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Remove all the occurrences of an element from a list in Python

  • Difficulty Level : Basic
  • Last Updated : 09 Apr, 2022

The task is to perform the operation of removing all the occurrences of a given item/element present in a list. Examples :

Input : 1 1 2 3 4 5 1 2 1 Output : 2 3 4 5 2 Explanation : The input list is [1, 1, 2, 3, 4, 5, 1, 2] and the item to be removed is 1. After removing the item, the output list is [2, 3, 4, 5, 2] Input : 5 6 7 8 9 10 7 Output : 5 6 8 9 10

In this article, we shall see how to execute this task in 3 ways :

  1. Using list comprehension
  2. Using filter() and __ne__
  3. Using remove()

Method 1 : Using list comprehension The list comprehension can be used to perform this task in which we just check for a match and reconstruct the list without the target element. We can create a sublist of those elements in the list that satisfies a certain condition. 

Python3




# Python 3 code to demonstrate
# the removal of all occurrences of a
# given item using list comprehension
 
def remove_items(test_list, item):
     
    # using list comprehension to perform the task
    res = [i for i in test_list if i != item]
 
    return res
 
# driver code
if __name__=="__main__":
     
    # initializing the list
    test_list = [1, 3, 4, 6, 5, 1]
 
    # the item which is to be removed
    item = 1
 
    # printing the original list
    print ("The original list is : " + str(test_list))
 
    # calling the function remove_items()
    res = remove_items(test_list, item)
 
    # printing result
    print ("The list after performing the remove operation is : " + str(res))

Output

The original list is : [1, 3, 4, 6, 5, 1]
The list after performing the remove operation is : [3, 4, 6, 5]

Method 2 : Using filter() and __ne__ We filter those items of the list which are not equal __ne__ to the item. 

Python3




# Python 3 code to demonstrate
# the removal of all occurrences of
# a given item using filter() and __ne__
 
def remove_items(test_list, item):
     
    # using filter() + __ne__ to perform the task
    res = list(filter((item).__ne__, test_list))
 
    return res
 
# driver code
if __name__=="__main__":
     
    # initializing the list
    test_list = [1, 3, 4, 6, 5, 1]
 
    # the item which is to be removed
    item = 1
 
    # printing the original list
    print ("The original list is : " + str(test_list))
 
    # calling the function remove_items()
    res = remove_items(test_list, item)
 
    # printing result
    print ("The list after performing the remove operation is : " + str(res))

Output

The original list is : [1, 3, 4, 6, 5, 1]
The list after performing the remove operation is : [3, 4, 6, 5]

Method 3 : Using remove() In this method, we iterate through each item in the list, and when we find a match for the item to be removed, we will call remove() function on the list. 

Python3




# Python 3 code to demonstrate
# the removal of all occurrences of
# a given item using remove()
 
def remove_items(test_list, item):
     
    # remove the item for all its occurrences
    c = test_list.count(item)
    for i in range(c):
            test_list.remove(item)
 
    return test_list
 
# driver code
if __name__=="__main__":
     
    # initializing the list
    test_list = [1, 3, 4, 6, 5, 1]
 
    # the item which is to be removed
    item = 1
 
    # printing the original list
    print ("The original list is :" + str(test_list))
 
    # calling the function remove_items()
    res = remove_items(test_list, item)
 
    # printing result
    print ("The list after performing the remove operation is :" + str(res))

Output

The original list is : [1, 3, 4, 6, 5, 1]
The list after performing the remove operation is : [3, 4, 6, 5]

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