| | Question 41

200 students appeared for GATE and CAT examinations. 60% passed in GATE, 40% passed the CAT and 25% passed both. Find the probability that a student selected at random has failed in both the examinations?
(A) 1/3
(B) 1/2
(C) 2/5
(D) 1/4


Answer: (D)

Explanation: Number of students passed in GATE = 200 x 60% = 120
Number of students passed in CAT = 200 x 40% = 80
Number of students passed in both = 200 x 25% = 50
Number of students passed in either GATE or CAT = 120 + 80 – 50 = 150
Hence, Number of students failed in both = 200 – 150 = 50
Required probability = 50/200 = 1/4

Quiz of this Question
Please comment below if you find anything wrong in the above post



My Personal Notes arrow_drop_up


Article Tags :
Practice Tags :


Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.