This function is also used to return the remainder(modulus) of 2 floating point numbers mentioned in its arguments.The quotient computed is rounded.
remainder = number – rquot * denom
Where rquot is the result of: number/denom, rounded toward the nearest integral value (with halfway cases rounded toward the even number).
Syntax :
double remainder(double a, double b)
float remainder(float a, float b)
long double remainder(long double a, long double b)
Parameter:
a and b are the values
of numerator and denominator.
Return:
The remainder() function returns the floating
point remainder of numerator/denominator
rounded to nearest.
Time Complexity: O(1)
Space Complexity: O(1)
Error or Exception : It is mandatory to give both the arguments otherwise it will give error – no matching function for call to ‘remainder()’ like this.
# CODE 1
CPP
#include <cmath>
#include <iostream>
using namespace std;
int main()
{
double a, b;
double answer;
a = 50.35;
b = -4.1;
answer = remainder(a, b);
cout << "Remainder of " << a << "/" << b << " is " << answer << endl;
a = 16.80;
b = 3.5;
answer = remainder(a, b);
cout << "Remainder of " << a << "/" << b << " is " << answer << endl;
a = 16.80;
b = 0;
answer = remainder(a, b);
cout << "Remainder of " << a << "/" << b << " is " << answer << endl;
return 0;
}
|
OUTPUT :
Remainder of 50.35/-4.1 is 1.15
Remainder of 16.8/3.5 is -0.7
Remainder of 16.8/0 is -nan
# CODE 2
CPP
#include <cmath>
#include <iostream>
using namespace std;
int main()
{
int a = 50;
double b = 41.35, answer;
answer = remainder(a, b);
cout << "Remainder of " << a << "/" << b << " = " << answer << endl;
return 0;
}
|
OUTPUT :
Remainder of 50/41.35 = 8.65
Last Updated :
06 Feb, 2023
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