Ratio and Proportion
Question 1 |
Present age of Vinod and Ashok are in ratio of 3:4 respectively. After 5 years, the ratio of their ages becomes 7:9 respectively. What is Ashokโs present age is ?
40 years | |
28 years | |
32 years | |
36 years |
Discuss it
Question 1 Explanation:
Let the present age of Vinod and Ashok be 3x years and 4x years respectively.
Then (3x+5) / (4x+5) = 7 / 9 โด 9(3x + 5) = 7(4x + 5) โด 27x + 45 = 28x + 35 โด x = 10 โด Ashokโs present age = 4x = 40 years
Question 2 |
At present, the ratio between ages of Ram and Shyam is 6:5 respectively. After 7 years, Shyamโs age will be 32 years. What is the present age of Ram?
32 | |
40 | |
30 | |
36 |
Discuss it
Question 2 Explanation:
Let the present age of Ram and Shyam be 6x years and 5x years respectively. Then 5x + 7 = 32 โด 5x = 25 โด x = 5 โด Present age of Ram = 6x = 30 years
Question 3 |
The present ages of A, B and C are in proportions 4:5:9. Nine years ago, sum of their ages was 45 years. Find their present ages in years
15,20,35 | |
20,24,36 | |
20,25,45 | |
16,20,36 |
Discuss it
Question 3 Explanation:
Let the current ages of A, B and C be ax years, 5x years and 9x respectively.
Then (4x-9) + (5x-9) + (9x-9) =45 โด 18x โ 27 = 45 โด 18x = 72 โด x = 4Present ages of A, B and C are 4x = 16, 5x = 20, 9x = 36 respectively.
Question 4 |
Two numbers are in the ratio of 2:9. If their H. C. F. is 19, numbers are:
6, 27 | |
8, 36 | |
38, 171 | |
20, 90 |
Discuss it
Question 4 Explanation:
Let the numbers be 2X and 9X Then their H.C.F. is X, so X = 19 โด Numbers are (2x19 and 9x19) i.e. 38 and 171
Question 5 |
In a box, there are 10p, 25p and 50p coins in the ratio 4:9:5 with the total sum of Rs 206. How many coins of each kind does the box have?
200, 360, 160 | |
135, 250, 150 | |
90, 60, 110 | |
Cannot be determined |
Discuss it
Question 5 Explanation:
Let the number of 10p, 25p, 50p coins be 4x, 9x, 5x respectively. Then,
4x/10 + 9x/4 + 5x/2 = 206 (Since, 10p = Rs 0.1, 25p = Rs 0.25, 50p = Rs 0.5)
=> 8x + 45x + 50x = 4120 (Multiplying both sides by 20 which is the LCM of 10, 4, 2)
=> 103x = 4120
=> x = 40.
Therefore,
No. of 10p coins = 4 x 40 = 160 (= Rs 16)
No. of 25p coins = 9 x 40 = 360 (= Rs 90)
No. of 50p coins = 5 x 40 = 200 (= Rs 100)
Question 6 |
Mark, Steve and Bill get their salaries in the ratio of 2:3:5. If their salaries are incremented by 15%, 10%, and 20% respectively, the new ratio of their salaries becomes:
8:16:15 | |
23:33:60 | |
33:30:20 | |
21:25:32 |
Discuss it
Question 6 Explanation:
Let their old salaries be 2a, 3a, 5a respectively. Then, their new salaries become:
115% of 2a = 2a x 1.15 = 2.3a
110% of 3a = 3a x 1.10 = 3.3a
120% of 5a = 5a x 1.20 = 6a
So, the new ratio becomes
2.3a:3.3a:6a
Upon simplification, this becomes
23:33:60
Question 7 |
In a library, the ratio of the books on Computer, Physics and Mathematics is 5:7:8. If the collection of books is increased respectively by 40%, 50% and 75%, find out the new ratio:
3:9:5 | |
7:5:3 | |
2:3:4 | |
2:5:4 |
Discuss it
Question 7 Explanation:
40% increase will lead to a factor of 140 and similarly 150 and 175 so new ratio is (5*140):(7*150):(8*175) on solving we get 2:3:4
Question 8 |
The ratio 5:3 represents 16 liters of a mixture containing milk and water. If 4 liters of water is added and 4 liters of milk is extracted from the mixture, then the ratio of the mixture will be:
7:3 | |
5:6 | |
2:3 | |
None of these |
Discuss it
Question 8 Explanation:
Amount of Milk in 16 litres of mixture: (5/8) x 16 = 10 litres
Amount of Water in 16 litres of mixture: 16-10 = 6 litres
If we add 4 litres of water and extract 4 litres of milk, the total volume remains the same.
Amount of Milk in 16 litres of new mixture: = 10 - 4 = 6 litres
Amount of Water in 16 litres of new mixture: = 6 + 4 = 10 litres
So, the new ratio becomes 3:5.
Question 9 |
If the ages of Jacob, Max and Samuel are in the proportion 3:5:7 and the average of their ages is 25 years, then find the age of the youngest person.
15 years | |
10 years | |
7 years | |
18 years |
Discuss it
Question 9 Explanation:
Let their ages be 3a, 5a and 7a. Then,
(3a + 5a + 7a) / 3 = 25
=> 15a/3 = 25
=> 5a = 25
=> a = 5
Therefore, age of the youngest person = 3a = 15 years
Question 10 |
The ratio of the speed of two trains is 7:8. If the second train covers 400 km in 4 h, find out the speed of the first train.
69.4 km/h | |
78.6 km/h | |
87.5 km/h | |
40.5 km/h |
Discuss it
Question 10 Explanation:
Let the speed of the two trains be 7x and 8x.
Then, 8x = 400 / 4
โ 8x = 100 โ x = 12.5 km/h.
Hence, speed of the first train = 7x = 7 ร 12.5 = 87.5 km/h.
There are 19 questions to complete.