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Reduction Formula

Last Updated : 26 Dec, 2023
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Integration involving higher-order terms is difficult to handle and solve. So, to simplify the solving process of higher-order terms and get rid of the lengthy-expression solving process of higher-order degree terms – Integration processes can be simplified by using Reduction Formulas.

The reduction formula comes to the rescue to simplify the higher-order terms. Integration of higher-order terms consisting of logarithmic, algebraic, and trigonometric functions are simplified by reduction formulas. n the Reduction formula, higher-order degree terms are given a degree n. Reduction formulas with degree n are derived from the integration base formulas. All rules of integration apply to these reduction formulas as well.

Reduction Formula for different expressions are listed below:

Reduction Formulas for Logarithmic expressions

∫ lognx dx = xlognx -n∫logn-1x dx

∫xnlogmx dx = xn+1logmx/ n+1 – m/n+1 .∫xnlogm-1x dx

Reduction Formulas for Algebraic expressions

∫ xn/mxn+k dx = x/m – y/k∫ 1/mxn+k dx

Reduction Formulas for Trigonometric expressions

∫ sinnx dx = -1/n sinn-1x. cosx + n-1/n∫sinn-2x dx

∫ cosnx dx = 1/n cosn-1x.sinx + n-1/n∫cosn-2x dx

∫ tannx dx = 1/n-1 tann-1x – ∫tann-2x dx

∫ sinnx.cosmx dx = sinn+1x. cosm-1x / n+m   +.   m-1/n+m∫ sinnx.cosm-2x dx

Reduction Formulas for Exponential expressions

∫ xnemx dx = 1/m. xnemx – n/m ∫xn-1emx dx

Reduction Formulas for Reduction Formulas for Inverse Trigonometric expressions 

∫ xn arc sinx dx = (xn+1/n+1) arc sinx – (1/n+1)∫(xn+1/(1-x2)1/2) dx

∫ xn arc cosx dx = (xn+1/n+1) arc cosx + (1/n+1)∫(xn+1/(1-x2)1/2) dx

∫ xn arc tanx dx = (xn+1/n+1) arc tanx – (1/n+1)∫(xn+1/(1+x2)1/2) dx

Sample Problems

Problem1: Simplify ∫ x2.log2x dx

Solution:

Using formula ∫xnlogmx dx = xn+1logmx/ n+1 – m/n+1 .∫xnlogm-1x dx

n=2, m=2

∫ x2.log2x dx = x3log2x/3 – 2/3.∫x2logx dx

= x3log2x/3 – 2/3.∫x2logx dx

= x3log2x/3 – 2/3. (x3.logx/3 – 1/3. ∫x2 dx)

= x3log2x/3 – 2/3. (x3.logx/3 – 1/3. x3/3)

= x3log2x/3 – 2/9. x3.logx – 2/27. x3

Problem2: Simplify ∫ tan5x dx

Solution:  

Using formula ∫ tannx dx = 1/n-1 tann-1x – ∫tann-2x dx

∫ tan5x dx = 1/4 tan4x – ∫tan3x dx

= 1/4 tan4x – ∫tan3x dx

= 1/4 tan4x – ( 1/2tan2x – ∫ tanx dx)

= 1/4 tan4x – 1/2tan2x  + 1/2. ln secx

Problem3: Simplify ∫ xe3x dx

Solution:  

Using formula ∫ xnemx dx = 1/m. xnemx – n/m ∫xn-1emx dx

= 1/3.xe3x – n/m ∫e3x dx

= 1/3.xe3x – n/m . 3. e3x dx

Problem4: Simplify ∫ log2x dx 

Solution:  

Using ∫ lognx dx = xlognx -n∫logn-1x dx

∫ log2x dx = 2log2x -2∫logx dx

= 2log2x -2∫logx dx

= 2log2x -2xlogx

Problem5: Simplify ∫ tan2x dx 

Solution: 

Using ∫ tannx dx = 1/n-1 tann-1x – ∫tann-2x dx

n=2

∫ tan2x dx = tanx – ∫tan0x dx

∫ tan2x dx = tanx – x



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