
    cout<<"\nLinked list after duplicate removal ";     
    printList(head);             
      
    return 0; 
  
// This code is contributed by rathbhupendra

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C

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/* C Program to remove duplicates from a sorted linked list */
#include<stdio.h>
#include<stdlib.h>
  
/* Link list node */
struct Node
{
    int data;
    struct Node* next;
};
  
/* The function removes duplicates from a sorted list */
void removeDuplicates(struct Node* head)
{
    /* Pointer to traverse the linked list */
    struct Node* current = head;
  
    /* Pointer to store the next pointer of a node to be deleted*/
    struct Node* next_next; 
    
    /* do nothing if the list is empty */
    if (current == NULL) 
       return
  
    /* Traverse the list till last node */
    while (current->next != NULL) 
    {
       /* Compare current node with next node */
       if (current->data == current->next->data) 
       {
           /* The sequence of steps is important*/               
           next_next = current->next->next;
           free(current->next);
           current->next = next_next;  
       }
       else /* This is tricky: only advance if no deletion */
       {
          current = current->next; 
       }
    }
}
  
/* UTILITY FUNCTIONS */
/* Function to insert a node at the beginging of the linked list */
void push(struct Node** head_ref, int new_data)
{
    /* allocate node */
    struct Node* new_node =
            (struct Node*) malloc(sizeof(struct Node));
              
    /* put in the data  */
    new_node->data  = new_data;
                  
    /* link the old list off the new node */
    new_node->next = (*head_ref);     
          
    /* move the head to point to the new node */
    (*head_ref)    = new_node;
}
  
/* Function to print nodes in a given linked list */
void printList(struct Node *node)
{
    while (node!=NULL)
    {
       printf("%d ", node->data);
       node = node->next;
    }
  
/* Driver program to test above functions*/
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;
    
    /* Let us create a sorted linked list to test the functions
     Created linked list will be 11->11->11->13->13->20 */
    push(&head, 20);
    push(&head, 13);
    push(&head, 13);  
    push(&head, 11);
    push(&head, 11);
    push(&head, 11);                                    
  
    printf("\n Linked list before duplicate removal  ");
    printList(head); 
  
    /* Remove duplicates from linked list */
    removeDuplicates(head); 
  
    printf("\n Linked list after duplicate removal ");         
    printList(head);            
    
    return 0;
}

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Java

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// Java program to remove duplicates from a sorted linked list
class LinkedList
{
    Node head;  // head of list
   
    /* Linked list Node*/
    class Node
    {
        int data;
        Node next;
        Node(int d) {data = d; next = null; }
    }
  
    void removeDuplicates()
    {
        /*Another reference to head*/
        Node curr = head;
  
        /* Traverse list till the last node */
        while (curr != null) {
             Node temp = curr;
            /*Compare current node with the next node and 
            keep on deleting them until it matches the current 
            node data */
            while(temp!=null && temp.data==curr.data) {
                temp = temp.next;
            }
            /*Set current node next to the next different 
            element denoted by temp*/
            curr.next = temp;
            curr = curr.next;
        }
    }
                      
    /* Utility functions */
  
    /* Inserts a new Node at front of the list. */
    public void push(int new_data)
    {
        /* 1 & 2: Allocate the Node &
                  Put in the data*/
        Node new_node = new Node(new_data);
   
        /* 3. Make next of new Node as head */
        new_node.next = head;
   
        /* 4. Move the head to point to new Node */
        head = new_node;
    }
  
    /* Function to print linked list */
     void printList()
     {
         Node temp = head;
         while (temp != null)
         {
            System.out.print(temp.data+" ");
            temp = temp.next;
         }  
         System.out.println();
     }
  
     /* Driver program to test above functions */
    public static void main(String args[])
    {
        LinkedList llist = new LinkedList();
        llist.push(20);
        llist.push(13);
        llist.push(13);
        llist.push(11);
        llist.push(11);
        llist.push(11);
          
        System.out.println("List before removal of duplicates");
        llist.printList();
          
        llist.removeDuplicates();
          
        System.out.println("List after removal of elements");
        llist.printList();
    }
/* This code is contributed by Rajat Mishra */    

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Python 3

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# Python3 program to remove duplicate
# nodes from a sorted linked list 
  
# Node class 
class Node: 
  
    # Constructor to initialize 
    # the node object 
    def __init__(self, data): 
        self.data = data 
        self.next = None
  
class LinkedList: 
  
    # Function to initialize head 
    def __init__(self): 
        self.head = None
  
    # Function to insert a new node 
    # at the beginning 
    def push(self, new_data): 
        new_node = Node(new_data) 
        new_node.next = self.head 
        self.head = new_node 
  
    # Given a reference to the head of a 
    # list and a key, delete the first 
    # occurence of key in linked list 
    def deleteNode(self, key): 
          
        # Store head node 
        temp = self.head 
  
        # If head node itself holds the 
        # key to be deleted 
        if (temp is not None): 
            if (temp.data == key): 
                self.head = temp.next
                temp = None
                return
  
        # Search for the key to be deleted, 
        # keep track of the previous node as
        # we need to change 'prev.next' 
        while(temp is not None): 
            if temp.data == key: 
                break
            prev = temp 
            temp = temp.next
  
        # if key was not present in 
        # linked list 
        if(temp == None): 
            return
  
        # Unlink the node from linked list 
        prev.next = temp.next
  
        temp = None
  
    # Utility function to print the 
    # linked LinkedList 
    def printList(self): 
        temp = self.head 
        while(temp): 
            print(temp.data , end = ' ')
            temp = temp.next
      
    # This function removes duplicates 
    # from a sorted list         
    def removeDuplicates(self):
        temp = self.head
        if temp is None:
            return
        while temp.next is not None:
            if temp.data == temp.next.data:
                new = temp.next.next
                temp.next = None
                temp.next = new
            else:
                temp = temp.next
        return self.head
  
# Driver Code 
llist = LinkedList() 
  
llist.push(20
llist.push(13
llist.push(13)
llist.push(11)
llist.push(11)
llist.push(11)
print ("Created Linked List: ")
llist.printList() 
print()
print("Linked List after removing"
             "duplicate elements:")
llist.removeDuplicates()
llist.printList() 
  
# This code is contributed by 
# Dushyant Pathak.

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C#

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// C# program to remove duplicates
// from a sorted linked list
using System;
      
public class LinkedList
{
    Node head; // head of list
  
    /* Linked list Node*/
    class Node
    {
        public int data;
        public Node next;
        public Node(int d) 
        {
            data = d; next = null;
        }
    }
  
    void removeDuplicates()
    {
        /*Another reference to head*/
        Node current = head;
  
        /* Pointer to store the next 
        pointer of a node to be deleted*/
        Node next_next;
  
        /* do nothing if the list is empty */
        if (head == null
            return;
  
        /* Traverse list till the last node */
        while (current.next != null
        {
  
            /*Compare current node with the next node */
            if (current.data == current.next.data) 
            {
                next_next = current.next.next;
                current.next = null;
                current.next = next_next;
            }
            else // advance if no deletion
                current = current.next;
        }
    }
                      
    /* Utility functions */
  
    /* Inserts a new Node at front of the list. */
    public void push(int new_data)
    {
        /* 1 & 2: Allocate the Node &
                Put in the data*/
        Node new_node = new Node(new_data);
  
        /* 3. Make next of new Node as head */
        new_node.next = head;
  
        /* 4. Move the head to point to new Node */
        head = new_node;
    }
  
    /* Function to print linked list */
    void printList()
    {
        Node temp = head;
        while (temp != null)
        {
            Console.Write(temp.data+" ");
            temp = temp.next;
        
        Console.WriteLine();
    }
  
    /* Driver code */
    public static void Main(String []args)
    {
        LinkedList llist = new LinkedList();
        llist.push(20);
        llist.push(13);
        llist.push(13);
        llist.push(11);
        llist.push(11);
        llist.push(11);
          
        Console.WriteLine("List before removal of duplicates");
        llist.printList();
          
        llist.removeDuplicates();
          
        Console.WriteLine("List after removal of elements");
        llist.printList();
    }
  
/* This code is contributed by 29AjayKumar */

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Output

Linked list before duplicate removal  11 11 11 13 13 20
Linked list after duplicate removal  11 13 20



Time Complexity: O(n) where n is the number of nodes in the given linked list.



Recursive Approach :  

C++

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/* C++ Program to remove duplicates
from a sorted linked list */
#include <bits/stdc++.h>
using namespace std;
  
/* Link list node */
class Node 
    public:
    int data; 
    Node* next; 
}; 
  
/* The function removes duplicates 
from a sorted list */
void removeDuplicates(Node* head) 
    /* Pointer to store the pointer of a node to be deleted*/
    Node* to_free; 
      
    /* do nothing if the list is empty */
    if (head == NULL) 
        return
  
    /* Traverse the list till last node */
    if (head->next != NULL) 
    
          
        /* Compare head node with next node */
        if (head->data == head->next->data) 
        
            /* The sequence of steps is important.
              to_free pointer stores the next of head
             pointer which is to be deleted.*/    
            to_free = head->next; 
        head->next = head->next->next;
        free(to_free);
        removeDuplicates(head);
        
        else /* This is tricky: only 
        advance if no deletion */
        
            removeDuplicates(head->next);
        
    
  
/* UTILITY FUNCTIONS */
/* Function to insert a node at the
beginging of the linked list */
void push(Node** head_ref, int new_data) 
    /* allocate node */
    Node* new_node = new Node();
              
    /* put in the data */
    new_node->data = new_data; 
                  
    /* link the old list off the new node */
    new_node->next = (*head_ref);     
          
    /* move the head to point to the new node */
    (*head_ref) = new_node; 
  
/* Function to print nodes 
in a given linked list */
void printList(Node *node) 
    while (node!=NULL) 
    
        cout<<" "<<node->data; 
        node = node->next; 
    
  
/* Driver code*/
int main() 
    /* Start with the empty list */
    Node* head = NULL; 
      
    /* Let us create a sorted linked
    list to test the functions 
    Created linked list will be 
    11->11->11->13->13->20 */
    push(&head, 20); 
    push(&head, 13); 
    push(&head, 13); 
    push(&head, 11); 
    push(&head, 11); 
    push(&head, 11);                                     
  
    cout<<"Linked list before duplicate removal "
    printList(head); 
  
    /* Remove duplicates from linked list */
    removeDuplicates(head); 
  
    cout<<"\nLinked list after duplicate removal ";     
    printList(head);             
      
    return 0; 
// This code is contributed by Ashita Gupta

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C

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/* C recursive Program to remove duplicates from a sorted linked list */
#include<stdio.h>
#include<stdlib.h>
  
/* Link list node */
struct Node
{
    int data;
    struct Node* next;
};
/* UTILITY FUNCTIONS */
/* Function to insert a node at the beginging of the linked list */
void push(struct Node** head_ref, int new_data)
{
    /* allocate node */
    struct Node* new_node =
            (struct Node*) malloc(sizeof(struct Node));
              
    /* put in the data  */
    new_node->data  = new_data;
                  
    /* link the old list off the new node */
    new_node->next = (*head_ref);     
          
    /* move the head to point to the new node */
    (*head_ref)    = new_node;
}
  
/* Function to print nodes in a given linked list */
void printList(struct Node *node)
{
    while (node!=NULL)
    {
       printf("%d ", node->data);
       node = node->next;
    }
  
 Node* deleteDuplicates(Node* head) {
        if (head == nullptr) return nullptr;
        if (head->next == nullptr) return head;
  
        if (head->data == head->next->data) {
            Node *tmp;
            // If find next element duplicate, preserve the next pointer to be deleted, 
            // skip it, and then delete the stored one. Return head
            tmp = head->next;
            head->next = head->next->next;
            free(tmp);
            return deleteDuplicates(head);
        }
  
        else {
  
            // if doesn't find next element duplicate, leave head 
            // and check from next element
            head->next = deleteDuplicates(head->next);
            return head;
        }
    }
  
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;
    
    /* Let us create a sorted linked list to test the functions
     Created linked list will be 11->11->11->13->13->20 */
    push(&head, 20);
    push(&head, 13);
    push(&head, 13);  
    push(&head, 11);
    push(&head, 11);
    push(&head, 11);                                    
  
    printf("\n Linked list before duplicate removal  ");
    printList(head); 
  
    /* Remove duplicates from linked list */
    head = deleteDuplicates(head); 
  
    printf("\n Linked list after duplicate removal ");         
    printList(head);            
    
    return 0;
}
/* This code is contributed by Yogesh shukla */   

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Java

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// Java Program to remove duplicates
// from a sorted linked list 
class GFG
{
/* Link list node */
static class Node 
    int data; 
    Node next; 
}; 
  
// The function removes duplicates
// from a sorted list 
static Node removeDuplicates(Node head) 
    /* Pointer to store the pointer
    of a node to be deleted*/
    Node to_free; 
      
    /* do nothing if the list is empty */
    if (head == null
        return null
  
    /* Traverse the list till last node */
    if (head.next != null
    
          
        /* Compare head node with next node */
        if (head.data == head.next.data) 
        
            /* The sequence of steps is important.
            to_free pointer stores the next of head
            pointer which is to be deleted.*/
            to_free = head.next; 
            head.next = head.next.next;
            removeDuplicates(head);
        
          
        /* This is tricky: only advance if no deletion */
        else 
        
            removeDuplicates(head.next);
        
    
    return head;
  
/* UTILITY FUNCTIONS */
/* Function to insert a node at the beginging
of the linked list */
static Node push(Node head_ref,
                 int new_data) 
    /* allocate node */
    Node new_node = new Node();
              
    /* put in the data */
    new_node.data = new_data; 
                  
    /* link the old list off the new node */
    new_node.next = (head_ref);     
          
    /* move the head to point to the new node */
    (head_ref) = new_node; 
    return head_ref;
  
/* Function to print nodes in a given linked list */
static void printList(Node node) 
    while (node != null
    
        System.out.print(" " + node.data); 
        node = node.next; 
    
  
/* Driver code*/
public static void main(String args[])
    /* Start with the empty list */
    Node head = null
      
    /* Let us create a sorted linked list
    to test the functions 
    Created linked list will be 11.11.11.13.13.20 */
    head = push(head, 20); 
    head = push(head, 13); 
    head = push(head, 13); 
    head = push(head, 11); 
    head = push(head, 11); 
    head = push(head, 11);                                     
  
    System.out.println("Linked list before"
                      " duplicate removal "); 
    printList(head); 
  
    /* Remove duplicates from linked list */
    head = removeDuplicates(head); 
  
    System.out.println("\nLinked list after"
                       " duplicate removal ");     
    printList(head);             
}
}  
  
// This code is contributed by Arnab Kundu

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Python3

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# Python3 Program to remove duplicates
# from a sorted linked list 
import math
  
# Link list node 
class Node: 
    def __init__(self,data): 
        self.data = data 
        self.next = None
  
# The function removes duplicates 
# from a sorted list 
def removeDuplicates(head): 
      
    # Pointer to store the pointer of a node 
    # to be deleted to_free 
      
    # do nothing if the list is empty 
    if (head == None): 
        return
  
    # Traverse the list till last node 
    if (head.next != None): 
          
        # Compare head node with next node 
        if (head.data == head.next.data): 
              
            # The sequence of steps is important. 
            # to_free pointer stores the next of head 
            # pointer which is to be deleted. 
            to_free = head.next
            head.next = head.next.next
              
            # free(to_free) 
            removeDuplicates(head) 
          
        # This is tricky: only advance if no deletion
        else
            removeDuplicates(head.next
          
    return head
  
# UTILITY FUNCTIONS 
# Function to insert a node at the 
# beginging of the linked list 
def push(head_ref, new_data): 
      
    # allocate node 
    new_node = Node(new_data) 
              
    # put in the data 
    new_node.data = new_data 
                  
    # link the old list off the new node 
    new_node.next = head_ref     
          
    # move the head to point to the new node 
    head_ref = new_node
    return head_ref
  
# Function to print nodes in a given linked list 
def printList(node): 
    while (node != None): 
        print(node.data, end = " "
        node = node.next
      
# Driver code
if __name__=='__main__'
  
    # Start with the empty list 
    head = None
      
    # Let us create a sorted linked list
    # to test the functions 
    # Created linked list will be 11.11.11.13.13.20 
    head = push(head, 20
    head = push(head, 13
    head = push(head, 13
    head = push(head, 11
    head = push(head, 11
    head = push(head, 11)                                 
  
    print("Linked list before duplicate removal ",
                                         end = "") 
    printList(head) 
  
    # Remove duplicates from linked list 
    removeDuplicates(head) 
  
    print("\nLinked list after duplicate removal ",
                                          end = "") 
    printList(head)         
      
# This code is contributed by Srathore

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C#

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// C# Program to remove duplicates
// from a sorted linked list 
using System;
      
class GFG
{
/* Link list node */
public class Node 
    public int data; 
    public Node next; 
}; 
  
// The function removes duplicates
// from a sorted list 
static Node removeDuplicates(Node head) 
    /* Pointer to store the pointer
    of a node to be deleted*/
    Node to_free; 
      
    /* do nothing if the list is empty */
    if (head == null
        return null
  
    /* Traverse the list till last node */
    if (head.next != null
    
          
        /* Compare head node with next node */
        if (head.data == head.next.data) 
        
            /* The sequence of steps is important.
            to_free pointer stores the next of head
            pointer which is to be deleted.*/
            to_free = head.next; 
            head.next = head.next.next;
            removeDuplicates(head);
        
          
        /* This is tricky: only advance if no deletion */
        else
        
            removeDuplicates(head.next);
        
    
    return head;
  
/* UTILITY FUNCTIONS */
/* Function to insert a node at the beginging
of the linked list */
static Node push(Node head_ref,
                 int new_data) 
    /* allocate node */
    Node new_node = new Node();
              
    /* put in the data */
    new_node.data = new_data; 
                  
    /* link the old list off the new node */
    new_node.next = (head_ref);     
          
    /* move the head to point to the new node */
    (head_ref) = new_node; 
    return head_ref;
  
/* Function to print nodes in 
a given linked list */
static void printList(Node node) 
    while (node != null
    
        Console.Write(" " + node.data); 
        node = node.next; 
    
  
// Driver code
public static void Main(String []args)
    /* Start with the empty list */
    Node head = null
      
    /* Let us create a sorted linked list
    to test the functions 
    Created linked list will be 11.11.11.13.13.20 */
    head = push(head, 20); 
    head = push(head, 13); 
    head = push(head, 13); 
    head = push(head, 11); 
    head = push(head, 11); 
    head = push(head, 11);                                     
  
    Console.Write("Linked list before"
                  " duplicate removal "); 
    printList(head); 
  
    /* Remove duplicates from linked list */
    head = removeDuplicates(head); 
  
    Console.Write("\nLinked list after"
                  " duplicate removal ");     
    printList(head);             
}
}
  
// This code is contributed by PrinciRaj1992

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Output

Linked list before duplicate removal  11 11 11 13 13 20
Linked list after duplicate removal  11 13 20



Another Approach: Create a pointer that will point towards the first occurrence of every element and another pointer temp which will iterate to every element and when the value of the previous pointer is not equal to the temp pointer, we will set the pointer of the previous pointer to the first occurrence of another node.

Below is the implementation of the above approach:

Java

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// Java program to remove duplicates
// from a sorted linked list
class LinkedList
{
    // head of list
    Node head;
   
    // Linked list Node
    class Node
    {
        int data;
        Node next;
        Node(int d) {
          data = d; 
          next = null
        }
    }
  
    // Function to remove duplicates
    // from the given linked list
    void removeDuplicates()
    {
        // Two references to head
        // temp will iterate to the
        // whole Linked List
        // prev will point towards 
        // the first occurence of every element
        Node temp = head,prev=head;
  
        // Traverse list till the last node
        while (temp != null) {
             
           // Compare values of both pointers
           if(temp.data!=prev.data)
           {
             /* if the value of prev is 
             not equal to the value of 
             temp that means there are no
             more occruences of the prev data.
             So we can set the next of 
             prev to the temp node.*/
             prev.next=temp;
             prev=temp;
           }
            /*Set the temp to the next node*/
            temp=temp.next;
        }
      /*This is the edge case if there
      are more than one occurrences 
      of the last element*/
      if(prev!=temp){
            prev.next=null;
        }
    }
                      
    /* Utility functions */
  
    /* Inserts a new Node at front of the list. */
    public void push(int new_data)
    {
        /* 1 & 2: Allocate the Node &
                  Put in the data*/
        Node new_node = new Node(new_data);
   
        /* 3. Make next of new Node as head */
        new_node.next = head;
   
        /* 4. Move the head to point to new Node */
        head = new_node;
    }
  
    /* Function to print linked list */
     void printList()
     {
         Node temp = head;
         while (temp != null)
         {
            System.out.print(temp.data+" ");
            temp = temp.next;
         }  
         System.out.println();
     }
  
     /* Driver program to test above functions */
    public static void main(String args[])
    {
        LinkedList llist = new LinkedList();
        llist.push(20);
        llist.push(13);
        llist.push(13);
        llist.push(11);
        llist.push(11);
        llist.push(11);
          
        System.out.print("List before ");
        System.out.println("removal of duplicates");
        llist.printList();
          
        llist.removeDuplicates();
          
        System.out.println("List after removal of elements");
        llist.printList();
    }
/* This code is contributed by Arshita */    

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Python3

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# Python3 program to remove duplicates 
# from a sorted linked list  
import math 
    
# Link list node  
class Node:  
      
    def __init__(self, data):
          
        self.data = data  
        self.next = None
    
# The function removes duplicates  
# from the given linked list 
def removeDuplicates(head):  
      
    # Do nothing if the list consist of 
    # only one element or empty  
    if (head == None and 
        head.next == None):
        return
      
    # Consturct a pointer 
    # pointing towards head
    current = head
      
    # Initalise a while loop till the 
    # second last node of the linkedlist 
    while (current.next):
          
        # If the data of current and next
        # node is equal we will skip the
        # node between them
        if current.data == current.next.data:
            current.next = current.next.next
              
        # If the data of current and 
        # next node is different move
        # the pointer to the next node
        else:
            current = current.next
      
    return
    
# UTILITY FUNCTIONS  
# Function to insert a node at the  
# beginging of the linked list  
def push(head_ref, new_data):  
      
    # Allocate node  
    new_node = Node(new_data)  
                
    # Put in the data  
    new_node.data = new_data  
                    
    # Link the old list off 
    # the new node  
    new_node.next = head_ref      
            
    # Move the head to point
    # to the new node  
    head_ref = new_node 
      
    return head_ref 
    
# Function to print nodes 
# in a given linked list  
def printList(node):  
      
    while (node != None):  
        print(node.data, end = " ")  
        node = node.next
        
# Driver code 
if __name__=='__main__':  
    
    head = None
      
    head = push(head, 20)  
    head = push(head, 13)  
    head = push(head, 13)  
    head = push(head, 11)  
    head = push(head, 11)  
    head = push(head, 11)                                  
    
    print("List before removal of "  
          "duplicates ", end = "")  
    printList(head)  
    
    removeDuplicates(head)  
    
    print("\nList after removal of "  
          "elements ", end = "")  
            
    printList(head)          
        
# This code is contributed by MukulTomar

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Output

List before removal of duplicates
11 11 11 13 13 20 
List after removal of elements
11 13 20 




Related Article : 
Remove all occurrences of duplicates from a sorted Linked List
References: 
cslibrary.stanford.edu/105/LinkedListProblems.pdf
 

 

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