Given a string str of lowercase characters. The task is to count the number of deletions required to reduce the string to its shortest length. In each delete operation, you can select a pair of adjacent lowercase letters that match, and then delete them. The task is to print the count of deletions done.
Input: str = "aaabccddd" Output: 3 Following are sequence of operations: aaabccddd -> abccddd -> abddd -> abd Input: str = "aa" Output: 1
- Initialize count = 1 initially.
- Iterate for every character, increase count if s[i]==s[i-1].
- If s[i]!=s[i-1], add count/2 to the number of steps, and re-initialize count to 1.
If s[i]!=s[i-1], then the number of deletions is increased by count/2. If the count is even, number of pairs will be count/2. If count is odd, then the number of deletions will be (count-1)/2 which is the same as (int)count/2.
Below is the implementation of the above approach:
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