Given two binary strings s and t. The task is to rearrange the string s in such a way that the occurrence of string t as a sub-string in s is maximum.
Input: s = “101101”, t = “110”
Input: s = “10”, t = “11100”
Input: s = “11000100”, t = “101”
Approach: If we can not make any occurrence of string t in string s then output any permutation of s. Otherwise, start the rearranged string with t. Now we will make the next occurrence of string t in string s as left as possible in order maximize the count of occurrence. To achieve this we will find the largest suffix of string t that matches the prefix of string t
of the same length. It can be found by Prefix Function, Z-Function or Hashes.
Below is the implementation of the above approach:
- Rearrange the string to maximize the number of palindromic substrings
- Find indices of all occurrence of one string in other
- Program to count occurrence of a given character in a string
- Minimize the length of string by removing occurrence of only one character
- Count occurrence of a given character in a string using Stream API in Java
- Rearrange a string so that all same characters become d distance away
- Rearrange characters in a string such that no two adjacent are same
- Rearrange a string so that all same characters become atleast d distance away
- Rearrange a string in sorted order followed by the integer sum
- Check if it is possible to rearrange a binary string with alternate 0s and 1s
- Rearrange characters in a string such that no two adjacent are same using hashing
- Rearrange a binary string as alternate x and y occurrences
- Generate two output strings depending upon occurrence of character in input string.
- Rearrange a string in the form of integer sum followed by the minimized character
- Rearrange the given string such that all prime multiple indexes have same character
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