Given an integer area, the task is to find the length and breadth of a rectangle with the given area such that the difference between the length and the breadth is minimum possible.
Input: area = 99
Output: l = 11, b = 9
All possible rectangles (l, b) are (99, 1), (33, 3) and (11, 9)
And the one with the minimum |l – b| is (11, 9)
Input: area = 25
Output: l = 5, b = 5
Approach: The task is to find two integers l and b such that l * b = area and |l – b| is as minimum as possible. Factorization can be used to solve the problem but doing just simple factorization from 1 to N will take a long time to get the required output for larger values of N.
To overcome this, just iterate upto . Considering < l ≤ N, then for all values of l, b will always be < .
Below is the implementation of the above approach:
l = 11, b = 9
l = 11, b = 9
Time Complexity: O()
Below is simple implementation.
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